Chapter 6, Problem 6L.1BST

Interpretation Introduction

Interpretation:

The Gibbs free energy of the reaction has to be written.

Concept Introduction:

The Gibbs free energy of the reaction is calculated as,

  ${\text{ΔG=-nFE}}_{\text{cell}}$

Here, $\text{ΔG=}$ Gibbs free energy

    $\text{n=}$ Number of electrons transferred (in moles)

  $\text{F=}$ Faraday’s constant $\left(\text{9}{\text{.6485×10}}^{\text{4}}\text{C}\cdot {\text{mol}}^{\text{-1}}\right)$

  ${\text{E}}_{\text{cell}}\text{=}$ Cell potential