Chapter 6, Problem 6H.27E

(a)

Interpretation Introduction

Interpretation:

The volume of ${\text{HNO}}_{\text{3}}$ at first stoichiometry point has to be given.

Concept Introduction:

Stiochiometry point:

The equivalence point is the point in a titration where the titrant completely neutralizes the solution.  This is also known as the stiochiometry point because it is where the moles if acid are equal to the amount needed to neutralize the moles of base.  The volume of titrant at this point can be calculated as,

  ${\text{V}}_{\text{2}}\text{=}\frac{{\text{V}}_{\text{1}}{\text{M}}_{\text{1}}}{{\text{M}}_{\text{2}}}$

Where ${\text{V}}_{\text{1}}$ is the volume titrant.

${\text{V}}_{\text{2}}$ is the volume analyte solution.

${\text{M}}_{\text{1}}$ is the molarity of titrant.

${\text{M}}_2$ is the molarity of analyte.

(b)

Interpretation Introduction

Interpretation:

The volume of ${\text{HNO}}_{\text{3}}$ at second stoichiometry point has to be given.