COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 7, Problem 62QAP
To determine
The average force exerted
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A 0.062-kg tennis ball, traveling at 20m/s, hits a wall, rebounds with the same speed in the opposite direction, and is hit again by another player, causing the ball to return to the wall at the same speed. The collision of the ball with the wall lasts 1.0 ms. The ball returns to the wall once every 0.60 s.
Determine the magnitude of the average force exerted on the ball during a single collision.
Determine the force that the ball exerts on the wall averaged over the time between collisions.
A 7.500 E+3-kg truck moving east at 10.3 m/s collides with a 2.500 E+3-kg car moving west at 35.0 m/s. The collision takes place over a time interval of 0.5 s. The car and the truck stick together after the collision. Find the force (in N) of the car on the truck during the collision. Call this force positive if it points to the east, and negative if it points to the west. (Could you give an explanation on how to transfer/ convert E +3)
A baseball fan layer pitches a ball toward home plate at a speed of 41 m/s . The batter swings, connects with the ball of mass 290 g and hits it so that the ball leaves the bat with a speed of 37 m/s . Assume you he ball is moving horizontally just before and just after the collision with the bat.
if the bat and ball are in contact for 3.00 m/s what is the magnitude of the average force exerted on the ball by the bat?
in kN
Chapter 7 Solutions
COLLEGE PHYSICS
Ch. 7 - Prob. 1QAPCh. 7 - Prob. 2QAPCh. 7 - Prob. 3QAPCh. 7 - Prob. 4QAPCh. 7 - Prob. 5QAPCh. 7 - Prob. 6QAPCh. 7 - Prob. 7QAPCh. 7 - Prob. 8QAPCh. 7 - Prob. 9QAPCh. 7 - Prob. 10QAP
Ch. 7 - Prob. 11QAPCh. 7 - Prob. 12QAPCh. 7 - Prob. 13QAPCh. 7 - Prob. 14QAPCh. 7 - Prob. 15QAPCh. 7 - Prob. 16QAPCh. 7 - Prob. 17QAPCh. 7 - Prob. 18QAPCh. 7 - Prob. 19QAPCh. 7 - Prob. 20QAPCh. 7 - Prob. 21QAPCh. 7 - Prob. 22QAPCh. 7 - Prob. 23QAPCh. 7 - Prob. 24QAPCh. 7 - Prob. 25QAPCh. 7 - Prob. 26QAPCh. 7 - Prob. 27QAPCh. 7 - Prob. 28QAPCh. 7 - Prob. 29QAPCh. 7 - Prob. 30QAPCh. 7 - Prob. 31QAPCh. 7 - Prob. 32QAPCh. 7 - Prob. 33QAPCh. 7 - Prob. 34QAPCh. 7 - Prob. 35QAPCh. 7 - Prob. 36QAPCh. 7 - Prob. 37QAPCh. 7 - Prob. 38QAPCh. 7 - Prob. 39QAPCh. 7 - Prob. 40QAPCh. 7 - Prob. 41QAPCh. 7 - Prob. 42QAPCh. 7 - Prob. 43QAPCh. 7 - Prob. 44QAPCh. 7 - Prob. 45QAPCh. 7 - Prob. 46QAPCh. 7 - Prob. 47QAPCh. 7 - Prob. 48QAPCh. 7 - Prob. 49QAPCh. 7 - Prob. 50QAPCh. 7 - Prob. 51QAPCh. 7 - Prob. 52QAPCh. 7 - Prob. 53QAPCh. 7 - Prob. 54QAPCh. 7 - Prob. 55QAPCh. 7 - Prob. 56QAPCh. 7 - Prob. 57QAPCh. 7 - Prob. 58QAPCh. 7 - Prob. 59QAPCh. 7 - Prob. 60QAPCh. 7 - Prob. 61QAPCh. 7 - Prob. 62QAPCh. 7 - Prob. 63QAPCh. 7 - Prob. 64QAPCh. 7 - Prob. 65QAPCh. 7 - Prob. 66QAPCh. 7 - Prob. 67QAPCh. 7 - Prob. 68QAPCh. 7 - Prob. 69QAPCh. 7 - Prob. 70QAPCh. 7 - Prob. 71QAPCh. 7 - Prob. 72QAPCh. 7 - Prob. 73QAPCh. 7 - Prob. 74QAPCh. 7 - Prob. 75QAPCh. 7 - Prob. 76QAPCh. 7 - Prob. 77QAPCh. 7 - Prob. 78QAPCh. 7 - Prob. 79QAPCh. 7 - Prob. 80QAPCh. 7 - Prob. 81QAPCh. 7 - Prob. 82QAPCh. 7 - Prob. 83QAPCh. 7 - Prob. 84QAPCh. 7 - Prob. 85QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Consider a frictionless track as shown in Figure P6.62. A block of mass m1 = 5.00 kg is released from . It makes a head-on elastic collision at with a block of mass m2= 10.0 kg that is initially at rest. Calculate the maximum height to which m1 rises after the collision. Figure P6.62arrow_forwardProfessional Application The Moon's craters are remnants of meteorite collisions. Suppose a fairly large asteroid that has a mass of 5.001012 kg (about a kilometer across) strikes the Moon ata speed of 15.0 km/s. (a) At what speed does the Moon recoil after the perfectly inelastic collision (the mass of the Moon is 7.361022 kg) ? (b) How much kinetic energy is lost in the collision? Such an event may have been observed by medieval English monks who reported observing a red glow and subsequent haze about the Moon. (c) In October 2009, NASA crashed a rocket into the Moon, and analyzed the plume produced by the impact. (Significant amounts of water were detected.) Answer part (a) and (b) for this real-life experiment. The mass of the rocket was 2000 kg and its speed upon impact was 9000 km/h. How does the plume produced alter these results?arrow_forwardProfessional Application (a) Calculate the maximum rate at which a rocket can expel gases if its acceleration cannot exceed seven times that of gravity. The mass of the rocket just as it runs out of fuel is 75,000-kg, and its exhaust velocity is 2.40103 m/s. Assume that the acceleration of gravity is the same as on Earth's surface (9.80 m/s2). (b) Why might it be necessary to limit the acceleration of a rocket?arrow_forward
- A billiard ball moving at 5.00 m/s strikes a stationary ball of the same mass. Alter the collision, the first ball moves at 4.33 m/s at an angle of 30.0 with respect to the original line of motion, (a) Find the velocity (magnitude and direction) of the second ball after collision, (h) Was the collision inelastic or elastic?arrow_forwardConsider a frictionless track as shown in Figure P6.62. A block of mass m1 = 5.00 kg is released from . It makes a head-on elastic collision at with a block of mass m2= 10.0 kg that is initially at rest. Calculate the maximum height to which m1 rises after the collision. Figure P6.62arrow_forwardSuppose a gangster sprays Superman’s chest with 3 g bullets at the rate of 100 bullets/min, and the speed of each bullet is 500 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman’s chest?arrow_forward
- A car with a mass of 970 kg and a speed of v1 = 17.5 m/s approaches an intersection, as shown in the figure. A 1300 kg minivan traveling at v2 is heading for the same intersection. The car and minivan collide and stick together. The direction of the wreckage after the collision is θ = 44.0 degrees above the x axis. Find the initial speed of the minivan, assuming external forces can be ignored. Find the final speed of the wreckage.arrow_forwardAn object of mass 20.00 kg, moving with an initial velocity of 5.00 m/s in the positive x direction, collides with and sticks to an object of mass 10.00 kg with an initial velocity (in the negative x direction) of -00 m/s. Find the change in kinetic energy of the system.arrow_forwardWe commonly see Superman being shot and bullets bounce off of him. Suppose Mr. Bad shoots Superman with 4.00 kg bullets at a rate of 100 bullets/min for 5.00 s. If the speed of each bullet is 480.00 m/s and rebounds straight back with no change in speed, calculate the magnitude of the average force experienced by Superman due to all the bullets.arrow_forward
- A 60-g tennis ball initially at rest is hit by a racket. The ball is in contact with the racket for a time of ∆t. After impact, the ball moves at a speed of 120 km / h. If the average force exerted by the racket on the ball was 1.0 × 103 N, find the contact time ∆t.arrow_forwardBob and Jim decide to play tug-of-war on a frictionless (icy) surface. Jim is considerably stronger than Bob, but Bob weighs 160 lb whereas Jim weighs 145 lb. Who loses by crossing over the midline first? Explain.arrow_forwardDuring a storm, rain comes straight down at a rate of 46.8 kph and perpendicularly hits the roof of a vehicle. Assuming the mass of rain per second that strikes the vehicle's roof is 270 kg/hr. Considering that the rain comes to rest upon striking the car, find the average force exerted by the vehicle's roof on that rain.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY