McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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When a large number of trials are performed for any random variable ‘X’, the predicted result is most likely the mean of all the outcomes for the random variable and it is known as expected value also known as expectation. The expected value, also known …

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Question

Polygon with three sides, three angles, and three vertices. Based on the properties of each side, the types of triangles are scalene (triangle with three three different lengths and three different angles), isosceles (angle with two equal sides and two equal angles), and equilateral (three equal sides and three angles of 60°). The types of angles are acute (less than 90°); obtuse (greater than 90°); and right (90°).

Chapter 7, Problem 22CR

To determine

To find:The measure of segment OW in a given triangle.

Expert Solution & Answer

Answer to Problem 22CR

The measure of segment OW is 25

Explanation of Solution

Given Information:

A triangle OTW with a line parallel to the base and intersecting the other two sides of the triangle at point S and V such that OS=8,ST=12 and OV=10 .

Formula used:

In a triangle when a segment is drawn parallel to the base intersects the other two sides at two respective points, it divides the sides in the same proportion.

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 7, Problem 22CR , additional homework tip 1

For example, in the above triangle TRS , the segment PQ is parallel to the base RS and it divides the respective sides TR and TS proportionately, expressed as,

RPPT=SQQT

Calculation:

Consider the given triangleOTW . Applying the relation between the proportional sides with the given sides,

OSST=OVVW

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 7, Problem 22CR , additional homework tip 2

Substituting the measures of the given sides, OS=8,ST=12 and OV=10 , the above equation becomes,

812=10VWVW=1208=15

Now, the length of the side OW is obtained as the sum of measure of OV and VW ,

OW=OV+VW=10+15=25

Chapter 7, Problem 21CR

Chapter 7, Problem 23CR

Chapter 7 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 7.1 - Prob. 1CE Ch. 7.1 - Prob. 2CE Ch. 7.1 - Prob. 3CE Ch. 7.1 - Prob. 4CE Ch. 7.1 - Prob. 5CE Ch. 7.1 - Prob. 6CE Ch. 7.1 - Prob. 7CE Ch. 7.1 - Prob. 8CE Ch. 7.1 - Prob. 9CE Ch. 7.1 - Prob. 10CE

Ch. 7.1 - Prob. 11CE Ch. 7.1 - Prob. 12CE Ch. 7.1 - Prob. 13CE Ch. 7.1 - Prob. 14CE Ch. 7.1 - Prob. 15CE Ch. 7.1 - Prob. 16CE Ch. 7.1 - Prob. 17CE Ch. 7.1 - Prob. 18CE Ch. 7.1 - Prob. 1WE Ch. 7.1 - Prob. 2WE Ch. 7.1 - Prob. 3WE Ch. 7.1 - Prob. 4WE Ch. 7.1 - Prob. 5WE Ch. 7.1 - Prob. 6WE Ch. 7.1 - Prob. 7WE Ch. 7.1 - Prob. 8WE Ch. 7.1 - Prob. 9WE Ch. 7.1 - Prob. 10WE Ch. 7.1 - Prob. 11WE Ch. 7.1 - Prob. 12WE Ch. 7.1 - Prob. 13WE Ch. 7.1 - Prob. 14WE Ch. 7.1 - Prob. 15WE Ch. 7.1 - Prob. 16WE Ch. 7.1 - Prob. 17WE Ch. 7.1 - Prob. 18WE Ch. 7.1 - Prob. 19WE Ch. 7.1 - Prob. 20WE Ch. 7.1 - Prob. 21WE Ch. 7.1 - Prob. 22WE Ch. 7.1 - Prob. 23WE Ch. 7.1 - Prob. 24WE Ch. 7.1 - Prob. 25WE Ch. 7.1 - Prob. 26WE Ch. 7.1 - Prob. 27WE Ch. 7.1 - Prob. 28WE Ch. 7.1 - Prob. 29WE Ch. 7.1 - Prob. 30WE Ch. 7.1 - Prob. 31WE Ch. 7.1 - Prob. 32WE Ch. 7.1 - Prob. 33WE Ch. 7.1 - Prob. 34WE Ch. 7.1 - Prob. 35WE Ch. 7.1 - Prob. 36WE Ch. 7.2 - Prob. 1CE Ch. 7.2 - Prob. 2CE Ch. 7.2 - Prob. 3CE Ch. 7.2 - Prob. 4CE Ch. 7.2 - 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Prob. 2MCE Ch. 7 - Prob. 3MCE Ch. 7 - Prob. 4MCE Ch. 7 - Prob. 5MCE Ch. 7 - Prob. 1ASNE Ch. 7 - Prob. 2ASNE Ch. 7 - Prob. 3ASNE Ch. 7 - Prob. 4ASNE Ch. 7 - Prob. 5ASNE Ch. 7 - Prob. 6ASNE Ch. 7 - Prob. 7ASNE Ch. 7 - Prob. 8ASNE Ch. 7 - Prob. 9ASNE Ch. 7 - Prob. 10ASNE Ch. 7 - Prob. 11ASNE Ch. 7 - Prob. 12ASNE Ch. 7 - Prob. 13ASNE Ch. 7 - Prob. 14ASNE Ch. 7 - Prob. 15ASNE Ch. 7 - Prob. 16ASNE Ch. 7 - Prob. 1CPE Ch. 7 - Prob. 2CPE Ch. 7 - Prob. 3CPE Ch. 7 - Prob. 4CPE Ch. 7 - Prob. 5CPE Ch. 7 - Prob. 6CPE Ch. 7 - Prob. 7CPE Ch. 7 - Prob. 8CPE Ch. 7 - Prob. 9CPE Ch. 7 - Prob. 1AE Ch. 7 - Prob. 2AE Ch. 7 - Prob. 3AE Ch. 7 - Prob. 4AE Ch. 7 - Prob. 5AE Ch. 7 - Prob. 6AE Ch. 7 - Prob. 7AE Ch. 7 - Prob. 8AE Ch. 7 - Prob. 9AE Ch. 7 - Prob. 10AE Ch. 7 - Prob. 11AE Ch. 7 - Prob. 12AE Ch. 7 - Prob. 13AE Ch. 7 - Prob. 14AE Ch. 7 - Prob. 15AE Ch. 7 - Prob. 1PE Ch. 7 - Prob. 2PE Ch. 7 - Prob. 3PE Ch. 7 - Prob. 4PE Ch. 7 - Prob. 5PE Ch. 7 - Prob. 6PE

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