McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Concept explainers

Ratios

A ratio is a comparison between two numbers of the same kind. It represents how many times one number contains another. It also represents how small or large one number is compared to the other.

Trigonometric Ratios

Trigonometric ratios give values of trigonometric functions. It always deals with triangles that have one angle measuring 90 degrees. These triangles are right-angled. We take the ratio of sides of these triangles.

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Question

Chapter 7.1, Problem 29WE

To determine

To find: measure of each angle of a hexagon given the ratio of its angles.

Expert Solution & Answer

Answer to Problem 29WE

The measure of each angle of the hexagon is 72°,90°,90°,144°,162°,162°

Explanation of Solution

Given Information: The ratio between angles of a hexagon is 4:5:5:8:9:9

Formula Used:

The sum of interior angles of a hexagon is 720⁰

Calculation:

A hexagon has six sides and six interior angles. Since ratio of the angles is always in the simplified form, it might not represent the actual measure. So, considering the angles as 4x, 5x ,5x,8x,9x and 9x, the sum of the angles of the hexagon can be expressed using the above relation as,

4x+5x+5x+8x+9x+9x=72040x=720x=72040=18

So each of the angles are given by,

4x=4×18=72°

5x=5×18=90°

8x=8×18=144°

9x=9×18=162°

Thus, the angles of the hexagon are 72°,90°,90°,144°,162°,162° .

Chapter 7.1, Problem 28WE

Chapter 7.1, Problem 30WE

Chapter 7 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 7.1 - Prob. 1CE Ch. 7.1 - Prob. 2CE Ch. 7.1 - Prob. 3CE Ch. 7.1 - Prob. 4CE Ch. 7.1 - Prob. 5CE Ch. 7.1 - Prob. 6CE Ch. 7.1 - Prob. 7CE Ch. 7.1 - Prob. 8CE Ch. 7.1 - Prob. 9CE Ch. 7.1 - Prob. 10CE

Ch. 7.1 - Prob. 11CE Ch. 7.1 - Prob. 12CE Ch. 7.1 - Prob. 13CE Ch. 7.1 - Prob. 14CE Ch. 7.1 - Prob. 15CE Ch. 7.1 - Prob. 16CE Ch. 7.1 - Prob. 17CE Ch. 7.1 - Prob. 18CE Ch. 7.1 - Prob. 1WE Ch. 7.1 - Prob. 2WE Ch. 7.1 - Prob. 3WE Ch. 7.1 - Prob. 4WE Ch. 7.1 - Prob. 5WE Ch. 7.1 - Prob. 6WE Ch. 7.1 - Prob. 7WE Ch. 7.1 - Prob. 8WE Ch. 7.1 - Prob. 9WE Ch. 7.1 - Prob. 10WE Ch. 7.1 - Prob. 11WE Ch. 7.1 - Prob. 12WE Ch. 7.1 - Prob. 13WE Ch. 7.1 - Prob. 14WE Ch. 7.1 - Prob. 15WE Ch. 7.1 - Prob. 16WE Ch. 7.1 - Prob. 17WE Ch. 7.1 - Prob. 18WE Ch. 7.1 - Prob. 19WE Ch. 7.1 - Prob. 20WE Ch. 7.1 - Prob. 21WE Ch. 7.1 - Prob. 22WE Ch. 7.1 - Prob. 23WE Ch. 7.1 - Prob. 24WE Ch. 7.1 - Prob. 25WE Ch. 7.1 - Prob. 26WE Ch. 7.1 - Prob. 27WE Ch. 7.1 - Prob. 28WE Ch. 7.1 - Prob. 29WE Ch. 7.1 - Prob. 30WE Ch. 7.1 - Prob. 31WE Ch. 7.1 - Prob. 32WE Ch. 7.1 - Prob. 33WE Ch. 7.1 - Prob. 34WE Ch. 7.1 - Prob. 35WE Ch. 7.1 - Prob. 36WE Ch. 7.2 - Prob. 1CE Ch. 7.2 - Prob. 2CE Ch. 7.2 - Prob. 3CE Ch. 7.2 - Prob. 4CE Ch. 7.2 - Prob. 5CE Ch. 7.2 - Prob. 6CE Ch. 7.2 - Prob. 7CE Ch. 7.2 - Prob. 8CE Ch. 7.2 - Prob. 9CE Ch. 7.2 - Prob. 10CE Ch. 7.2 - Prob. 11CE Ch. 7.2 - Prob. 12CE Ch. 7.2 - Prob. 13CE Ch. 7.2 - Prob. 14CE Ch. 7.2 - Prob. 15CE Ch. 7.2 - Prob. 16CE Ch. 7.2 - Prob. 1WE Ch. 7.2 - Prob. 2WE Ch. 7.2 - Prob. 3WE Ch. 7.2 - Prob. 4WE Ch. 7.2 - Prob. 5WE Ch. 7.2 - Prob. 6WE Ch. 7.2 - Prob. 7WE Ch. 7.2 - Prob. 8WE Ch. 7.2 - Prob. 9WE Ch. 7.2 - Prob. 10WE Ch. 7.2 - Prob. 11WE Ch. 7.2 - Prob. 12WE Ch. 7.2 - Prob. 13WE Ch. 7.2 - Prob. 14WE Ch. 7.2 - Prob. 15WE Ch. 7.2 - Prob. 16WE Ch. 7.2 - Prob. 17WE Ch. 7.2 - Prob. 18WE Ch. 7.2 - Prob. 19WE Ch. 7.2 - Prob. 20WE Ch. 7.2 - Prob. 21WE Ch. 7.2 - Prob. 22WE Ch. 7.2 - Prob. 23WE Ch. 7.2 - Prob. 24WE Ch. 7.2 - Prob. 25WE Ch. 7.2 - Prob. 26WE Ch. 7.2 - Prob. 27WE Ch. 7.2 - Prob. 28WE Ch. 7.2 - Prob. 29WE Ch. 7.2 - Prob. 30WE Ch. 7.2 - Prob. 31WE Ch. 7.2 - Prob. 32WE Ch. 7.2 - Prob. 33WE Ch. 7.2 - Prob. 34WE Ch. 7.2 - Prob. 35WE Ch. 7.2 - Prob. 36WE Ch. 7.2 - Prob. 37WE Ch. 7.2 - 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