Chapter 6.1, Problem 3E

(a)

To determine

To Calculate: $\text{P}\left(Y>20\right)$ and explain it

Answer to Problem 3E

  $\text{P}\left(Y>20\right)=0.42$

Explanation of Solution

Given:

Money collected	0	5	10	15	20	25
Probability	0.02	0.05	0.08	0.16	0.27	0.42

Calculation:

  $\begin{array}{c}\text{P}\left(Y>20\right)=\text{P}\left(Y=25\right)\\ =0.42\end{array}$

It is 0.42 probabilities that the amount of money collected which is greater than $20.

(b)

To determine

To Calculate: the event for at least $20 is collected in terms of Y and its probability

Answer to Problem 3E

  $Y\ge 20$

  $\text{P}\left(Y\ge 20\right)=0.69$

Explanation of Solution

Calculation:

  $\begin{array}{c}\text{P}\left(Y\ge 20\right)=\text{P}\left(Y=20\right)+\text{P}\left(Y=25\right)\\ =0.27+0.42\\ =0.69\end{array}$