   Chapter 7.2, Problem 11E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Sketching a Plane in Space In Exercises 1-12, find the x-, y-, and z-intercepts of the plane. Then sketch the plane. See Example 1. x − 3 z = 3

To determine

To calculate: The x-intercept, y-intercept and z-intercept of the plane, x3z=3 and sketch the plane.

Explanation

Given information:

The equation of plane is x3z=3.

Calculation:

Consider equation of plane,

x3z=3 ...... (1)

Substitute, 0 for z and in equation (1).

x3(0)=3x=3

Hence, the x-intercept of the plane, x3z=3 is (3,0,0).

Substitute, 0 for x and in equation (1).

03z=3z=1

Hence, the z-intercept of the plane, x3z=3 is (0,0,1).

Since plane, x3z=3 parallel to y-axis but perpendicular to x-y plane.

Therefore, the plane, x3z=3 intersect at y-axis at infinity.

There is no y-intercept.

Graph:

Consider the rectangular co-ordinate system x, y and z

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