The most stable E1 product for each of the given reactions is needed to be drawn. Concept introduction: In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide. E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism. The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical . If the β-positions are different and the products formed are also different . This means the double bond can form in two different regions so this type of reaction is called regioselective . The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes . To draw: the major E1 product for the given reactions.

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Answer 1

Question

Chapter 8, Problem 62PP

(a)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

(b)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

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Answer 2

Question

Chapter 8, Problem 62PP

(a)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

(b)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

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Answer 3

Question

Chapter 8, Problem 62PP

(a)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

(b)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

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Answer 4

Question

Chapter 8, Problem 62PP

(a)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

(b)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

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Answer 5

Chapter 8, Problem 62PP

(a)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

(b)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

Answer 6

Chapter 8, Problem 62PP

(a)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

Answer 7

Chapter 8, Problem 62PP

(a)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The most stable E1 product for each of the given reactions is needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.

E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.

The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.

The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.

To draw: the major E1 product for the given reactions.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 8.3 - Prob. 1LTS Ch. 8.3 - Prob. 1PTS Ch. 8.3 - Prob. 2ATS Ch. 8.3 - Prob. 3ATS Ch. 8.3 - Prob. 4CC Ch. 8.4 - Prob. 2LTS Ch. 8.4 - Prob. 5PTS Ch. 8.4 - Prob. 6ATS Ch. 8.5 - Prob. 3LTS Ch. 8.5 - Prob. 7PTS

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