   Chapter 7.2, Problem 12E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Sketching a Plane in Space In Exercises 1-12, find the x-, y-, and z-intercepts of the plane. Then sketch the plane. See Example 1. 5 y − 3 z = 15

To determine

To calculate: The x-intercept, y-intercept and z-intercept of the plane, 5y3z=15 and sketch the plane.

Explanation

Given information:

The equation of plane is 5y3z=15.

Calculation:

Consider equation of plane,

5y3z=15 ...... (1)

Substitute, 0 for z and in equation (1).

5y3(0)=15y=3

Hence, the y-intercept of the plane, 5y3z=15 is (0,3,0).

Substitute, 0 for z and in equation (1).

5(0)3z=15z=5

Hence, the z-intercept of the plane, 5y3z=15 is (0,0,5).

Since plane, 5y3z=15 parallel to x-axis but perpendicular to y-z plane.

Therefore, the plane, 5y3z=15 intersect at y-axis at infinity.

There is no x-intercept.

Graph:

Consider the rectangular co-ordinate system x, y and z

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