EBK COMPUTER NETWORKING
7th Edition
ISBN: 8220102955479
Author: Ross
Publisher: PEARSON
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Chapter 8, Problem R18RQ
Program Plan Intro
Nonce:
A number that the protocol can use only once is known as “nonce”.
Features of nonce:
- It is a type of data bit identification in IT security and other types of technical systems and can be characterized as a "throwaway" bit of data that is a placeholder for specific security strategies.
- In SSL, nonce are used to defend against the “connection replay attack” and also used to protect that entity against attacks which fall under the very large umbrella of "replay".
- Once-in-a-lifetime value of nonce is because the entity sending the nonce will never again use that value to check whether another entity is "live" till the entities lifetime.
HMAC:
A
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Students have asked these similar questions
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Chapter 8 Solutions
EBK COMPUTER NETWORKING
Ch. 8 - Prob. R1RQCh. 8 - Prob. R2RQCh. 8 - Prob. R3RQCh. 8 - Prob. R4RQCh. 8 - Prob. R5RQCh. 8 - Prob. R6RQCh. 8 - Prob. R7RQCh. 8 - Prob. R8RQCh. 8 - Prob. R9RQCh. 8 - Prob. R10RQ
Ch. 8 - Prob. R11RQCh. 8 - Prob. R12RQCh. 8 - Prob. R13RQCh. 8 - Prob. R14RQCh. 8 - Prob. R15RQCh. 8 - Prob. R16RQCh. 8 - Prob. R17RQCh. 8 - Prob. R18RQCh. 8 - Prob. R19RQCh. 8 - Prob. R20RQCh. 8 - Prob. R21RQCh. 8 - Prob. R22RQCh. 8 - Prob. R23RQCh. 8 - Prob. R24RQCh. 8 - Prob. R25RQCh. 8 - Prob. R26RQCh. 8 - Prob. R27RQCh. 8 - Prob. R28RQCh. 8 - Prob. R29RQCh. 8 - Prob. R30RQCh. 8 - Prob. R31RQCh. 8 - Prob. R32RQCh. 8 - Prob. R33RQCh. 8 - Prob. P1PCh. 8 - Prob. P2PCh. 8 - Prob. P3PCh. 8 - Prob. P4PCh. 8 - Prob. P5PCh. 8 - Prob. P6PCh. 8 - Prob. P8PCh. 8 - Prob. P12PCh. 8 - Prob. P13PCh. 8 - Prob. P14PCh. 8 - Prob. P18PCh. 8 - Prob. P20PCh. 8 - Prob. P21PCh. 8 - Prob. P22PCh. 8 - Prob. P23P
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Similar questions
- We may evaluate the two modes of cypher encryption, cypher block chaining and cypher feedback mode, by looking at how many encryption operations are needed to transport a large file.To what extent is the more efficient option preferred?arrow_forwardAssume that you have a suitable source of randomness which can produce at least 264264 random bits before it repeats. What is the easiest way to turn this into a stream cipher suitable for encrypting long streams of plaintext?arrow_forward2) The RC4 stream cipher, used in the WEP encryption scheme, relies on an initialization vector (IV). What is the purpose of the IV? Why it is important that the IV is not reused?arrow_forward
- Compare the cypher feedback mode with cypher block chaining for large file delivery.Which ratio is more efficient?arrow_forwardComparing CBC mode to OFB mode, only in OFB mode... A. each block is encrypted separately B. an initialization vector is utilized C. each ciphertext block depends on the previous ciphertext block D. a key stream is utilizedarrow_forwardIs it possible in SSL for the receiver to reorder SSL record blocks that arrive out of order? If so, explain how it can be done. If not, why not?arrow_forward
- Consider CBC-mode encryption with a block cipher having a 256-bit key and 128-bit block length to encrypt a 1024-bit message. What is the length of the resulting ciphertext? Does your answer change if the key size is 128 bits?arrow_forwardWhat is the biggest advantage of CBC mode of operation a. It does not need Initialization Vector (IV) b. A cipher text block depends on all blocks before it c. It does not propagate errors in the cipher text d. It can encrypt in parallel different parts of the messagesarrow_forwardIn terms of the number of encryption operations required to transfer a large file, compare cypher block chaining versus cypher feedback mode. How much more efficient is one than the other, and how much more efficient is one?arrow_forward
- If you need to deliver a large file across an encrypted channel, your best options are crypt feedback mode or cypher block chaining. How much more effective is one than the other, exactly?arrow_forwardWe use DES in cipher feedback mode (CFB) to encrypt a plaintext m = m1m2 ...m100 into a ciphertext c1c2 ...c100, where each mi is 8-bit long. The ciphertext is sent to Bob. If c15 and c25 are missing and c8 and c88 are received as c8' and c88' wrongly, what mi’s can B compute correctly from the received ciphertext?arrow_forwardCheck out the differences between cypher block chaining and cypher feedback mode for sending large files. Which ratio do you think works better?arrow_forward
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