Chapter 9, Problem 13CR

a

To determine

To find:The angle formed by the hands of the clock at the given time i.e. $11:50$

Answer to Problem 13CR

The angle formed is ${55}^0$

Explanation of Solution

Given information:The time given is

  $11:50$

Calculation:We know that a circle contains ${360}^0$ . Hence, each unit measure will comprise of

  $\frac{{360}^0}{360}=1^0$

Now, difference between hour hand and minute hand at $11:50$ is

  $(30+25)=55\text{ units}$

Thus, we can say that the angle will be

  $55(1^0)={55}^0$

b

To determine

To find:The angle formed by the hands of the clock at the given time i.e. $12:01$

Answer to Problem 13CR

The angle formed is ${5.5}^0$

Explanation of Solution

Given information:The time given is

  $12:01$

We know that a circle contains ${360}^0$ . Hence, each unit measure will comprise of

  $\frac{{360}^0}{360}=1^0$

Now, difference between hour hand and minute hand at $12:01$ is

  $(6-0.5)=5.5\text{ units}$

Thus, we can say that the angle will be

  $5.5(1^0)={5.5}^0$