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Campbell Essential Biology with Physiology (5th Edition)
5th Edition
ISBN: 9780321967671
Author: Eric J. Simon, Jean L. Dickey, Jane B. Reece, Kelly A. Hogan
Publisher: PEARSON
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Chapter 9, Problem 11SQ
Summary Introduction
To explain: The determination of the genotype of one brown F2 mice in problem 10, the analysis whether a brown mouse is homozygous or heterozygous.
Introduction: There are two alleles for a gene which express the brown color in mice. The gene for the brown color in mice is depicted by B, which is a dominant gene and the allele for the recessive gene is depicted by b. The genotype of the dominant homozygous brown mouse will be BB and the genotype of the dominant heterozygous brown mice will be depicted by Bb in the
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Students have asked these similar questions
In Drosophila, a fully heterozygous female with the X-linked recessive genes a, b, and c (not necessarily in that order on
the chromosome) was mated to a male that was genetically a, b, c (not necessarily in that order on the chromosome).
The offspring occurred in the following phenotypic ratios:
Phenotypes:
Numbers:
What is the cis/trans arrangement in the heterozygous parent?
Wild
426
а, с, b
428
Which gene is in the middle?
a
23
c, b
22
If you added 23, 22, 3, and 2, it would give you the map distance between
genes
C
49
b, a
46
What calculation would you make to determine if interference was
occurring? (you don't have to complete the calculation)
b.
C, a
Total
1000
3.
In Drosophila,, the curled mutation (cu, chromosome 3, position 50.0) results in wings that curl up,
while ebony (e, chromosome 3, position 70.7) results in a dark body. True breeding, wild type females
are mated with true breeding males with curled wings and ebony bodies.
Considering Drosophila notation, which of the following correctly diagrams the P1 cross?
X
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+ +
O+
X
+
X +
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+
X
+
+ +
3+
X
X
X
X
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+
Y
Y
cu
cu
cu
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cu
cu J
e
e
e
e
e
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cu
cu
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As stated in Solved Problem 2, recessive mutation in certain mice called waltzers causes them to execute bizarre steps. W. H. Gates crossed waltzers with pure-breeding normal mice and found, among several hundred normal progeny, a single waltzing female mouse. This mouse was mated with a waltzing male, and her offspring were waltzers. When mated with a homozygous normal male, all her progeny were normal. Some of these normal males and females were intercrossed, and, unexpectedly, none of their progeny were waltzers. T. S. Painter examined the chromosomes of some of Gates’s waltzing mice that showed a breeding behavior similar to that of the original, unusual waltzing female. He found that these mice had the normal number of 40 chromosomes. In the unusual waltzers, however, one member of a chromosome pair was abnormally short. Interpret these observations as completely as possible, both genetically and cytologically.
Chapter 9 Solutions
Campbell Essential Biology with Physiology (5th Edition)
Ch. 9 - The genetic makeup of an organism is called its...Ch. 9 - Which of Mendels laws is represented by each...Ch. 9 - Prob. 3SQCh. 9 - Prob. 4SQCh. 9 - Prob. 5SQCh. 9 - Prob. 6SQCh. 9 - Prob. 7SQCh. 9 - Prob. 8SQCh. 9 - Prob. 9SQCh. 9 - Prob. 10SQ
Ch. 9 - Prob. 11SQCh. 9 - Prob. 12SQCh. 9 - Incomplete dominance is seen in the inheritance of...Ch. 9 - Why was Henry VIII wrong to blame his wives for...Ch. 9 - Prob. 15SQCh. 9 - Prob. 16SQCh. 9 - Prob. 17SQCh. 9 - Prob. 18PSCh. 9 - Prob. 19PSCh. 9 - Prob. 20BSCh. 9 - Gregor Mendel never saw a gene, yet he concluded...Ch. 9 - Prob. 22BS
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- In Drosophila,, the curled mutation (cu, chromosome 3, position 50.0) results in wings that curl up, while ebony (e, chromosome 3, position 70.7) results in a dark body. True breeding, wild type females are mated with true breeding males with curled wings and ebony bodies. Considering Drosophila notation, which of the following correctly diagrams the F1 cross? X X 3+ cu e + X X e + + + + + cu e + O + ■ 3+ X X X X Y Y + + ■ cu cu cu ' + ■ cu ■ ' + e + e e e e e + cu +arrow_forwardYou cross a true-breeding yellow-bodied, smooth-winged female fly with a true-breeding red-bodied, crinkle-winged male. The red body phenotype is dominant to the yellow body phenotype and smooth wings are dominant to crinkled wings. Use B or b for body color alleles, and W or w for wing surface alleles.(4 points) a) What are the genotypes of the P generation flies? b) What will be the genotype(s) and phenotype(s) of the F1 offspring? c) You discover that the genes for body color and wing surface are linked. You perform a dihybrid test cross between the F1 flies from part (b) with a true-breeding yellow-bodied, crinkle-winged fly. Use the following results of this cross to determine the recombination frequency (%) between the body color and wing surface genes. (Remember that the recombinants are the ones that do not resemble the parental types from the P generation.) Body Color Wing Surface # of Individuals red smooth 102 yellow smooth 404 red crinkled 396 yellow crinkled…arrow_forwardIn a cross between a white-eyed female (ww) and a red-eyed male (w+Y), nearly all the progeny were either red-eyed females (w+w) or white-eyed males (wY). However, about 1 in every 2000 F1 flies had an "exceptional phenotype" and was either a white-eyed female or red-eyed male. How did Bridges explain this unexpected result? A) Crossing over B) Incomplete cytokinesis C) Incorrect synapsis D) Nondisjunction E) Pseudoautosomal regionarrow_forward
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