LL ORG CHEM
6th Edition
ISBN: 9781264840083
Author: SMITH
Publisher: MCG
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Chapter 6.8, Problem 20P
Draw an energy diagram for a two-step reaction,
compounds is
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For a reaction that follows the general rate law Rate = KIAJ [B), what will happen to the rate of reaction if the concentration of A and B are increased by a factor of 6?
O The rate will increase by a factor of 36.00.
O The rate will decrease by a factor of 1/6.00.
O The rate will decrease by a factor of 1/36.00.
O The rate will increase by a factor of 6.00.
Consider the following reaction:
(a) The rate law for this reaction is first order in NO₂(g) and first order in O3(g). What is the rate law for this reaction?
O Rate = k [NO₂(g)] [03(9)]
Rate = k [NO₂(g)]² [03(9)]
O Rate = k [NO₂(g)] [03(9)]²
O Rate = k [NO₂(g)]² [03(g)]²
Rate = k [NO₂(g)] [03(g)]³
Rate = k [NO₂(g)]4 [03(9)]
(b) If the rate constant for this reaction at a certain temperature is 73200, what is the reaction rate when [NO₂(g)] = 0.973 M and [O3(9)] = 1.42 M?
Rate =
2 NO₂(g) + 03(g) → N₂05(9) + O₂(g)
M/s.
Rate =
(c) What is the reaction rate when the concentration of NO₂(g) is doubled, to 1.95 M while the concentration of O3(g) is 1.42 M?
M/s
Draw an energy diagram for a two-step reaction, A -> B -> C, where the relative energy of these compounds is C < A < B, and the conversion of B ? C is rate-determining.
Chapter 6 Solutions
LL ORG CHEM
Ch. 6.2 - Prob. 2PCh. 6.3 - Problem 6.3 By taking into account...Ch. 6.3 - Problem 6.4 Use curved arrows to show the movement...Ch. 6.3 - Problem 6.5 Follow the curved arrows and draw the...Ch. 6.4 - Prob. 6PCh. 6.4 - Problem 6.7 Use the values in Table 6.2 to...Ch. 6.4 - Prob. 8PCh. 6.5 - aWhich Keq corresponds to a negative value of G,...Ch. 6.5 - Given each of the following values, is the...Ch. 6.5 - Given each of the following values, is the...
Ch. 6.5 - The equilibrium constant for the conversion of the...Ch. 6.6 - Prob. 13PCh. 6.6 - For a reaction with H=40kJ/mol, decide which of...Ch. 6.6 - For a reaction with H=20kJ/mol, decide which of...Ch. 6.7 - Draw an energy diagram for a reaction in which the...Ch. 6.7 - Prob. 17PCh. 6.7 - Prob. 18PCh. 6.8 - Problem 6.19 Consider the following energy...Ch. 6.8 - Draw an energy diagram for a two-step reaction,...Ch. 6.9 - Which value if any corresponds to a faster...Ch. 6.9 - Prob. 22PCh. 6.9 - Problem 6.23 For each rate equation, what effect...Ch. 6.9 - Prob. 24PCh. 6.10 - Identify the catalyst in each equation. a....Ch. 6 - Draw the products of homolysis or heterolysis of...Ch. 6 - Explain why the bond dissociation energy for bond...Ch. 6 - Classify each transformation as substitution,...Ch. 6 - Prob. 29PCh. 6 - 6.31 (a) Add curved arrows for each step to show...Ch. 6 - Prob. 35PCh. 6 - 6.39. a. Which value corresponds to a negative...Ch. 6 - Prob. 40PCh. 6 - For which of the following reaction is S a...Ch. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - 6.44 Consider the following reaction: .
Use curved...Ch. 6 - Prob. 45PCh. 6 - 6.50 The conversion of acetyl chloride to methyl...Ch. 6 - Prob. 50PCh. 6 - Prob. 53P
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- . Account for the increase in reaction rate brought about by a catalyst.arrow_forwardWhy awe elementary reactions involving three or more reactants very uncommon?arrow_forwardConsider the following statements: In general, the rate of a chemical reaction increases a bit at first because it takes a while for the reaction to get warmed up. After that, however, the rate of the reaction decreases because its rate is dependent on the concentrations of the reactants, and these are decreasing. Indicate everything that is correct in these statements, and indicate everything that is incorrect. Correct the incorrect statements and explain.arrow_forward
- The reaction O₂(g) + 2 NO(g) → 2 NO₂(g) was studied at a certain temperature with the following results: (a) What is the rate law for this reaction? O Ratek [0₂(9)] [NO(g)] O Ratek [0₂(9)]² [NO(g)] O Rate = k [0₂(9)] [NO(g)]² O Ratek [0₂(9)]² [NO(g)]² O Ratek [0₂(9)] [NO(g)]³ O Rate = k [O₂(g)]* [NO(g)] (b) What is the value of the rate constant? Experiment [0₂(9)] (M) 0.0235 0.0235 0.0470 0.0470 [NO(g)] (M) 0.0235 0.0470 0.0235 0.0470 Rate (M/S) 0.158 0.633 0.317 1.27 (c) What is the reaction rate when the concentration of O₂(g) is 0.0318 M and that of NO(g) is 0.0649 M if the temperature is the same as that used to obtain the data shown above?arrow_forwardDraw an energy diagram for a two-step reaction, A → B → C, where the relative energy of these compounds is C < A < B, and the conversion of B→ C is rate-determining.arrow_forwardConsider the reaction (image attached) A. Find Δ[O2]/Δt B. Find Δ[H2O]/Δt C. Find Δ[S8]/Δt D. Find the rate of this reactionarrow_forward
- Consider the following reaction: (a) The rate law for this reaction is first order in HBr(g) and first order in O₂(g). What is the rate law for this reaction? Rate = k [HBr(g)] [O₂(g)] O Rate = k [HBr(g)]² [O₂(g)] O Rate = k [HBr(g)] [O₂(g)]² O Rate = k [HBr(g)]² [0₂(g)]² O Rate = k [HBr(g)] [O₂(g)]³ O Rate = k [HBr(g)]4 [0₂(g)] (b) If the rate constant for this reaction at a certain temperature is 11500, what is the reaction rate when [HBr(g)] = 0.00379 M and [O₂(g)] = 0.00876 M? Rate = 4 HBr(g) + O₂(g) → 2 H₂O(g) + 2 Br₂(g) M/s. Rate = (c) What is the reaction rate when the concentration of HBr(g) is doubled, to 0.00758 M while the concentration of O₂(g) is 0.00876 M? M/Sarrow_forwardHere are representations of a reaction: A + B --> products Unshaded spheres represent A molecules. Shaded spheres represent B molecules. Trial 1 Trial 2 Trial 3 Trial 4 Rate = 1 Rate = 1 Rate = 4 Rate = 4arrow_forwardDraw an energy diagram for each reaction. Label the axes, the startingmaterial, product, transition state, ΔHo, and Ea.a.) a concerted reaction with ΔHo = −80 kJ/mol and Ea = 16 kJ/molb.) a two-step reaction, A → B → C, in which the relative energy of thecompounds is A < C < B, and the step A → B is rate-determiningarrow_forward
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