COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Question
Chapter 7, Problem 54QAP
To determine
The speed and direction of the combined two-car wreck immediately after collision
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COLLEGE PHYSICS
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- A head-on, elastic collision occurs between two billiard balls of equal mass. If a red ball is traveling to the right with speed v and a blue ball is traveling to the left with speed 3v before the collision, what statement is true concerning their velocities subsequent to the collision? Neglect any effects of spin. (a) The red ball travels to the left with speed v, while the blue ball travels to the right with speed 3v. (b) The red ball travels to the left with speed v, while the blue ball continues to move to the left with a speed 2v. (c) The red ball travels to the left with speed 3v, while the blue ball travels to the right with speed v. (d) Their final velocities cannot be determined because momentum is not conserved in the collision. (e) The velocities cannot be determined without knowing the mass of each ball.arrow_forwardA 65.0-kg person throws a 0.045 0-kg snowball forward with a ground speed of 30.0 m/s. A second person, with a mass of 60.0 kg, catches the snowball. Both people are on skates. The first person is initially moving forward with a speed of 2.50 m/s, and the second person is initially at rest. What are the velocities of the two people after the snowball is exchanged? Disregard friction between the skates and the ice.arrow_forwardProfessional Application Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1200 kg and is approaching at 8.00 m/s due south. The second car has a mass of 850 kg and is approaching at 17.0 m/s due west. (a) Calculate the final velocity (magnitude and direction) of the cars. (b) How much kinetic energy is lost in the collision? (This energy goes into deformation of the cars.) Note that because both cars have an initial velocity, you cannot use the equations for conservation of momentum along the x-axis and y-axis; instead, you must look for other simplifying aspects.arrow_forward
- Consider a frictionless track as shown in Figure P6.62. A block of mass m1 = 5.00 kg is released from . It makes a head-on elastic collision at with a block of mass m2= 10.0 kg that is initially at rest. Calculate the maximum height to which m1 rises after the collision. Figure P6.62arrow_forwardA 3.00-kg steel ball strikes a wall with a speed of 10.0 m/s an angle of = 60.0 with the surface. It bounces off with the same speed and angle (Fig. P9.67). If the ball is in contact with the wall for 0.200 s, what is the average force exerted by the wall on the ball?arrow_forwardA car of mass 750 kg traveling at a velocity of 27 m/s in the positive x-direction crashes into the rear of a truck of mass 1 500 kg that is at rest and in neutral at an intersection. If the collision is inelastic and the truck moves forward at 15.0 m/s, what is the velocity of the car after the collision? (See Section 6.3.)arrow_forward
- Consider a frictionless track as shown in Figure P6.62. A block of mass m1 = 5.00 kg is released from . It makes a head-on elastic collision at with a block of mass m2= 10.0 kg that is initially at rest. Calculate the maximum height to which m1 rises after the collision. Figure P6.62arrow_forwardA 65.0-kg person throws a 0.045 0-kg snowball forward with a ground speed of 30.0 m/s. A second person, with a mass of 60.0 kg, catches the snowball. Both people are on skates. The first person is initially moving forward with a speed of 2.50 m/s, and the second person is initially at rest. What are the velocities of the two people after the snowball is exchanged? Disregard friction between the skates and the ice.arrow_forwardProfessional Application Explain in terms of impulse how padding reduces forces in a collision. State this in terms of a real example, such as the advantages of a carpeted vs, tile floor for a day care center.arrow_forward
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Elastic and Inelastic Collisions; Author: Professor Dave Explains;https://www.youtube.com/watch?v=M2xnGcaaAi4;License: Standard YouTube License, CC-BY