Chapter 8, Problem 14MCQ

To determine

To Factor: Factorise the given polynomial..

Answer to Problem 14MCQ

The polynomial $3x^2+6x+x+2$ in the factor form is $(3x+1)(x+2)$ ..

Explanation of Solution

Given information:

The polynomial

  $3x^2+6x+x+2$ .

Factor the polynomial as shown below;

Group the terms with common factor.

  $3x^2+6x+x+2=\left(3x^2+6x\right)+(x+2)$

take $3x$ as common from the first group and 1 as common from the second group.

  $\begin{array}{cc}3x^2+6x+x+2& =\left(3x^2+6x\right)+(x+2)\\ & =3x(x+2)+1(x+2)\\ & =(3x+1)(x+2)\end{array}$

The polynomial $3x^2+6x+x+2$ in the factor form is $(3x+1)(x+2)$ .