Explanation Given: The distance s in feet above the ground after t seconds is given by the equation s = − 16 t 2 + 640 t . Formula used: Quadratic formula: The root of the quadratic equation a x 2 + b x + c = 0 is given by; x = − b ± b 2 − 4 a c 2 a Calculation: Find the range of time t (in seconds) if the height s is greater than 6000 feet as: s > 6000 − 16 t 2 + 640 t > 6000 16 t 2 − 640 t + 6000 < 0 t 2 − 40 t + 375 < 0 Since, factorization of the given quadratic equation is not possible, use quadratic formula to find the boundary points as: t = − ( − 40 ) ± ( − 40 ) 2 − 4 ( 1 ) ( 375 ) 2 ( 1 ) = 40 ± 1600 − 1500 2 = 40 ± 100 2 = 20 ± 5 Now, use calculator to find the possible boundary of t as: t = 20 + 5 = 25 And, t = 20 − 5 = 15 Divide the number line with the help of this boundary points. This gives;

8th Edition

ISBN: 9780134178967

Author: John Tobey Jr., Jeffrey Slater, Jamie Blair, Jenny Crawford

Publisher: PEARSON

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Chapter 8.6, Problem 29E

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To calculate: The range of time of t(in seconds) for the projectile equation s=−16t2+640 with an initial velocity 640ft/sec if the height s is greater than 6000 feet.

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Chapter 8.6, Problem 28E

Chapter 8.6, Problem 30E

Chapter 8 Solutions

Intermediate Algebra (8th Edition)

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The range of time of t (in seconds) for the projectile equation s = − 16 t 2 + 640 with an initial velocity 640 ft/sec if the height s is greater than 6000 feet .

Solution Summary: The author calculates the range of time for the projectile equation s=-16t2+640 with an initial velocity of 640ft/sec if the height is greater than

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To calculate: The range of time of t(in seconds) for the projectile equation s=−16t2+640 with an initial velocity 640ft/sec if the height s is greater than 6000 feet.

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Chapter 8 Solutions