Explanation Given data: The mass of electron is, m = 9.11 × 10 − 31 kg . The velocity of the electron is, v = 4.3 × 10 6 m ⋅ s − 1 . Formula used: The de Broglie relation is given by, λ = h p ……(1) Here, λ is the wavelength, p is the momentum and h is planck constant. The momentum of a particle is given by: p = m v ……(2) Here, m is the mass, p is the momentum and v is the velocity of the particle. Explanation: Calculate the momentum of electron. Substitute 9.11 × 10 − 31 kg for m and 4.3 × 10 6 m ⋅ s − 1 for v in the equation (2). p = m v = ( 9.11 × 10 − 31 kg ) ⋅ ( 4.3 × 10 6 m ⋅ s − 1 ) = 39

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Chapter 8, Problem 1PEB

To determine

The de Broglie wavelength of the electron.

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Chapter 8, Problem 6FFA

Chapter 8, Problem 2PEB

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