   Chapter 7.2, Problem 4E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Sketching a Plane in Space In Exercises 1-12, find the x-, y-, and z-intercepts of the plane. Then sketch the plane. See Example 1. 3 x + 6 y + 2 z = 6

To determine

To calculate: The x-intercept, y-intercept and z-intercept of the plane, 3x+6y+2z=6 and sketch the plane.

Explanation

Given information:

The equation of plane is 3x+6y+2z=6.

Formula used:

The general equation of plane,

ax+by+cz=d

The x-intercept of the plane, ax+by+cz=d can be calculated by substituting 0 for y and 0 for z, the y-intercept of the plane, ax+by+cz=d can be calculated by substituting 0 for x and 0 for z and the z-intercept of the plane, ax+by+cz=d can be calculated by substituting 0 for x and 0 for y.

Calculation:

Consider equation of plane,

3x+6y+2z=6 ...... (1)

Substitute, 0 for y and 0 for z in equation (1).

3(x)+6(0)+2(0)=63x=6x=2

Hence, the x-intercept of the plane, 3x+6y+2z=6 is (2,0,0).

Substitute, 0 for x and 0 for z in equation (1).

3(0)+6(y)+2(0)=66y=6y=1

Hence, the y-intercept of the plane, 3x+6y+2z=6 is (0,1,0).

Substitute, 0 for x and 0 for y in equation (1)

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