Exploring Chemical Analysis
Exploring Chemical Analysis
5th Edition
ISBN: 9781429275033
Author: Daniel C. Harris
Publisher: Macmillan Higher Education
Question
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Chapter 6, Problem 6.2P
Interpretation Introduction

Interpretation:

The volume of KMnO4 with 0.1650M needed to react with 108.0mL of 0.1650M oxalic acid; and volume of oxalic acid with 0.1650M needed to react with 108.0mL of 0.1650MKMnO4 has to be calculated.

Concept-Introduction:

Acid–base titration: It consists of a neutralization reaction where a measured volume of a known concentrated an acid or a base is used for determining the concentration of an unknown solution of base or acid with known volume.  The known concentrated solution is called the titrant, while the unknown concentrated solution is called the analyte.

Molarity: The concentration for solutions is expressed in terms of molarity as follows,

  Molarity = No. of moles of soluteVolume of solution in L

Expert Solution & Answer
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Answer to Problem 6.2P

The volume of oxalic acid is 270 mL.

Explanation of Solution

Given data is,

  Reaction : 5Oxalic acid + 2MnO4+6H+  10CO2 + 2Mn2++8H2

The moles of oxalic acid is calculated as shown below,

   5Oxalic acid 2MnO4+6H+  10CO2 + 2Mn2++8H2No.ofmoles =(0.1650M)(108.0mL)Molarity=0.165M=(17.82)mole

Here, 5 mole of oxalic acid requires 2 mole of KMnO4 and 17.82mole of oxalic acid requires ‘x’ mole of KMnO4

Thus,

  'x'moleofKMnO4= (2moleKMnO4)(17.8moleoxalic acid)5moleoxalicacid=7.12mole

Calculation of Volume of KMnO4 as shown below;

  Volume of KMnO4=7.12moleKMnO40.1650mole/mL=43.2mL.

Therefore, the volume of KMnO4 is 43.2mL.

Given data is,

  Reaction : 5Oxalic acid + 2MnO4+6H+  10CO2 + 2Mn2++8H2

The moles of KMnO4 is calculated as shown below,

  5Oxalic acid 2MnO4+6H+  10CO2 + 2Mn2++8H2No.ofmoles =(0.1650M)(108.0mL)=(17.82)mole

Here, 5 mole Of oxalic acid requires 2 mole of KMnO4 and ‘x’ of oxalic acid requires 17.82mole mole of KMnO4.

Thus,

  'x'moleofoxalic acid= (5moleoxalic acid)(17.8moleKMnO4)2moleKMnO4=44.5mole

Calculation of Volume of KMnO4 as shown below;

  Volume ofoxalic acid=44.5mole0.1650mole/mL=269.69mL=270mL.

Therefore, the volume of oxalic acid is 270mL.

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