Chapter 6, Problem 6.83SP

Interpretation Introduction

Interpretation:

$2.08g$ of cisplatin was formed from $3.42g$ of $K_{2}PtC{l}_4$ and $1.61g$ of $N{H}_3$, the percent yield of the reaction has to be determined.

Concept Introduction:

• One mole has Avogadro number $(6.023\times {10}^{23})$ of formula unit
• Molar mass of a substance is the mass in grams of one mole of a substance.
• $No:ofmoles=\frac{Mass\times 1mol}{Molarmass}$
• The limiting reactant is the reactant that limits the amount of other reactant that can combine and the amount product that can form in a chemical reaction.
• The excess reactant is the substance that is not used up completely in a reaction.
• $\%yield=\frac{Actualyield}{Theoreticalyield}\times 100$