Explanation Given: y 2 = − 4 y + 2 x + 1 Concept and Formula used: There are two standard forms of parabola given by ( x − h ) 2 = 4 p ( y − k ) with focus ( h , k + p ) , directrix is y = k − p and vertex is ( h , k ) . ( y − k ) 2 = 4 p ( x − h ) with focus ( h + p , k ) , directrix is x = h − p and vertex is ( h , k ) . Graph: As given y 2 = − 4 y + 2 x + 1 we have y 2 = − 4 y + 2 x + 1 ⇒ y 2 + 4 y = 2 x + 1 ⇒ ( y ) 2 + 2 × 2 × y + ( 2 ) 2 = 2 x + 1 + ( 2 ) 2 ⇒ ( y + 2 ) 2 = 2 x + 1 + 4 ⇒ ( y − ( − 2 ) ) 2 = 2 x + 5 ⇒ ( y &

MyLab Math with Pearson eText -- Standalone Access Card -- for Precalculus: A Unit Circle Approach (3rd Edition)

3rd Edition

ISBN: 9780134753164

Author: J. S. Ratti, Marcus S. McWaters, Leslaw Skrzypek

Publisher: PEARSON

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Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.

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Unread DISCUSSION - Do We Really Need the Chain Rule?? Reply Our favorite little Calculus cat, Pucky, is back! He's been watching our online sessions and seeing our homework this week. And through all the rules and methods of this week, Pucky has just one problem. Pucky doesn't believe in the Chain Rule. He doesn't think we really need it. Pucky thinks that if we have f (x) should just have to use the power rule to find that f'(x)=2(x²+1)=2(x² + 1) = (x²+1)² then we For this discussion, write a post that briefly explains to Pucky why that derivative is incorrect and why we need to use the Chain Rule here. Don't just quote rules or theorems though, remember Pucky has already read the section and those rules and theorems make him growl and hiss. Try to come up with other explanations or reasons why Pucky's derivative is wrong beyond just "You need to use the Chain Rule". Help Pucky to realize that the Chain Rule is important and necessary and that even though he might prefer the Chain…

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MyLab Math with Pearson eText -- Standalone Access Card -- for Precalculus: A Unit Circle Approach (3rd Edition)

Chapter 8.2, Problem 1E Chapter 8.2, Problem 2E Chapter 8.2, Problem 3E Chapter 8.2, Problem 4E Chapter 8.2, Problem 5E Chapter 8.2, Problem 6E Chapter 8.2, Problem 7E Chapter 8.2, Problem 8E Chapter 8.2, Problem 9E Chapter 8.2, Problem 10E

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Chapter 8, Problem 7RE

Solution Summary: The author explains that the graph, vertex, focus and directrix of the given parabola are to be determined.

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