Chapter 6, Problem 6D.1ST

Interpretation Introduction

Interpretation:

From the given data $A$ and $E_a$ have to be determined.

Concept Introduction:

Intergrated rate eqaution for a second order reaction is,

$\frac{1}{\left[A\right]}=\frac{1}{{\left[A\right]}_0}+kt$

$\left[A\right]$ is the concentration of reactant A at time t ${\left[A\right]}_0$ is the  initial concentration of reactant, k is the rate constant.

The activation energy from the given information has to be calculated from the modified Arrhenius equation.

  $\ln \frac{k_1}{k_2}=\frac{E_a}{R}\left[\frac{1}{T_2}-\frac{1}{T_1}\right]$

Arrhenius equation:

• Arrhenius equation is a formula that represents the temperature dependence of reaction rates
• The Arrhenius equation has to be represented as follows $k=A{e}^{-E_a/RT}$
• $E_a$ represents the activation energy and it’s unit is kJ/mol
• R represents the universal gas constant and it has the value of $\text{8}\text{.314 J/K}\text{.mol}$
• T represents the absolute temperature
• A represents the frequency factor or collision frequency