The data for the volume and temperature of 0.50 mole of Helium gas at a pressure of 1.0 atm is given. The graph of volume of 0.50 mole of Helium gas as a function of temperature is to be plotted and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half is to be stated. Concept introduction: According to the Charles’ law, the volume of a gas is directly proportional to temperature of the gas at the constant pressure and for fixed moles of gas. To determine: The graph of volume of 0.50 mole of Helium gas as a function of temperature and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half of the given value.

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Answer 1

Question

Chapter 6, Problem 6.56QP

Interpretation Introduction

Interpretation: The data for the volume and temperature of 0.50 mole of Helium gas at a pressure of 1.0 atm is given. The graph of volume of 0.50 mole of Helium gas as a function of temperature is to be plotted and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half is to be stated.

Concept introduction: According to the Charles’ law, the volume of a gas is directly proportional to temperature of the gas at the constant pressure and for fixed moles of gas.

To determine: The graph of volume of 0.50 mole of Helium gas as a function of temperature and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half of the given value.

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Answer 2

Question

Chapter 6, Problem 6.56QP

Interpretation Introduction

Interpretation: The data for the volume and temperature of 0.50 mole of Helium gas at a pressure of 1.0 atm is given. The graph of volume of 0.50 mole of Helium gas as a function of temperature is to be plotted and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half is to be stated.

Concept introduction: According to the Charles’ law, the volume of a gas is directly proportional to temperature of the gas at the constant pressure and for fixed moles of gas.

To determine: The graph of volume of 0.50 mole of Helium gas as a function of temperature and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half of the given value.

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Answer 3

Question

Chapter 6, Problem 6.56QP

Interpretation Introduction

Interpretation: The data for the volume and temperature of 0.50 mole of Helium gas at a pressure of 1.0 atm is given. The graph of volume of 0.50 mole of Helium gas as a function of temperature is to be plotted and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half is to be stated.

Concept introduction: According to the Charles’ law, the volume of a gas is directly proportional to temperature of the gas at the constant pressure and for fixed moles of gas.

To determine: The graph of volume of 0.50 mole of Helium gas as a function of temperature and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half of the given value.

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Answer 4

Question

Chapter 6, Problem 6.56QP

Interpretation Introduction

Interpretation: The data for the volume and temperature of 0.50 mole of Helium gas at a pressure of 1.0 atm is given. The graph of volume of 0.50 mole of Helium gas as a function of temperature is to be plotted and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half is to be stated.

Concept introduction: According to the Charles’ law, the volume of a gas is directly proportional to temperature of the gas at the constant pressure and for fixed moles of gas.

To determine: The graph of volume of 0.50 mole of Helium gas as a function of temperature and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half of the given value.

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Answer 5

Chapter 6, Problem 6.56QP

Interpretation Introduction

Interpretation: The data for the volume and temperature of 0.50 mole of Helium gas at a pressure of 1.0 atm is given. The graph of volume of 0.50 mole of Helium gas as a function of temperature is to be plotted and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half is to be stated.

Concept introduction: According to the Charles’ law, the volume of a gas is directly proportional to temperature of the gas at the constant pressure and for fixed moles of gas.

To determine: The graph of volume of 0.50 mole of Helium gas as a function of temperature and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half of the given value.

Answer 6

Chapter 6, Problem 6.56QP

Interpretation Introduction

Interpretation: The data for the volume and temperature of 0.50 mole of Helium gas at a pressure of 1.0 atm is given. The graph of volume of 0.50 mole of Helium gas as a function of temperature is to be plotted and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half is to be stated.

Concept introduction: According to the Charles’ law, the volume of a gas is directly proportional to temperature of the gas at the constant pressure and for fixed moles of gas.

To determine: The graph of volume of 0.50 mole of Helium gas as a function of temperature and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half of the given value.

Answer 7

Chapter 6, Problem 6.56QP

Interpretation Introduction

Interpretation: The data for the volume and temperature of 0.50 mole of Helium gas at a pressure of 1.0 atm is given. The graph of volume of 0.50 mole of Helium gas as a function of temperature is to be plotted and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half is to be stated.

Concept introduction: According to the Charles’ law, the volume of a gas is directly proportional to temperature of the gas at the constant pressure and for fixed moles of gas.

To determine: The graph of volume of 0.50 mole of Helium gas as a function of temperature and the comparison of the graph with graph obtained in Problem 6.55 after reducing the moles to half of the given value.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 6.2 - Prob. 1PE Ch. 6.2 - Prob. 2PE Ch. 6.3 - Prob. 3PE Ch. 6.3 - Prob. 4PE Ch. 6.3 - Prob. 5PE Ch. 6.4 - Prob. 6PE Ch. 6.4 - Prob. 7PE Ch. 6.5 - Prob. 8PE Ch. 6.5 - Prob. 9PE Ch. 6.6 - Prob. 10PE

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