   Chapter 7.5, Problem 13QY ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 13-15, find f(1, 0) and f(4, -1). f ( x , y ) = x − 9 y 2

To determine

To calculate: The values of f(1,0) and f(4,1) for the function f(x,y)=x9y2.

Explanation

Given Information:

The provided function is f(x,y)=x9y2.

Calculation:

Consider the function, f(x,y)=x9y2

The value of x and y for f(1,0) are 1 and 0 respectively.

Substitute x=1 and y=0 in the equation f(x,y)=x9y2,

f(1,0)=19(0)2=10=1

The value of x and y for f(4,1) are 4 and 1 respectively

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Differentiate. H(u)=(uu)(u+u)

Single Variable Calculus: Early Transcendentals, Volume I

#### In Problems 83 and 84, simplify each complex fraction. x1x1x1x1+1

Mathematical Applications for the Management, Life, and Social Sciences

#### j × (−k) = i −i j + k −j − k

Study Guide for Stewart's Multivariable Calculus, 8th

#### True or False: x2x24dx should be evaluated using integration by parts.

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 