LL ORG CHEM
6th Edition
ISBN: 9781264840083
Author: SMITH
Publisher: MCG
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Chapter 6.6, Problem 13P
Interpretation Introduction
(a)
Interpretation: Whether the starting material or product is favored at equilibrium is to be predicted on the basis of the given value of
Concept introduction: The change in Gibbs free energy and enthalpy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction, whereas the change in enthalpy describes the relative bond strength in the substance.
Interpretation Introduction
(b)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy and enthalpy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction, whereas the change in enthalpy describes the relative bond strength in the substance.
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Given each value, determine whether the starting material or product is favored at equilibrium.
a.Keq = 0.5
b.ΔGo = −100 kJ/mol
c.ΔHo = 8.0 kJ/mol
d.Keq = 16
e. ΔGo = 2.0 kJ/mol
f.ΔHo = 200 kJ/mol
g. ΔSo = 8 J/(K•mol)
h.ΔSo = −8 J/(K•mol)
Considering each of the following values and neglecting entropy, tell whether the starting material or product is favored at equilibrium: (a) ΔHo = 80 kJ/mol; (b) ΔHo = −40 kJ/mol.
Given each of the following values, is the starting material or product favored at equilibrium?A.) Keq = 5.5b.) ΔGo = 40 kJ/mol
Chapter 6 Solutions
LL ORG CHEM
Ch. 6.2 - Prob. 2PCh. 6.3 - Problem 6.3 By taking into account...Ch. 6.3 - Problem 6.4 Use curved arrows to show the movement...Ch. 6.3 - Problem 6.5 Follow the curved arrows and draw the...Ch. 6.4 - Prob. 6PCh. 6.4 - Problem 6.7 Use the values in Table 6.2 to...Ch. 6.4 - Prob. 8PCh. 6.5 - aWhich Keq corresponds to a negative value of G,...Ch. 6.5 - Given each of the following values, is the...Ch. 6.5 - Given each of the following values, is the...
Ch. 6.5 - The equilibrium constant for the conversion of the...Ch. 6.6 - Prob. 13PCh. 6.6 - For a reaction with H=40kJ/mol, decide which of...Ch. 6.6 - For a reaction with H=20kJ/mol, decide which of...Ch. 6.7 - Draw an energy diagram for a reaction in which the...Ch. 6.7 - Prob. 17PCh. 6.7 - Prob. 18PCh. 6.8 - Problem 6.19 Consider the following energy...Ch. 6.8 - Draw an energy diagram for a two-step reaction,...Ch. 6.9 - Which value if any corresponds to a faster...Ch. 6.9 - Prob. 22PCh. 6.9 - Problem 6.23 For each rate equation, what effect...Ch. 6.9 - Prob. 24PCh. 6.10 - Identify the catalyst in each equation. a....Ch. 6 - Draw the products of homolysis or heterolysis of...Ch. 6 - Explain why the bond dissociation energy for bond...Ch. 6 - Classify each transformation as substitution,...Ch. 6 - Prob. 29PCh. 6 - 6.31 (a) Add curved arrows for each step to show...Ch. 6 - Prob. 35PCh. 6 - 6.39. a. Which value corresponds to a negative...Ch. 6 - Prob. 40PCh. 6 - For which of the following reaction is S a...Ch. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - 6.44 Consider the following reaction: .
Use curved...Ch. 6 - Prob. 45PCh. 6 - 6.50 The conversion of acetyl chloride to methyl...Ch. 6 - Prob. 50PCh. 6 - Prob. 53P
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- Calculate the energy change of the following reaction: 2NO + O2→ 2NO2 ΔH: NO = 90.0 kJ/mol NO2= 34.0 kJ/mol O2= 0.0 kJ/mol a -180 kJ b -112 kJ c 35.0 kJ d -248 kJarrow_forwardWhich value (if any) corresponds to a faster reaction: (a) Ea = 40 kJ/mol or Ea = 4 kJ/mol; (b) a reaction temperature of 0 °C or a reaction temperature of 25 °C; (c) Keq = 10 or Keq = 100; (d) ΔH° = −10 kJ/mol or ΔH° = 10 kJ/mol?arrow_forwardDiscuss the conditions needed to have a reaction with gaseous reagents and gaseous products so that The value of Kp increases with increasing temperature The value of ΔG° increases with increasing temperature The value of k increases with increasing temperature The conversion of one of the reagents increases with increasing pressurearrow_forward
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