Chapter 6, Problem 6.71SP

(a)

Interpretation Introduction

Interpretation:

Mass in grams of $I_2$ that are needed to react with $49.2g$ of $H_{2}S$ has to be calculated.

Concept Introduction:

• Molecular weight is the sum of atomic weight of all atoms in a molecule.
• The percent composition is the percent by mass of each element in a compound.
• Empirical formula gives the information about the smallest whole number ratio of atoms in a compound.
• Molecular formula gives information about the ratios of different atoms in a compound.
• $No:ofmoles=\frac{Mass\times 1mol}{Molarmass}$

(b)

Interpretation Introduction

Interpretation:

Mass in grams of $HI$ that are produced from $95.4g$ of $H_{2}S$ has to be identified.

Concept Introduction:

• Molecular weight is the sum of atomic weight of all atoms in a molecule.
• The percent composition is the percent by mass of each element in a compound.
• Empirical formula gives the information about the smallest whole number ratio of atoms in a compound.
• Molecular formula gives information about the ratios of different atoms in a compound.
• $No:ofmoles=\frac{Mass\times 1mol}{Molarmass}$