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(a)
Interpretation:
The type of bond form between H and S to be predicted.
Concept introduction:
Power of an atom to attract electrons in a bond is electro negativity. Electro negativity is directly proportional to ionic character of the bond.
![Check Mark](/static/check-mark.png)
Answer to Problem 74SSC
Bond is non polar covalent.
Explanation of Solution
Electro negativity of H atom is 2 and electro negativity of S atom is 2.58. Thus electro negativity difference is as follows:
(b)
Interpretation:
The type of bond form between C and H to be predicted.
Concept introduction:
Power of an atom to attract electrons in a bond is electro negativity. Electro negativity is directly proportional to ionic character of the bond.
![Check Mark](/static/check-mark.png)
Answer to Problem 74SSC
Bond is non polar covalent.
Explanation of Solution
Electro negativity of H atom is 2 and electro negativity of C atom is 2.55. Thus electro negativity difference is as follows:
(c)
Interpretation:
The type of bond form between Na and S to be predicted.
Concept introduction:
Power of an atom to attract electrons in a bond is electro negativity. Electro negativity is directly proportional to ionic character of the bond.
![Check Mark](/static/check-mark.png)
Answer to Problem 74SSC
Bond is polar covalent.
Explanation of Solution
Electro negativity of Na atom is 0.93 and electro negativity of S atom is 2.58. Thus electro negativity difference is as follows:
Chapter 8 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
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