Campbell Essential Biology with Physiology (5th Edition)
5th Edition
ISBN: 9780321967671
Author: Eric J. Simon, Jean L. Dickey, Jane B. Reece, Kelly A. Hogan
Publisher: PEARSON
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Chapter 9, Problem 15SQ
Summary Introduction
To explain: The reason for the occurrence of hemophilia, a sex-linked recessive disorder in boy and to draw the pedigree that shows the genotypes of the three individuals. The fraction of the couple’s children that are likely to suffer from hemophilia and the fraction of the carriers formed due to this cross.
Introduction:
Hemophilia is a genetic disease of the blood, which is caused due to a genetic mutation of the factor VIII involved in blood clotting. In this disease the clotting of the blood decreases. It is a sex-linked recessive disorder.
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A WOMAN IS HETEROZYGOUS FOR TWO
HARMFUL RECESSIVE ALLELES IN
DIFFERENT CHROMOSOMES, ONE FOR
PHENYLKETONURIA (PKU) AND THE
OTHER FOR CYSTIC FIBROSIS (CF). SHE
MARRIES AN UNAFFECTED MAN WHO IS
A CARRIER FOR NEITHER DISEASE.
IF SHE HAS A DAUGHTER, WHAT IS THE
PROBABILITY THAT THE CHILD WILL
CARRY NEITHER OF THE RECESSIVE
ALLELES?
EXACTLY ONE?
BOTH?
Hemophilia is a sex-linked recessive trait. A male hemophiliac and phenotypically normal female have a son with hemophilia.
They would like to have one more child. What is the probability of having a child without hemophilia? Explain using a Punnett square.
Is it possible for a girl to be born with hemophilia? Explain.
A young couple went to see a genetic counselor because each had a sibling affected with cystic fibrosis. (Cystic fibrosis is a recessive disease and neither member of the couple nor any of their four parents is affected).
What is the probability that the female of this couple is a carrier and what are the chances that their child will be affected with cystic fibrosis?
Chapter 9 Solutions
Campbell Essential Biology with Physiology (5th Edition)
Ch. 9 - The genetic makeup of an organism is called its...Ch. 9 - Which of Mendels laws is represented by each...Ch. 9 - Prob. 3SQCh. 9 - Prob. 4SQCh. 9 - Prob. 5SQCh. 9 - Prob. 6SQCh. 9 - Prob. 7SQCh. 9 - Prob. 8SQCh. 9 - Prob. 9SQCh. 9 - Prob. 10SQ
Ch. 9 - Prob. 11SQCh. 9 - Prob. 12SQCh. 9 - Incomplete dominance is seen in the inheritance of...Ch. 9 - Why was Henry VIII wrong to blame his wives for...Ch. 9 - Prob. 15SQCh. 9 - Prob. 16SQCh. 9 - Prob. 17SQCh. 9 - Prob. 18PSCh. 9 - Prob. 19PSCh. 9 - Prob. 20BSCh. 9 - Gregor Mendel never saw a gene, yet he concluded...Ch. 9 - Prob. 22BS
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- A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?arrow_forwardGiven the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?arrow_forwardCould an individual with blood type O (genotype ii) be a legitimate child of parents in which one parent had blood type A and the other parent had blood type B?arrow_forward
- In humans, the allele for normal blood clotting (H) is dominant to the allele for hemophilia. This is a sex-linked trait found on the X chromosome. A woman with normal blood clotting has four children: a normal son, a hemophiliac son, and two normal daughters. The father has normal blood clotting. What is the probable genotype for each member of the family?arrow_forwardFor a recessive condition, two normal heterozygous individuals have children. What is the likelihood of their children being affected by this condition? What is the likelihood of their children being carriers without the condition? What is the likelihood of their asymptomatic children being carriers? Suppose that an individual with the condition has children with a heterozygous individual, what is the likelihood of their children being carriers?arrow_forwardIn humans, the allele for normal blood clotting, H, is dominant to the allele for hemophilia, h. This is a sex-linked trait found on the X chromosome. A woman with normal blood clotting has four children: a normal son, a hemophiliac son, and two normal daughters. The father has normal blood clotting. What is the genotype for each member of the family?arrow_forward
- Hemophilia is caused by an X-linked recessive mutation in humans. If a woman whose paternal uncle (father's brother) was a hemophiliac marries a man whose brother is also a hemophiliac, what is the probability of their first child having hemophilia (Note: assume that there are no other cases of hemophilia in the pedigree and no hidden carriers)? Select one: a. 1/2 b. 1/8 c. 0 d. 1/4 e. 1 Oarrow_forward*Cystic fibrosis is a rare autosomal recessive condition. phenotypically normal man whose father had cystic fibrosis marries a phenotypically normal woman from outside the family.² a) Draw the pedigree as far as described. b) If the frequency of heterozygotes in the general population is 1/50, what is the probability that the couple's first child will have cystic fibrosis? c) If the first child does have cystic fibrosis, what is the probability that the second child will be normal?arrow_forwardDuchenne Muscular Dystrophy (DMD) is an X-linked recessive trait. Fill in a Punnett square for a man with DMD and a woman who carries DMD. Then use your Punnett square to answer the following questions: A) What is the probability that one of their daughters will have DMD? ___% B) What is the probability that one of their daughters is a carrier of DMD? ______ % C) What is the probability that one of their sons will have DMD? ______ % D) What is the probability that one of their sons is a carrier of DMD? ______ % E) On which chromosome is the gene for DMD located? _____arrow_forward
- One form of the bleeding disorder known as von Willebrand disease is an autosomal recessive disease. A man who is a carrier marries a woman who is also a carrier of the disease. (a) What percentage of their children are likely to have a disease phenotype? (b) What percentage of their children are likely to have a normal phenotype? (c) What percentage of their children are likely to be carriers of the disease?arrow_forwardA man with blood type O (genotype ii) has a father with blood type A and a mother with blood type B. Is this man a legitimate child of these parents? What is a possible phenotype of an individual that results from a woman with type AB blood and a man with type B blood? Explain with diagrams.arrow_forwardBoth red/green color blindness (R=normal, r=colorblind) and Duchenne-type muscular dystrophy (D=normal, d=muscular dystrophy) are X-linked recessive traits that map close to each other. A woman has a father who is red/green color blind. Her mother's family has a history of Duchenne's muscular dystrophy. This woman is apparently healthy with neither color blindness nor muscular dystrophy. She marries a healthy man and they have four sons and two daughters. Half the sons are healthy but color blind, the other half have normal color vision, but have Duchenne's muscular dystrophy. The daughters are both normal. What is the genotype of the woman? ** The notation is written as X/X (so the / separates the two X chromosomes in a female) Group of answer choices RD/rd rd/rd Rd/rD RD/RDarrow_forward
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