The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Chapter 9, Problem 3CRE

(a)

To determine

To explain the null hypothesis and the alternative hypothesis and write their symbols

(a)

Expert Solution
Check Mark

Explanation of Solution

Given information:

A company manufactures classroom chairs for the high school students. The mean breaking strength of the chairs is 300 pounds. One chair with strength 220 pounds collapsed.

Let μ be the strength of the chair.

The null hypothesis is the hypothesis that is considered to be true.

It is denoted as H0 .

Define the null hypothesis H0:μ=300

One of the chairs with weight less than 300 pounds collapsed.

Define the alternate hypothesis H1:μ<300

(b)

To determine

To explain: What is Type I and Type II error and what are the consequences of each.

(b)

Expert Solution
Check Mark

Explanation of Solution

Type I error is defined as the error when H0 is rejected when H0 is true.

The null hypothesis H0:μ=300 .

The mean breaking strength of the chair is 300 pounds.

Type II error is defined as the error when H0 is accepted when H0 is not true.

The alternate hypothesis is H1:μ<300 .

This indicates that the mean breaking strength of the chair is less than 300 pounds.

In the given problem, Type II error indicate that the chances of collapsing a chair are less.

Type II error indicate that the chance that chair will collapse are more.

(c)

To determine

To find out: Out of the significance levels given below which is recommended.

  1. 0.01
  2. 0.05
  3. 0.10

(c)

Expert Solution
Check Mark

Explanation of Solution

Given Information : The three level of significance 0.01 , 0.05 and 0.10 .

Type I error is defined as the error when H0 is rejected when H0 is true.

The null hypothesis H0:μ=300

Type II error is defined as the error when H0 is accepted when H0 is not true.

The alternate hypothesis is H1:μ<300 .

In response to the given problem, Type I error indicate that chair will collapse less.

Type II error indicate that the chair will collapse more often.

The main objective is to keep the Type II error as less as possible as its more serious.

This will happen when Type I error α is more.

The value α also signifies the level of significance.

Out of the given values 0.01 , 0.05 and 0.10 .

The greatest value is 0.10 .

Therefore, choose significance level 0.10

(d)

To determine

To explain: the meaning of Power of Test.

(d)

Expert Solution
Check Mark

Explanation of Solution

Given Information: The power of the test to detect μ=294 is given as 0.71

The null hypothesis H0:μ=300 .

The alternate hypothesis is H1:μ<300 .

The power of the test to detect μ=294 is given as 0.71

The power of the test is defined as the probability of rejecting the null hypothesis if the alternative hypothesis is true.

The power of the test is 0.71 , this implies that when μ=294 probability of rejecting the null hypothesis is 0.71 .

(e)

To determine

To find out: the ways the increase the power of the test

(e)

Expert Solution
Check Mark

Explanation of Solution

The following are the ways the increase the power of the test.

  1. Increase the sample size: Increasing the sample size will give better estimation.
  2. Increase the level of significance: This will increase the probability of committing a Type I error which will decrease the Type II error. Therefore, by definition it will increase the power of test.

Chapter 9 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 9.1 - Prob. 6ECh. 9.1 - Prob. 7ECh. 9.1 - Prob. 8ECh. 9.1 - Prob. 9ECh. 9.1 - Prob. 10ECh. 9.1 - Prob. 11ECh. 9.1 - Prob. 12ECh. 9.1 - Prob. 13ECh. 9.1 - Prob. 14ECh. 9.1 - Prob. 15ECh. 9.1 - Prob. 16ECh. 9.1 - Prob. 17ECh. 9.1 - Prob. 18ECh. 9.1 - Prob. 19ECh. 9.1 - Prob. 20ECh. 9.1 - Prob. 21ECh. 9.1 - Prob. 22ECh. 9.1 - Prob. 23ECh. 9.1 - Prob. 24ECh. 9.1 - Prob. 25ECh. 9.1 - Prob. 26ECh. 9.1 - Prob. 27ECh. 9.1 - Prob. 28ECh. 9.1 - Prob. 29ECh. 9.1 - Prob. 30ECh. 9.1 - Prob. 31ECh. 9.1 - Prob. 32ECh. 9.2 - Prob. 1.1CYUCh. 9.2 - Prob. 2.1CYUCh. 9.2 - Prob. 3.1CYUCh. 9.2 - Prob. 33ECh. 9.2 - Prob. 34ECh. 9.2 - Prob. 35ECh. 9.2 - Prob. 36ECh. 9.2 - Prob. 37ECh. 9.2 - Prob. 38ECh. 9.2 - Prob. 39ECh. 9.2 - Prob. 40ECh. 9.2 - Prob. 41ECh. 9.2 - Prob. 42ECh. 9.2 - Prob. 43ECh. 9.2 - Prob. 44ECh. 9.2 - Prob. 45ECh. 9.2 - Prob. 46ECh. 9.2 - Prob. 47ECh. 9.2 - Prob. 48ECh. 9.2 - Prob. 49ECh. 9.2 - Prob. 50ECh. 9.2 - Prob. 51ECh. 9.2 - Prob. 52ECh. 9.2 - Prob. 53ECh. 9.2 - Prob. 54ECh. 9.2 - Prob. 55ECh. 9.2 - Prob. 56ECh. 9.2 - Prob. 57ECh. 9.2 - Prob. 58ECh. 9.2 - Prob. 59ECh. 9.2 - Prob. 60ECh. 9.2 - Prob. 61ECh. 9.2 - Prob. 62ECh. 9.3 - Prob. 1.1CYUCh. 9.3 - Prob. 1.2CYUCh. 9.3 - Prob. 1.3CYUCh. 9.3 - Prob. 2.1CYUCh. 9.3 - Prob. 3.1CYUCh. 9.3 - Prob. 3.2CYUCh. 9.3 - Prob. 63ECh. 9.3 - Prob. 64ECh. 9.3 - Prob. 65ECh. 9.3 - Prob. 66ECh. 9.3 - Prob. 67ECh. 9.3 - Prob. 68ECh. 9.3 - Prob. 69ECh. 9.3 - Prob. 70ECh. 9.3 - Prob. 71ECh. 9.3 - Prob. 72ECh. 9.3 - Prob. 73ECh. 9.3 - Prob. 74ECh. 9.3 - Prob. 75ECh. 9.3 - Prob. 76ECh. 9.3 - Prob. 77ECh. 9.3 - Prob. 78ECh. 9.3 - Prob. 79ECh. 9.3 - Prob. 80ECh. 9.3 - Prob. 81ECh. 9.3 - Prob. 82ECh. 9.3 - Prob. 83ECh. 9.3 - Prob. 84ECh. 9.3 - Prob. 85ECh. 9.3 - Prob. 86ECh. 9.3 - Prob. 87ECh. 9.3 - Prob. 88ECh. 9.3 - Prob. 89ECh. 9.3 - Prob. 90ECh. 9.3 - Prob. 91ECh. 9.3 - Prob. 92ECh. 9.3 - Prob. 93ECh. 9.3 - Prob. 94ECh. 9.3 - Prob. 95ECh. 9.3 - Prob. 96ECh. 9.3 - Prob. 97ECh. 9.3 - Prob. 98ECh. 9.3 - Prob. 99ECh. 9.3 - Prob. 100ECh. 9.3 - Prob. 101ECh. 9.3 - Prob. 102ECh. 9.3 - Prob. 103ECh. 9.3 - Prob. 104ECh. 9.3 - Prob. 105ECh. 9.3 - Prob. 106ECh. 9.3 - Prob. 107ECh. 9.3 - Prob. 108ECh. 9 - Prob. 1CRECh. 9 - Prob. 2CRECh. 9 - Prob. 3CRECh. 9 - Prob. 4CRECh. 9 - Prob. 5CRECh. 9 - Prob. 6CRECh. 9 - Prob. 7CRECh. 9 - Prob. 8CRECh. 9 - Prob. 9CRECh. 9 - Prob. 1PTCh. 9 - Prob. 2PTCh. 9 - Prob. 3PTCh. 9 - Prob. 4PTCh. 9 - Prob. 5PTCh. 9 - Prob. 6PTCh. 9 - Prob. 7PTCh. 9 - Prob. 8PTCh. 9 - Prob. 9PTCh. 9 - Prob. 10PTCh. 9 - Prob. 11PTCh. 9 - Prob. 12PTCh. 9 - Prob. 13PT

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