BIOCHEMISTRY
9th Edition
ISBN: 2818440090622
Author: BERG
Publisher: MAC HIGHER
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Question
Chapter 8, Problem 44P
Interpretation Introduction
Interpretation:
The step in the given series of reactions that is rate limiting is to be stated. The reason corresponding to the correct choice is to be stated.
Concept introduction:
The Michaelis-Menten equation relates the concentration of substrate with the velocity of the reaction. A constant which expresses the substrate’s concentration if the velocity of reaction equals to the half of the maximum velocity of the reaction is known as Michaelis-Menten constant. The step that can control the overall reaction rate which generates the final product is known as rate limiting step.
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In the reaction Na + Cl à Na+ + Cl-, which component is said to become ‘oxidized’ and which is considered reduced?
Na, Cl
Cl, Cl
Na, Na
Cl, Na
not true about the Michaelis-Menten equation?
The equation that gives the rate, v, of an
the substrate concentration [S] is the Michaelis-Menten equation
= Vmax[S]/(Km + [S]), where V,
enzyme-catalyzed reaction for all values of
max and Km are constants. Which of the following is
a)
for [S] << Km, V = Vmax
applies to most enzymes, but allosteric enzymes have different kinetics
when [S] = Km, then v =
Vmax/2
gives the rate when the enzyme concentration, temperature, pH, and ionic
strength are constant
for very high values of [S], v approaches Vmax
e)
Which is correct about the constant Km in the Michaelis-Menten equation?
also called the catalytic constant or turnover number
equal to the number of product molecules produced per unit time when the
enzyme is saturated with substrate
it is the constant in the first order rate equation v = k[A]
it is the constant in the second order rate equation v =
equal to the substrate concentration at which the velocity or rate of a reaction is
½ the…
For 100 words. What are the two essential requirements to effectively carry out metabolic work?
Chapter 8 Solutions
BIOCHEMISTRY
Ch. 8 - Prob. 1PCh. 8 - Prob. 2PCh. 8 - Prob. 3PCh. 8 - Prob. 4PCh. 8 - Prob. 5PCh. 8 - Prob. 6PCh. 8 - Prob. 7PCh. 8 - Prob. 8PCh. 8 - Prob. 9PCh. 8 - Prob. 10P
Ch. 8 - Prob. 11PCh. 8 - Prob. 12PCh. 8 - Prob. 13PCh. 8 - Prob. 14PCh. 8 - Prob. 15PCh. 8 - Prob. 16PCh. 8 - Prob. 17PCh. 8 - Prob. 18PCh. 8 - Prob. 19PCh. 8 - Prob. 20PCh. 8 - Prob. 21PCh. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Prob. 24PCh. 8 - Prob. 25PCh. 8 - Prob. 26PCh. 8 - Prob. 27PCh. 8 - Prob. 28PCh. 8 - Prob. 29PCh. 8 - Prob. 30PCh. 8 - Prob. 31PCh. 8 - Prob. 32PCh. 8 - Prob. 33PCh. 8 - Prob. 34PCh. 8 - Prob. 35PCh. 8 - Prob. 36PCh. 8 - Prob. 37PCh. 8 - Prob. 38PCh. 8 - Prob. 39PCh. 8 - Prob. 40PCh. 8 - Prob. 41PCh. 8 - Prob. 42PCh. 8 - Prob. 43PCh. 8 - Prob. 44PCh. 8 - Prob. 45PCh. 8 - Prob. 46PCh. 8 - Prob. 47PCh. 8 - Prob. 48PCh. 8 - Prob. 49P
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