Chemistry-Masteringchemistry With Etext
7th Edition
ISBN: 9780133891782
Author: McMurry
Publisher: PEARSON
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Chapter 6, Problem 6.76SP
Find the lattice energy of LiBr(s) in Table 6.3, and calculate the energy change in kilojoules per mole for the formation of solid LiBr from the elements. (The sublimation energy for Li(s) is +159.4 kJ/mol, the
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Calculate the lattice energy for LiBr(s) given the following:
sublimation energy for Li(s)
+166 kJ/mol
ΔHf for Br(g)
+97 kJ/mol
first ionization energy of Li(g)
+520. kJ/mol
electron affinity of Br(g)
–325 kJ/mol
enthalpy of formation of LiBr(s)
–351 kJ/mol
The lattice energy of NaBr is –752 kJ/mol. This energy corresponds to which reaction below?
Na(s) + 1/2 Br2(g) → NaBr(s)
Na(g) + Br(g) → NaBr(s)
Na(g) + Br(g) → NaBr(s)
Na+(g) + Br–(g) → NaBr(s)
Na+(aq) + Br–(aq) → NaBr(s)
The lattice energy of MgO is 3890 kJ/mol. The first and the second ionization energies (IE1 and IE2) of Mg are 738 kJ/mol and 1450.6 kJ/mol, respectively. The first ionization energy of O is 1314 kJ/mol. The first electron affinity (EA1) of O is +141 kJ/mol. Using these data, as well as data from a table of thermodynamic data at 1 atm and 25°C, determine the second electron affinity for oxygen, EA2(O). kJ/mol
Chapter 6 Solutions
Chemistry-Masteringchemistry With Etext
Ch. 6 - Prob. 6.1PCh. 6 - APPLY 6.2 Which of the following sets of ions are...Ch. 6 - Prob. 6.3PCh. 6 - Conceptual APPLY 6.4 Which of the following...Ch. 6 - Prob. 6.5PCh. 6 - Prob. 6.6ACh. 6 - Prob. 6.7PCh. 6 - Conceptual APPLY 6.8 The figure on the right...Ch. 6 - Prob. 6.9PCh. 6 - Conceptual APPLY 6.10 Which of the indicated three...
Ch. 6 - Prob. 6.11PCh. 6 - Prob. 6.12ACh. 6 - Prob. 6.13PCh. 6 - APPLY 6.14 Calculate the energy of electrostatic...Ch. 6 - Prob. 6.15PCh. 6 - Conceptual APPLY 6.16 One of the following...Ch. 6 - Prob. 6.17PCh. 6 - PROBLEM 6.18 Compare the following two ionic...Ch. 6 - PROBLEM 6.19 An ionic liquid consisting of a bulky...Ch. 6 - Where on the periodic table would you find the...Ch. 6 - Which of the following spheres is likely to...Ch. 6 - Circle the approximate part or parts of the...Ch. 6 - Prob. 6.23CPCh. 6 - This figure represents the successive ionization...Ch. 6 - In the following drawings, red spheres represent...Ch. 6 - Which of the following drawings is more likely to...Ch. 6 - Prob. 6.27CPCh. 6 - Which of the following alkali metal halides has...Ch. 6 - Which of the following alkali metal halides has...Ch. 6 - Three binary compounds are represented on the...Ch. 6 - Given the following values for the formation of...Ch. 6 - What is the difference between a covalent bond and...Ch. 6 - Prob. 6.33SPCh. 6 - What is the difference between a molecule and an...Ch. 6 - Prob. 6.35SPCh. 6 - How many protons and electrons are in each of the...Ch. 6 - What is the identity of the element X in the...Ch. 6 - Prob. 6.38SPCh. 6 - Prob. 6.39SPCh. 6 - Prob. 6.40SPCh. 6 - Prob. 6.41SPCh. 6 - What doubly positive ion has the following...Ch. 6 - Prob. 6.43SPCh. 6 - Prob. 6.44SPCh. 6 - Which element in the transition-metal series Sc...Ch. 6 - Prob. 6.46SPCh. 6 - Prob. 6.47SPCh. 6 - Prob. 6.48SPCh. 6 - Prob. 6.49SPCh. 6 - Prob. 6.50SPCh. 6 - Prob. 6.51SPCh. 6 - Prob. 6.52SPCh. 6 - Prob. 6.53SPCh. 6 - Prob. 6.54SPCh. 6 - Prob. 6.55SPCh. 6 - Prob. 6.56SPCh. 6 - Prob. 6.57SPCh. 6 - Prob. 6.58SPCh. 6 - Prob. 6.59SPCh. 6 - What is the relationship between the electron...Ch. 6 - Prob. 6.61SPCh. 6 - Prob. 6.62SPCh. 6 - Prob. 6.63SPCh. 6 - Prob. 6.64SPCh. 6 - Prob. 6.65SPCh. 6 - Prob. 6.66SPCh. 6 - Prob. 6.67SPCh. 6 - Prob. 6.68SPCh. 6 - Prob. 6.69SPCh. 6 - Prob. 6.70SPCh. 6 - Prob. 6.71SPCh. 6 - Prob. 6.72SPCh. 6 - Prob. 6.73SPCh. 6 - Prob. 6.74SPCh. 6 - Prob. 6.75SPCh. 6 - Find the lattice energy of LiBr(s) in Table 6.3,...Ch. 6 - Prob. 6.77SPCh. 6 - Prob. 6.78SPCh. 6 - Prob. 6.79SPCh. 6 - Prob. 6.80SPCh. 6 - Prob. 6.81SPCh. 6 - Prob. 6.82SPCh. 6 - Prob. 6.83SPCh. 6 - Use the data and the result in Problem 6.78 to...Ch. 6 - Prob. 6.85SPCh. 6 - Prob. 6.86CPCh. 6 - Prob. 6.87CPCh. 6 - Prob. 6.88CPCh. 6 - Prob. 6.89CPCh. 6 - Prob. 6.90CPCh. 6 - Prob. 6.91CPCh. 6 - Prob. 6.92CPCh. 6 - Prob. 6.93CPCh. 6 - Prob. 6.94CPCh. 6 - Prob. 6.95CPCh. 6 - Prob. 6.96CPCh. 6 - Prob. 6.97CPCh. 6 - Prob. 6.98CPCh. 6 - Consider the electronic structure of the element...Ch. 6 - Prob. 6.100MPCh. 6 - Prob. 6.101MP
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- Calculate the lattice energy of potassium fluoride, KF, using the BornHaber cycle. Use thermodynamic data from Appendix C to obtain the enthalpy changes for each step. (Note: You will obtain a slightly different answer if you use values given in Chapter 8 for the ionization energy and electron affinity, which are energy values at 0 K rather than the enthalpy changes at 298 K.)arrow_forwardThe lattice energy of an ionic solid such as NaCl is the enthalpy change H for the process in which the solid changes to ions. For example, NaCl(s)Na+(g)+Cl(g)H=786kJ/mol Assume that the ionization energy and electron a affinity are H values for the processes defined by those terms. The ionization energy of Na is 496 kJ/mol. Use this, the electron affinity from Table 8.4, and the lattice energy of NaCl to calculate H for the following process: Na(g)+Cl(g)NaCl(s)arrow_forwardThe standard heat of formation of BaBr2BaBr2 is −−764 kJ/molkJ/mol. The first ionization energy of BaBa is 503 kJ/molkJ/mol and its second ionization energy is 965 kJ/molkJ/mol. The heat of sublimation of Ba[Ba(s)→Ba(g)]Ba[Ba(s)→Ba(g)] is 175 kJ/molkJ/mol. The bond energy of Br2Br2 is 193 kJ/molkJ/mol, the heat of vaporization of Br2(l)Br2(l) is 31 kJ/molkJ/mol, and the electron affinity of BrBr is −−325 kJ/molkJ/mol. Calculate the lattice energy of BaBr2BaBr2.arrow_forward
- Use the data provided below to calculate the lattice energy of RbCl. Is this value greater or less than thelattice energy of NaCl? Explain.Electron affinity of Cl = –349 kJ/mol1st ionization energy of Rb = 403 kJ/molBond energy of Cl2 = 242 kJ/molSublimation energy of Rb = 86.5 kJ/molΔHf [RbCl (s)] = –430.5 kJ/molarrow_forwardSuppose there is an element X which occurs naturally as X2(g).X2(g) + 2O2(g) → X2O4(g)ΔHof of O(g) is 249 kJ/molΔHof of X(g) is 458.5 kJ/molΔHof of X2O4(g) is 31 kJ/molThe X-X single bond energy is 116 kJ/molUse the above data to estimate the average bond energy in X2O4. Give your answer to the nearest 1 kJ/mol.arrow_forwardConsider an ionic compound, MX3, composed of generic metal M and generic gaseous halogen X. The enthalpy of formation of MX3 is ΔHf∘=−965 kJ/mol. The enthalpy of sublimation of M is ΔHsub=123 kJ/mol. The first, second, and third ionization energies of M are IE1=557 kJ?mol, IE2=1751 kJ/mol, and IE3=2731 kJ/mol. The electron affinity of X is ΔHEA=−339 kJ/mol The bond energy of X2 is BE=235 kJ/mol. Determine the lattice energy of MX3.arrow_forward
- Calculate the lattice formation enthalpy (lattice energy) of the lattice for LiF(s), in kJ/mol, given the following information: Sublimation energy for Li(s) 161 kJ/mol AH: for F(g) 77 kJ/mol First ionization 520 kJ/mol energy of Li(g) Electron affinity of F(g) -328 kJ/mol Enthalpy of formation of LİF(s) -617 kJ/mol kJ/mol 1 3 4 6. C 7 8 +/- х 100 Tap here or pull up for additional resources LO 00arrow_forward8. Given the following information: Li(s) HI(g) → H(g) + I(g) enthalpy of sublimation of Li(s) = 166 kJ/mol bond energy of HI = 295 kJ/mol Li(g) Li(g) → Li"(g) + e ionization energy of Li(g)= 520. kJ/mol I(g) + e — Г(g) electron affinity of I(g) = -295 kJ/mol Li"(g) + I(g) → LiI(s) lattice energy of LiI(s) = -737 kJ/mol H2(g) → 2H(g) Calculate the change in enthalpy for: bond energy of H2 = 432 kJ/mol 2Li(s) + 2HI(g) –→ H2(g) + 2LİI(s) a. 330 kJ b. –534 kJ c. -483 kJ d. -984 kJ e. none of thesearrow_forwardConsider the following data for nickel: atomic mass electronegativity electron affinity ionization energy heat of fusion 58.693 1.91 112. 737.1 g mol 17.2 kJ mol kJ mol kJ mol Does the following reaction absorb or release energy? (1) Ni (g) → Ni(g) + e Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): Does the following reaction absorb or release energy? (2) Ni' (g) + e Ni (g) - Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): Orelease O absorb O Can't be decided with the data given. O yes O no kJ/mol O release O absorb O Can't be decided with the data given. O yes O no kJ/molarrow_forward
- Calculate the lattice energy of NaBr(s), given the following thermochemical equations, where A/E and AEA are ionization energy and electron affinity, respectively. Na(s)Na(g) AH = +107 kJ Na(g) Nat(g) + e A/E = +496 kJ -> 1/2 Br₂(g) → Br(g) AHf = +112 kJ - Br(g) + e¯ → Br¯(g) AEA = -325 kJ Na(s) + 1/2 Br₂(g) → NaBr(s) AH = -361 kJ ->> - -1401 kJ -751 kJ +29 kJ -29 kJ +751 kJarrow_forwardGiven the following information, construct a Born-Haber cycle to calculate the lattice energy of CrCl₂I(s): Net energy change for the formation of CrCl₂I(s) = -420 kJ/mol Bond dissociation energy for I2(g) = +243 kJ/mol Bond dissociation energy for Cl2(g) for Cl2(g) for 12(g) = +151 kJ/mol Heat of sublimation for I2(s) = +62 kJ/mol Heat of sublimation for Cr(s) = +397 kJ/mol = E₁₁ for Cr(g) = 652 kJ/mol E₁₂ for Cr(g) == 1588 kJ/mol E₁3 for Cr(g) = 2882 kJ/mol Eea for Cl(g)=-349 kJ/mol === Eea for I(g) = -295 kJ/molarrow_forwardChoose the related energy for the following reaction: 2 Cs* (g) + O2- (g) → Cs20 (s) electron affinity ionization energy heat of formation lattice energyarrow_forward
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