Chapter 9.1, Problem 5PSA

a

To determine

To calculate: The Value of xin the given expression i.e. $x^2=25$

Answer to Problem 5PSA

The Values of x are $5$ and $-5$ .

Explanation of Solution

Given information:$x^2=25$

Calculation: $x^2=25$

  $\begin{array}{l}\Rightarrow x=\sqrt{25}\\ \Rightarrow x=\pm 5\end{array}$

  $\Rightarrow x=5$ and $x=-5$

b

To determine

To calculate: The Value of xin the given expression i.e. $x^2=144$ .

Answer to Problem 5PSA

Values of x are $12$ and $-12$ .

Explanation of Solution

Given information:$x^2=144$

Calculation: $x^2=144$

  $\begin{array}{l}\Rightarrow x=\sqrt{144}\\ \Rightarrow x=\pm 12\end{array}$

  $\Rightarrow x=12$ and $x=-12$

c

To determine

To calculate: The Value of xin the given expression i.e. $x^2=169$

Answer to Problem 5PSA

Values of x are $5$ and $-5$ .

Explanation of Solution

Given information:$x^2=169$

Calculation: $x^2=169$

  $\begin{array}{l}\Rightarrow x=\sqrt{169}\\ \Rightarrow x=\pm 13\end{array}$

  $\Rightarrow x=13$ and $x=-13$

d

To determine

To calculate: The Value of x in the given expression i.e. $x^2=\frac{1}{4}$

Answer to Problem 5PSA

Values of x are $\frac{1}{2}$ and $\frac{-1}{2}$ .

Explanation of Solution

Given information:$x^2=\frac{1}{4}$

Calculation: $x^2=\frac{1}{4}$

  $\begin{array}{l}\Rightarrow x=\sqrt{\frac{1}{4}}\\ \Rightarrow x=\pm \frac{1}{2}\end{array}$

  $\Rightarrow x=\frac{1}{2}$ and $x=\frac{-1}{2}$

e

To determine

To calculate: The Value of xin the given expression i.e. $x^2=12$

Answer to Problem 5PSA

Values of x are $2\sqrt{3}$ and $-2\sqrt{3}$ .

Explanation of Solution

Given information:$x^2=12$

Calculation: $x^2=12$

  $\begin{array}{l}\Rightarrow x=\sqrt{12}\\ \Rightarrow x=\pm 2\sqrt{3}\end{array}$

  $\Rightarrow x=2\sqrt{3}$ and $x=-2\sqrt{3}$

f

To determine

To calculate: The Value of xin the given expression i.e. $x^2=18$

Answer to Problem 5PSA

Values of x are $3\sqrt{2}$ and $-3\sqrt{2}$ .

Explanation of Solution

Given information:$x^2=18$

Calculation: $x^2=18$

  $\begin{array}{l}\Rightarrow x=\sqrt{18}\\ \Rightarrow x=\pm 3\sqrt{2}\end{array}$

  $\Rightarrow x=3\sqrt{2}$ and $x=-3\sqrt{2}$