For Problems 121-124, use the following discussion. Projectile Motion The path of a projectile fired at an inclination θ to the horizontal with initial speed v 0 is a parabola (see the figure). The range R of the projectile, that is, the horizontal distance that the projectile travels, is found by using the function R ( θ ) = v 0 2 sin ( 2 θ ) g where g ≈ 32.2 feet per second per second ≈ 9.8 meters per second per second is the acceleration due to gravity. The maximum height H of the projectile is given by the function H ( θ ) = v 0 2 ( sin θ ) 2 g 2 In Problems 121-124, find the range R and maximum height H . (See the discussion on the previous page.) The projectile is fired at an angle of 30 ∘ to the horizontal with an initial speed of 150 meters per second.
For Problems 121-124, use the following discussion. Projectile Motion The path of a projectile fired at an inclination θ to the horizontal with initial speed v 0 is a parabola (see the figure). The range R of the projectile, that is, the horizontal distance that the projectile travels, is found by using the function R ( θ ) = v 0 2 sin ( 2 θ ) g where g ≈ 32.2 feet per second per second ≈ 9.8 meters per second per second is the acceleration due to gravity. The maximum height H of the projectile is given by the function H ( θ ) = v 0 2 ( sin θ ) 2 g 2 In Problems 121-124, find the range R and maximum height H . (See the discussion on the previous page.) The projectile is fired at an angle of 30 ∘ to the horizontal with an initial speed of 150 meters per second.
Solution Summary: The author explains how to find the range R and maximum height H.
For Problems 121-124, use the following discussion.
Projectile Motion The path of a projectile fired at an inclination
to the horizontal with initial speed
is a parabola (see the figure).
The range
of the projectile, that is, the horizontal distance that the projectile travels, is found by using the function
where
feet per second per second
meters per second per second is the acceleration due to gravity. The maximum height
of the projectile is given by the function
In Problems 121-124, find the range
and maximum height
. (See the discussion on the previous page.)
The projectile is fired at an angle of
to the horizontal with an initial speed of 150 meters per second.
The velocity of Engr. Garcia in meters/sec when he jumped out of the plane given is given by the equation v(h)=sqrt [(9.8)(2)(h)], where h is a function of height in meters. At what height should he jump if he wants to hit the ground at 150 m/s ignoring air resistance.
I have a question, on how this problem could mean when finding the angle with the figure shown, and the given function?
I need to find the value of the trig function indicated sec 0
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