Chapter 8.6, Problem 77SR

To determine

To Explain: The intensity of the sound from busy street traffic than sound from normal conversation.

Explanation of Solution

Given information:

The table for intensity of sounds:

Watts Per Square Meter	Common Sounds
${10}^{(-11)}$	Rustling leaves
${10}^{(-10)}$	Whisper
${10}^{(-6)}$	Normal conversation
${10}^{(-5)}$	Busy street traffic
${10}^{(-4)}$	Vaccum cleaner
${10}^{(-1)}$	Front rows of rock concert
${10}^{(1)}$	Threshold of plan
${10}^{(2)}$	Military jet take off

Proof:

Consider the table below:

Watts Per Square Meter	Common Sounds
${10}^{(-11)}$	Rustling leaves
${10}^{(-10)}$	Whisper
${10}^{(-6)}$	Normal conversation
${10}^{(-5)}$	Busy street traffic
${10}^{(-4)}$	Vaccum cleaner
${10}^{(-1)}$	Front rows of rock concert
${10}^{(1)}$	Threshold of plan
${10}^{(2)}$	Military jet take off

The strategy is to say how many times more intense the sound from busy street traffic than sound from normal conversation.

Here the intense of sound for busy street traffic is: ${10}^{-5}$

Again, the intense of sound for normal conversation is: ${10}^{-6}.$

Hence, the number of times will be:

  $\begin{array}{cc}\frac{{10}^{-5}}{{10}^{-6}}=& {10}^{-5-(-6)}\\ =& {10}^{-5+6}\\ & ={10}^1\\ & =10\end{array}$

Therefore, the sound from busy street traffic is 10 times more intense than sound from normal conversation.