Foundations Of Astronomy, Loose-leaf Version
Foundations Of Astronomy, Loose-leaf Version
13th Edition
ISBN: 9781305637986
Author: Michael A. Seeds, Dana Backman
Publisher: Brooks Cole
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Chapter 7, Problem 9P
To determine

The wavelength of the photon.

The part of the electromagnetic spectrum.

The electron starting and finishing point in the orbit.

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Visible light falls into wavelength ranges of 400-700 nm, for which  1 m=1×109 nm The energy and wavelength of light are related by the equationE=hcλ where E is energy in Joules, h is Planck's constant ( 6.626×10−34 J-s ), c is the speed of light ( 2.998×108 m/s), and λ is the wavelength in m. If a visible light photon has a wavelength of 632.3 nm, what is the energy of the photon (in J)?
A photon has an energy of 1.9 meV (milli electron Volt). What is the wavelength of this photon, expressed in micrometers? Keep four significant digits. And the answer is NOT 6.543
a) What is the wavelength lambda (m) of green light having a frequency of 5.7 x 10^14 Hz. b). Determine the energy (J) of each photon of the green light using the formula E = hf, where E is energy in Joules, h is Planck's constant (6.62 x 10^-34 J/s) and f is frequency in Hz.
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