EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
9th Edition
ISBN: 9781337517218
Author: SOBHAN
Publisher: VST
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Chapter 9, Problem 9.3P
To determine
Find the total stress
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9.1 Through 9.3 A soil profile consisting of three layers is shown in Figure 9.25.
Calculate the values of o, u, and o' at points A, B, C, and D for the following
cases. In each case, plot the variations of o,u,and o' with depth. Characteristics
of layers 1,2, and 3 for each case are given below:
Layer 1
Groundwater table
Layer 2
Layer 3
O Dry sand
Clay
Sand
Rock
Figure 9.25
Problem
Layer no.
Thickness
Soil parameters
9.1
1
H - 7 ft
- 110 Ib'fn
2
H = 12 ft
Y- 121 Ib'ft
H, = 6 ft
Y = 118 Ib/f3
H =5m
P= 0G, = 2 64
H, = 8 m
e = 0.55: G, = 2.7
H, = 3 m
w = 38%; e = 1.2
9.3
1
H - 3 m
Y- 16 kNim
2
H. - 6 m
Yu - 18 kN'm
3
H, - 2.5 m
Yut - 17 kN/m
9.1 Through 9.3 A soil profile consisting of three layers is shown in Figure 9.25.
Calculate the values of ơ, u, and o' at points A, B, C, and D for the following cases.
In each case, plot the variations of ơ, u, and o' with depth. Characteristics
of layers 1, 2, and 3 for each case are given below:
H
Layer I
Groundwater table
H2
Layer 2
Layer 3
| Dry sand
Sand a Clay
Rock
Figure 9.25
Layer no.
Thickness
Soll parameters
H; = 2.1 m
Hz = 3.66 m
- 1.83 m
Ye = 17.23 kN/m
18.96 kN/m
18.5 kN/m
9.1
Yut
3
H3
Yaut
A soil profile is shown in Figure 6.24. Calculate the values of o, u, and o at
points A, B, C, and D. Plot the variation of ơ, u, and ơ with depth. We are
given the values in the table.
Layer No.
Thickness (m)
Unit weight (kN/m³)
H = 2
H2 = 3
= 7
I
Ydry = 15
Ysat = 17.8
II
%3D
III
%3D
Ysat =
18.6
Chapter 9 Solutions
EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
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- 2) A soil profile consisting of three layers is shown in the Figure. A) Calculate the values of σ, u and σ' at points A,B,C and D if Layer 1: H1=5m, e=0.7, Gs=2.69 Layer 2: H2=8m, e=0.55, Gs=2.7 Layer 3: H3=3m, w=38%, e=1.2 B) What is the change in effective stress at point C if: If the water table drops by 2m? If the water table rises to the surface up to point A? Water level rises 3 m above point A due to flooding?arrow_forward7. A soil profile consisting of three layers is shown in the figure. Calculate the values of the total stress, effective stress ad pore water pressure at points A, B, C, and D for the following cases. In each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are given below:arrow_forward9.1 Through 9.3 A soil profile consisting of three layers is shown in Figure 9.25.Calculate the values of σ, u, and σ′ at points A, B, C, and D for the following cases. Ineach case, plot the variations of σ, u, and σ′ with depth. Characteristics of layers 1, 2,and 3 for each case are given below:arrow_forward
- Q-1: A soil profile consisting of three layers is shown in the following figure. a) Calculate the values of o, u and o' at points A, B, C, and D Layer no. 1 2 3 ↑ H₁ H₂ H₂ Thickness H, = 2.1 m H₂ = 3.66 m H₂ = 1.83 m Dry sand Soll parameters Y₁ = 17.23 kN/m³ Ysat 18.96 kN/m³ Ysat 18.5 kN/m³ Sand Clay Rock Layer 1 Groundwater table Layer 2 Layer 3 ⒸDengage Learning 2014 b) Calculate the effective stress at c when water table drops by 2m (consider x 16.5 for layer 2). c) Calculate the effective stress at c when water table rises by 2m above layer 1 due to flooding (consider Ysa 18.5 for layer 1).arrow_forwardA 2 m Ya = 17 kN/m3 Layer 1 Groundwater table Practice Problem 2: A soil profile consisting of three layers is shown in Figure 1.6. Calculate the values of o, u, and o' at points A, B, C, and D. In each case, plot 1.5 m the variations of o, u, and ' with depth. 4 m Ysat = 18 kN/m3 Layer 2 Ysat= 20 kN/m2 Layer 3 O Dry sand Sand Clay Rock Figure 1.6arrow_forwardA soil profile consisting of three layers is shown in the figure. Calculate the values of the total stress, effective stress ad pore waterpressureat points A, B, C, and D for the following cases. In each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are given belowarrow_forward
- Q2. A soil profile consisting of three layers is shown in Figure 1 below. Unit weight of water (yw) = 9.81 kN/m³ Layer no. 1 2 3 ↑ H₁ H₂ Dry sand Sand Clay Rock Figure 1: Soil Profile Thickness H₁ = 1.5 m H₂ = 2.53 m H3 = 2.64 m Layer 1 Groundwater table Layer 2 Layer 3 Soil parameters Yd = 16.5 kN/m³, Ysat = 17.42 kN/m³ Ya = 16.5 kN/m³, Ysat = 18.55 kN/m³ Yd = 17.50 kN/m³, Ysat = 19.23 kN/m³ a) Calculate the values of o, u and o' at points A, B, C and D. b) Calculate the effective stress at C when water table drops by 2 m. c) Calculate the effective stress at C when water table rises by 1 m above layer 1 due to flooding.arrow_forward7. A soil profile consisting of three layers is shown in the figure. Calculate the values of the total stress, effective stress ad pore water pressure at points A, B, C, and D for the following cases. In each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are given below: Page 3 of 4 Layer 1 Groundwater table Layer 2 Layer 3 Dry sand Sand Clay Rock Layer no. Thickness Soil parameters 1 Y = 110 lb/ft³ 121 Ib/ft H = 7 ft 2 %3D Yat = 3 H, = 6 ft Yeat = 118 lb/ft³ e = 0.7; G, = 2.69 e = 0.55; G, = 2.7 w = 38%;e = 1.2 %3D 1 H = 5 m II, = 8 m %3D 3 H, = 3 m 1 H, = 3 m Y = 16 kN/m 18 kN/m 2 H¸ = 6 m Yat 3 H, = 2.5 m 17 kN/m %3D Ysat %3D 2.arrow_forwardA soil profile is shown in Figure P3.2 along with the standard penetration numbers in the clay layer. Use Eqs. (3.8) and (3.9) to determine the variation of cu and OCR with depth. What is the average value of cu and OCR?arrow_forward
- A soil profile is shown in Figure Q. Given: Layer I – H, = 3 m, Ya = 15 kN/m³; Layer II – H, = 4 m, Ysat = 16 kN/m³; Layer III – H3 = 5 m, Ysat = 18 kN/m³. Plot the variation of a, u and o' with depth. %3D A Layer I Groundwater table H2 Layer II H3 Layer III Figure Q : Dry sand Sand Clay Rockarrow_forwardQ.11 Consider the three layered soil strata shown in the figure below. The thickness and coefficient of vertical permeability of each layer is mentioned in the figure. Flow Ah = 0.50 m -3 H, = 3 m K, = 3 x 10° cm/s %3D -2 H2 = 2 m K, = 6.5 x 10 cm/s H = 9 m H3 = 4 m. L = 2 m -4 Kg = 7 x 10 cm/s The total head loss in three layers isarrow_forwardA soil profile is shown in Figure P3.3 along with the stan- dard penetration numbers in the clay layer. Use Eqs. (3.8b) and (3.9) to determine the variation of c, and OCR with depth. What is the average value of c, and OCR? Dry sand y = 16.5 kN/m² 1.5 m Groundwater table Sand 1.5 m Ysat = 19 kN/m³ N60 1.5 m • 8 Clay Ysat = 16.8 kN/m³ 1.5 m A • 8 1.5 m 9 1.5 m 10 Sandarrow_forward
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