Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Question
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Chapter 9.6, Problem 5PSA

a.

To determine

To find:The missing side of the triangle where other two sides are 9 and 15

a.

Expert Solution
Check Mark

Answer to Problem 5PSA

The missing side is 12

Explanation of Solution

Given:

Two sides are 9 and 15

Concept used:

Here, we are using Pythagoras theorem.

Calculation:

Here, the formula is

  (Hypotenuse)2=(perpendicular)2+(base)2

Let the missing side be x

  (x)2=(15)2(9)2

  x=22581

  x=144

  x=12

  12

Conclusion: Hence, the missing side is 12

b.

To determine

To find:The missing side of the triangle where other two sides are 6 and 8

b.

Expert Solution
Check Mark

Answer to Problem 5PSA

The missing side is 27

Explanation of Solution

Given:

Two sides are 6 and 8

Concept used:

Here, we are using Pythagoras theorem.

Calculation:

Here, the formula is

  (Hypotenuse)2=(perpendicular)2+(base)2

  x2=(8)2(6)2

  x2=6436

  x=28

  x=27

Conclusion: Hence, the missing side is 27

c.

To determine

To find:The missing side of the triangle where other two sides are 24 and 26

c.

Expert Solution
Check Mark

Answer to Problem 5PSA

The missing side is 10

Explanation of Solution

Given:

Two sides are 24 and 26

Concept used:

Here, we are using Pythagoras theorem.

Calculation:

Here, the formula is

  (Hypotenuse)2=(perpendicular)2+(base)2

  x2=(26)2(24)2

  x=676576

  x=100

  x=10

Conclusion: Hence, the missing side is 10

d.

To determine

To find:The missing side of the triangle where other two sides are 1.3 and 1.2 .

d.

Expert Solution
Check Mark

Answer to Problem 5PSA

The missing side is 0.5

Explanation of Solution

Given:

Two sides are 1.3 and 1.2

Concept used:

Here, we are using Pythagoras theorem.

Calculation:

Here, the formula is

  (Hypotenuse)2=(perpendicular)2+(base)2

  x2=(1.3)2(1.2)2

  x2=1.691.44

  x=0.25

  x=0.5

Conclusion: Hence, the missing side is 0.5

e.

To determine

To find:The missing side of the triangle where other two sides are 16 and 30 .

e.

Expert Solution
Check Mark

Answer to Problem 5PSA

The missing side is 34

Explanation of Solution

Given:

Two sides are 16 and 30

Concept used:

Here, we are using Pythagoras theorem.

Calculation:

Here, the formula is

  (Hypotenuse)2=(perpendicular)2+(base)2

  x2=(30)2+(16)2

  x2=900+256

  x=1156

  x=34

Conclusion: Hence, the missing side is 34

f.

To determine

To find:The missing side of the triangle where other two sides are 20 and 15 .

f.

Expert Solution
Check Mark

Answer to Problem 5PSA

The missing side is 57

Explanation of Solution

Given:

Two sides are 20 and 15

Concept used:

Here, we are using Pythagoras theorem.

Calculation:

Here, the formula is

  (Hypotenuse)2=(perpendicular)2+(base)2

  x2=(20)2(15)2

  x2=400225

  x=175

  x=57

Conclusion: Hence, the missing side is 57

g.

To determine

To find:The missing side of the triangle where other two sides are 75 and 21 .

g.

Expert Solution
Check Mark

Answer to Problem 5PSA

The missing side is 72

Explanation of Solution

Given: Two sides are 75 and 21

Concept used: Here, we are using Pythagoras theorem.

Calculation: Here, the formula is

  (Hypotenuse)2=(perpendicular)2+(base)2

  x2=(75)2(21)2

  x2=5625441

  x=5184

  x=72

Conclusion: Hence, the missing side is 72

h.

To determine

To find:The missing side of the triangle where other two sides are 51 and 24

h.

Expert Solution
Check Mark

Answer to Problem 5PSA

The missing side is 45

Explanation of Solution

Given: Two sides are 51 and 24

Concept used: Here, we are using Pythagoras theorem.

Calculation: Here, the formula is

  (Hypotenuse)2=(perpendicular)2+(base)2

  x2=(51)2(24)2

  x2=2601576

  x=2025

  x=45

Conclusion: Hence, the missing side is 45

h.

To determine

To find:The missing side of the triangle where other two sides are 57 and 127 .

h.

Expert Solution
Check Mark

Answer to Problem 5PSA

The missing side is 137

Explanation of Solution

Given: Two sides are 57 and 127

Concept used: Here, we are using Pythagoras theorem.

Calculation: Here, the formula is

  (Hypotenuse)2=(perpendicular)2+(base)2

  x2=(127)2(57)2

  x2=1008175

  x=833

  x=137

Conclusion: Hence, the missing side is 137

Chapter 9 Solutions

Geometry For Enjoyment And Challenge

Ch. 9.1 - Prob. 11PSBCh. 9.1 - Prob. 12PSBCh. 9.1 - Prob. 13PSCCh. 9.2 - Prob. 1PSACh. 9.2 - Prob. 2PSACh. 9.2 - Prob. 3PSACh. 9.2 - Prob. 4PSACh. 9.2 - Prob. 5PSACh. 9.2 - Prob. 6PSACh. 9.2 - Prob. 7PSACh. 9.2 - Prob. 8PSACh. 9.2 - Prob. 9PSACh. 9.2 - Prob. 10PSACh. 9.2 - Prob. 11PSACh. 9.2 - Prob. 12PSBCh. 9.2 - Prob. 13PSBCh. 9.2 - Prob. 14PSBCh. 9.2 - Prob. 15PSBCh. 9.2 - Prob. 16PSBCh. 9.2 - Prob. 17PSBCh. 9.3 - Prob. 1PSACh. 9.3 - Prob. 2PSACh. 9.3 - Prob. 3PSACh. 9.3 - Prob. 4PSACh. 9.3 - Prob. 5PSACh. 9.3 - Prob. 6PSACh. 9.3 - Prob. 7PSACh. 9.3 - Prob. 8PSACh. 9.3 - Prob. 9PSACh. 9.3 - Prob. 10PSACh. 9.3 - Prob. 11PSACh. 9.3 - Prob. 12PSBCh. 9.3 - Prob. 13PSBCh. 9.3 - Prob. 14PSBCh. 9.3 - Prob. 15PSBCh. 9.3 - Prob. 16PSBCh. 9.3 - Prob. 17PSBCh. 9.3 - Prob. 18PSBCh. 9.3 - Prob. 19PSCCh. 9.3 - Prob. 20PSCCh. 9.3 - Prob. 21PSCCh. 9.3 - Prob. 22PSCCh. 9.3 - Prob. 23PSDCh. 9.3 - Prob. 24PSDCh. 9.4 - Prob. 1PSACh. 9.4 - Prob. 2PSACh. 9.4 - Prob. 3PSACh. 9.4 - Prob. 4PSACh. 9.4 - Prob. 5PSACh. 9.4 - Prob. 6PSACh. 9.4 - Prob. 7PSACh. 9.4 - Prob. 8PSACh. 9.4 - Prob. 9PSACh. 9.4 - Prob. 10PSACh. 9.4 - Prob. 11PSBCh. 9.4 - Prob. 12PSBCh. 9.4 - Prob. 13PSBCh. 9.4 - Prob. 14PSBCh. 9.4 - Prob. 15PSBCh. 9.4 - Prob. 16PSBCh. 9.4 - Prob. 17PSBCh. 9.4 - Prob. 18PSBCh. 9.4 - Prob. 19PSBCh. 9.4 - Prob. 20PSBCh. 9.4 - Prob. 21PSBCh. 9.4 - Prob. 22PSBCh. 9.4 - Prob. 23PSBCh. 9.4 - Prob. 24PSCCh. 9.4 - Prob. 25PSCCh. 9.4 - Prob. 26PSCCh. 9.4 - Prob. 27PSCCh. 9.4 - Prob. 28PSCCh. 9.4 - Prob. 29PSCCh. 9.4 - Prob. 30PSCCh. 9.4 - Prob. 31PSCCh. 9.4 - Prob. 32PSDCh. 9.4 - Prob. 33PSDCh. 9.4 - Prob. 34PSDCh. 9.4 - Prob. 35PSDCh. 9.4 - Prob. 36PSDCh. 9.5 - Prob. 1PSACh. 9.5 - Prob. 2PSACh. 9.5 - Prob. 3PSACh. 9.5 - Prob. 4PSACh. 9.5 - Prob. 5PSACh. 9.5 - Prob. 6PSACh. 9.5 - Prob. 7PSACh. 9.5 - Prob. 8PSACh. 9.5 - Prob. 9PSACh. 9.5 - Prob. 10PSACh. 9.5 - Prob. 11PSACh. 9.5 - Prob. 12PSACh. 9.5 - Prob. 13PSBCh. 9.5 - Prob. 14PSBCh. 9.5 - Prob. 15PSBCh. 9.5 - Prob. 16PSBCh. 9.5 - Prob. 17PSBCh. 9.5 - Prob. 18PSBCh. 9.5 - Prob. 19PSBCh. 9.5 - Prob. 20PSBCh. 9.5 - Prob. 21PSBCh. 9.5 - Prob. 22PSBCh. 9.5 - Prob. 23PSBCh. 9.5 - Prob. 24PSBCh. 9.5 - Prob. 25PSCCh. 9.5 - Prob. 26PSCCh. 9.5 - Prob. 27PSCCh. 9.6 - Prob. 1PSACh. 9.6 - Prob. 2PSACh. 9.6 - Prob. 3PSACh. 9.6 - Prob. 4PSACh. 9.6 - Prob. 5PSACh. 9.6 - Prob. 6PSACh. 9.6 - Prob. 7PSACh. 9.6 - Prob. 8PSACh. 9.6 - Prob. 9PSACh. 9.6 - Prob. 10PSACh. 9.6 - Prob. 11PSACh. 9.6 - Prob. 12PSACh. 9.6 - Prob. 13PSBCh. 9.6 - Prob. 14PSBCh. 9.6 - Prob. 15PSBCh. 9.6 - Prob. 16PSBCh. 9.6 - Prob. 17PSBCh. 9.6 - Prob. 18PSBCh. 9.6 - Prob. 19PSCCh. 9.6 - Prob. 20PSCCh. 9.6 - Prob. 21PSCCh. 9.6 - Prob. 22PSCCh. 9.6 - Prob. 23PSCCh. 9.6 - Prob. 24PSDCh. 9.6 - Prob. 25PSDCh. 9.7 - Prob. 1PSACh. 9.7 - Prob. 2PSACh. 9.7 - Prob. 3PSACh. 9.7 - Prob. 4PSACh. 9.7 - Prob. 5PSACh. 9.7 - Prob. 6PSACh. 9.7 - Prob. 7PSACh. 9.7 - Prob. 8PSACh. 9.7 - Prob. 9PSACh. 9.7 - Prob. 10PSACh. 9.7 - Prob. 11PSACh. 9.7 - Prob. 12PSBCh. 9.7 - Prob. 13PSBCh. 9.7 - Prob. 14PSBCh. 9.7 - Prob. 15PSBCh. 9.7 - Prob. 16PSBCh. 9.7 - Prob. 17PSBCh. 9.7 - Prob. 18PSBCh. 9.7 - Prob. 19PSBCh. 9.7 - Prob. 20PSBCh. 9.7 - Prob. 21PSBCh. 9.7 - Prob. 22PSBCh. 9.7 - Prob. 23PSBCh. 9.7 - Prob. 24PSCCh. 9.7 - Prob. 25PSCCh. 9.7 - Prob. 26PSCCh. 9.7 - Prob. 27PSDCh. 9.7 - Prob. 28PSDCh. 9.8 - Prob. 1PSACh. 9.8 - Prob. 2PSACh. 9.8 - Prob. 3PSACh. 9.8 - Prob. 4PSACh. 9.8 - Prob. 5PSACh. 9.8 - Prob. 6PSACh. 9.8 - Prob. 7PSACh. 9.8 - Prob. 8PSACh. 9.8 - Prob. 9PSACh. 9.8 - Prob. 10PSACh. 9.8 - Prob. 11PSBCh. 9.8 - Prob. 12PSBCh. 9.8 - Prob. 13PSBCh. 9.8 - Prob. 14PSBCh. 9.8 - Prob. 15PSBCh. 9.8 - Prob. 16PSBCh. 9.8 - Prob. 17PSBCh. 9.8 - Prob. 18PSCCh. 9.8 - Prob. 19PSCCh. 9.8 - Prob. 20PSCCh. 9.8 - Prob. 21PSCCh. 9.8 - Prob. 22PSCCh. 9.8 - Prob. 23PSDCh. 9.9 - Prob. 1PSACh. 9.9 - Prob. 2PSACh. 9.9 - Prob. 3PSACh. 9.9 - Prob. 4PSACh. 9.9 - Prob. 5PSACh. 9.9 - Prob. 6PSACh. 9.9 - Prob. 7PSACh. 9.9 - Prob. 8PSACh. 9.9 - Prob. 9PSBCh. 9.9 - Prob. 10PSBCh. 9.9 - Prob. 11PSBCh. 9.9 - Prob. 12PSBCh. 9.9 - Prob. 13PSBCh. 9.9 - Prob. 14PSBCh. 9.9 - Prob. 15PSBCh. 9.9 - Prob. 16PSBCh. 9.9 - Prob. 17PSBCh. 9.9 - Prob. 18PSBCh. 9.9 - Prob. 19PSCCh. 9.9 - Prob. 20PSCCh. 9.9 - Prob. 21PSCCh. 9.9 - Prob. 22PSCCh. 9.10 - Prob. 1PSACh. 9.10 - Prob. 2PSACh. 9.10 - Prob. 3PSACh. 9.10 - Prob. 4PSACh. 9.10 - Prob. 5PSACh. 9.10 - Prob. 6PSBCh. 9.10 - Prob. 7PSBCh. 9.10 - Prob. 8PSBCh. 9.10 - Prob. 9PSBCh. 9.10 - Prob. 10PSBCh. 9.10 - Prob. 11PSBCh. 9.10 - Prob. 12PSBCh. 9.10 - Prob. 13PSBCh. 9.10 - Prob. 14PSBCh. 9.10 - Prob. 15PSBCh. 9.10 - Prob. 16PSCCh. 9.10 - Prob. 17PSCCh. 9.10 - Prob. 18PSCCh. 9.10 - Prob. 19PSCCh. 9.10 - Prob. 20PSDCh. 9.10 - Prob. 21PSDCh. 9 - Prob. 1RPCh. 9 - Prob. 2RPCh. 9 - Prob. 3RPCh. 9 - Prob. 4RPCh. 9 - Prob. 5RPCh. 9 - Prob. 6RPCh. 9 - Prob. 7RPCh. 9 - Prob. 8RPCh. 9 - Prob. 9RPCh. 9 - Prob. 10RPCh. 9 - Prob. 11RPCh. 9 - Prob. 12RPCh. 9 - Prob. 13RPCh. 9 - Prob. 14RPCh. 9 - Prob. 15RPCh. 9 - Prob. 16RPCh. 9 - Prob. 17RPCh. 9 - Prob. 18RPCh. 9 - Prob. 19RPCh. 9 - Prob. 20RPCh. 9 - Prob. 21RPCh. 9 - Prob. 22RPCh. 9 - Prob. 23RPCh. 9 - Prob. 24RPCh. 9 - Prob. 25RPCh. 9 - Prob. 26RPCh. 9 - Prob. 27RPCh. 9 - Prob. 28RPCh. 9 - Prob. 29RPCh. 9 - Prob. 30RPCh. 9 - Prob. 31RPCh. 9 - Prob. 32RPCh. 9 - Prob. 33RPCh. 9 - Prob. 34RPCh. 9 - Prob. 35RPCh. 9 - Prob. 36RPCh. 9 - Prob. 37RPCh. 9 - Prob. 1CRCh. 9 - Prob. 2CRCh. 9 - Prob. 3CRCh. 9 - Prob. 4CRCh. 9 - Prob. 5CRCh. 9 - Prob. 6CRCh. 9 - Prob. 7CRCh. 9 - Prob. 8CRCh. 9 - Prob. 9CRCh. 9 - Prob. 10CRCh. 9 - Prob. 11CRCh. 9 - Prob. 12CRCh. 9 - Prob. 13CRCh. 9 - Prob. 14CRCh. 9 - Prob. 15CRCh. 9 - Prob. 16CRCh. 9 - Prob. 17CRCh. 9 - Prob. 18CRCh. 9 - Prob. 19CRCh. 9 - Prob. 20CRCh. 9 - Prob. 21CRCh. 9 - Prob. 22CRCh. 9 - Prob. 23CRCh. 9 - Prob. 24CRCh. 9 - Prob. 25CRCh. 9 - Prob. 26CRCh. 9 - Prob. 27CRCh. 9 - Prob. 28CRCh. 9 - Prob. 29CRCh. 9 - Prob. 30CRCh. 9 - Prob. 31CR
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