BIG IDEAS MATH Integrated Math 1: Student Edition 2016
BIG IDEAS MATH Integrated Math 1: Student Edition 2016
16th Edition
ISBN: 9781680331127
Author: HOUGHTON MIFFLIN HARCOURT
Publisher: Houghton Mifflin Harcourt
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Chapter 7.3, Problem 19E

(a)

To determine

To describe:

The shape of each distribution data in a given data.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given:

Each entry in a two −way table

Concept used:

Bivariate joint frequency distribution are contingency table.

The total row and total column of the marginal distribution while the body of the table is the joint frequencies

Calculation:

The distribution for freshmen is symmetric and the distribution for sophomores is skewed left.

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7.3, Problem 19E

(b)

To determine

To explain:

The number of songs downloaded by freshmen to the number of songs downloaded sophomores.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given:

Each entry in a two −way table

Concept used:

Bivariate joint frequency distribution are contingency table.

The total row and total column of the marginal distribution while the body of the table is the joint frequencies

Calculation:

The most data are the five-number summary because the median is closer to either Q1orQ3

The centers and spreads of the two data sets are quite different from each other.

The median for sophomores is 850 more than the mean for freshmen.

So, sophomores is more variability in the number of songs downloaded by sophomores.

(c)

To determine

To explain:

The songs downloaded between 730and1570 songs on MP3 players.

(c)

Expert Solution
Check Mark

Explanation of Solution

Given:

Each entry in a two −way table

Concept used:

Bivariate joint frequency distribution are contingency table.

The total row and total column of the marginal distribution while the body of the table is the joint frequencies

Calculation:

For symmetric distribution :-the mean corresponds to half of the data on Q2 and the

Standard deviation is the variation from the mean.

For skewed distribution :-the median corresponds to most likely lie

The most data are the five-number summary because the median is closer to either Q1orQ3 .

Assuming a symmetric distribution is bell-shaped

  68% of the data lie within 1 standard deviation of the mean.

Because the mean is 1150 and the standard deviation is 420 ,the interval from 7301570 represent about 68% of the data.

So,expect about 0.68(45)31 of the freshmen to have downloaded 7301570 songs.

(d)

To determine

To explain:

The songs downloaded between 310and1990 songs on MP3 players.

(d)

Expert Solution
Check Mark

Explanation of Solution

Given:

Each entry in a two −way table

Concept used:

Bivariate joint frequency distribution are contingency table.

The total row and total column of the marginal distribution while the body of the table is the joint frequencies

Calculation:

For symmetric distribution :-the mean corresponds to half of the data on Q2 and the

Standard deviation is the variation from the mean.

For skewed distribution :-the median corresponds to most likely lie

The most data are the five-number summary because the median is closer to either Q1orQ3 .

Assuming a symmetric distribution is bell-shaped

  95% of the data lie within 2 standard deviation of the mean.

Because the mean is 1150 and the standard deviation is 420 ,the interval from 3101990 represent about 95% of the data.

So,expect about 0.95(45)31 of the freshmen to have downloaded 3101990 songs.

Chapter 7 Solutions

BIG IDEAS MATH Integrated Math 1: Student Edition 2016

Ch. 7.1 - Prob. 11ECh. 7.1 - Prob. 12ECh. 7.1 - Prob. 13ECh. 7.1 - Prob. 14ECh. 7.1 - Prob. 15ECh. 7.1 - Prob. 16ECh. 7.1 - Prob. 17ECh. 7.1 - Prob. 18ECh. 7.1 - Prob. 19ECh. 7.1 - Prob. 20ECh. 7.1 - Prob. 21ECh. 7.1 - Prob. 22ECh. 7.1 - Prob. 23ECh. 7.1 - Prob. 24ECh. 7.1 - Prob. 25ECh. 7.1 - Prob. 26ECh. 7.1 - Prob. 27ECh. 7.1 - Prob. 28ECh. 7.1 - Prob. 29ECh. 7.1 - Prob. 30ECh. 7.1 - Prob. 31ECh. 7.1 - Prob. 32ECh. 7.1 - Prob. 33ECh. 7.1 - Prob. 34ECh. 7.1 - Prob. 35ECh. 7.1 - Prob. 36ECh. 7.1 - Prob. 37ECh. 7.1 - Prob. 38ECh. 7.1 - Prob. 39ECh. 7.1 - Prob. 40ECh. 7.1 - Prob. 41ECh. 7.1 - Prob. 42ECh. 7.1 - Prob. 43ECh. 7.1 - Prob. 44ECh. 7.1 - Prob. 45ECh. 7.1 - Prob. 46ECh. 7.1 - Prob. 47ECh. 7.2 - Prob. 1ECh. 7.2 - Prob. 2ECh. 7.2 - Prob. 3ECh. 7.2 - Prob. 4ECh. 7.2 - Prob. 5ECh. 7.2 - Prob. 6ECh. 7.2 - Prob. 7ECh. 7.2 - Prob. 8ECh. 7.2 - Prob. 9ECh. 7.2 - Prob. 10ECh. 7.2 - Prob. 11ECh. 7.2 - Prob. 12ECh. 7.2 - Prob. 13ECh. 7.2 - Prob. 14ECh. 7.2 - Prob. 15ECh. 7.2 - Prob. 16ECh. 7.2 - Prob. 17ECh. 7.2 - Prob. 18ECh. 7.2 - Prob. 19ECh. 7.2 - Prob. 20ECh. 7.2 - Prob. 21ECh. 7.2 - Prob. 22ECh. 7.2 - Prob. 23ECh. 7.2 - Prob. 24ECh. 7.2 - Prob. 25ECh. 7.2 - Prob. 26ECh. 7.2 - Prob. 27ECh. 7.3 - Prob. 1ECh. 7.3 - Prob. 2ECh. 7.3 - Prob. 3ECh. 7.3 - Prob. 4ECh. 7.3 - Prob. 5ECh. 7.3 - Prob. 6ECh. 7.3 - Prob. 7ECh. 7.3 - Prob. 8ECh. 7.3 - Prob. 9ECh. 7.3 - Prob. 10ECh. 7.3 - Prob. 11ECh. 7.3 - Prob. 12ECh. 7.3 - Prob. 13ECh. 7.3 - Prob. 14ECh. 7.3 - Prob. 15ECh. 7.3 - Prob. 16ECh. 7.3 - Prob. 17ECh. 7.3 - Prob. 18ECh. 7.3 - Prob. 19ECh. 7.3 - Prob. 20ECh. 7.3 - Prob. 21ECh. 7.3 - Prob. 22ECh. 7.3 - Prob. 23ECh. 7.3 - Prob. 24ECh. 7.3 - Prob. 25ECh. 7.3 - Prob. 26ECh. 7.3 - Prob. 27ECh. 7.3 - Prob. 28ECh. 7.3 - Prob. 1QCh. 7.3 - Prob. 2QCh. 7.3 - Prob. 3QCh. 7.3 - Prob. 4QCh. 7.3 - Prob. 5QCh. 7.3 - Prob. 6QCh. 7.3 - Prob. 7QCh. 7.3 - Prob. 8QCh. 7.3 - Prob. 9QCh. 7.4 - Prob. 1ECh. 7.4 - Prob. 2ECh. 7.4 - Prob. 3ECh. 7.4 - Prob. 4ECh. 7.4 - Prob. 5ECh. 7.4 - Prob. 6ECh. 7.4 - Prob. 7ECh. 7.4 - Prob. 8ECh. 7.4 - Prob. 9ECh. 7.4 - Prob. 10ECh. 7.4 - Prob. 11ECh. 7.4 - Prob. 12ECh. 7.4 - Prob. 13ECh. 7.4 - Prob. 14ECh. 7.4 - Prob. 15ECh. 7.4 - Prob. 16ECh. 7.4 - Prob. 17ECh. 7.4 - Prob. 18ECh. 7.4 - Prob. 19ECh. 7.4 - Prob. 20ECh. 7.4 - Prob. 21ECh. 7.4 - Prob. 22ECh. 7.4 - Prob. 23ECh. 7.4 - Prob. 24ECh. 7.4 - Prob. 25ECh. 7.4 - Prob. 26ECh. 7.4 - Prob. 27ECh. 7.4 - Prob. 28ECh. 7.4 - Prob. 29ECh. 7.4 - Prob. 30ECh. 7.4 - Prob. 31ECh. 7.4 - Prob. 32ECh. 7.4 - Prob. 33ECh. 7.4 - Prob. 34ECh. 7.5 - Prob. 1ECh. 7.5 - Prob. 2ECh. 7.5 - Prob. 3ECh. 7.5 - Prob. 4ECh. 7.5 - Prob. 5ECh. 7.5 - Prob. 6ECh. 7.5 - Prob. 7ECh. 7.5 - Prob. 8ECh. 7.5 - Prob. 9ECh. 7.5 - Prob. 10ECh. 7.5 - Prob. 11ECh. 7.5 - Prob. 12ECh. 7.5 - Prob. 13ECh. 7.5 - Prob. 14ECh. 7.5 - Prob. 15ECh. 7.5 - Prob. 16ECh. 7.5 - Prob. 17ECh. 7.5 - Prob. 18ECh. 7.5 - Prob. 19ECh. 7.5 - Prob. 20ECh. 7.5 - Prob. 21ECh. 7.5 - Prob. 22ECh. 7.5 - Prob. 23ECh. 7.5 - Prob. 24ECh. 7.5 - Prob. 25ECh. 7.5 - Prob. 26ECh. 7.5 - Prob. 27ECh. 7.5 - Prob. 28ECh. 7.5 - Prob. 29ECh. 7.5 - Prob. 30ECh. 7.5 - Prob. 31ECh. 7.5 - Prob. 32ECh. 7.5 - Prob. 33ECh. 7 - Prob. 1CRCh. 7 - Prob. 2CRCh. 7 - Prob. 3CRCh. 7 - Prob. 4CRCh. 7 - Prob. 5CRCh. 7 - Prob. 6CRCh. 7 - Prob. 7CRCh. 7 - Prob. 8CRCh. 7 - Prob. 9CRCh. 7 - Prob. 10CRCh. 7 - Prob. 11CRCh. 7 - Prob. 12CRCh. 7 - Prob. 13CRCh. 7 - Prob. 14CRCh. 7 - Prob. 15CRCh. 7 - Prob. 1CTCh. 7 - Prob. 2CTCh. 7 - Prob. 3CTCh. 7 - Prob. 4CTCh. 7 - Prob. 5CTCh. 7 - Prob. 6CTCh. 7 - Prob. 7CTCh. 7 - Prob. 8CTCh. 7 - Prob. 9CTCh. 7 - Prob. 10CTCh. 7 - Prob. 1CACh. 7 - Prob. 2CACh. 7 - Prob. 3CACh. 7 - Prob. 4CACh. 7 - Prob. 5CACh. 7 - Prob. 6CACh. 7 - Prob. 7CACh. 7 - Prob. 8CACh. 7 - Prob. 9CA
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