Chapter 9, Problem 9.46FU

Interpretation Introduction

(a)

Interpretation:

The mass of $\text{C6H6O2}$ should be calculated.

Concept Introduction:

The actual yield of the product is the amount of product which is formed at the end of reaction experimentally whereas theoretical yield represents the amount of product calculated by expecting that 100 % of reactant changes to product. The percent yield can be shown as:

  $\text{Percent yield = }\frac{\text{Actual yield}}{\text{Theoretical yield}}\text{ x 100}$

Interpretation Introduction

(b)

Interpretation:

The theoretical yield of ${\text{C}}_{\text{10}}{\text{H}}_{\text{12}}{\text{O}}_{\text{2}}$ should be calculated.

Concept Introduction:

The actual yield of the product is the amount of product which is formed at the end of reaction experimentally whereas theoretical yield represents the amount of product calculated by expecting that 100 % of reactant changes to product. The percent yield can be shown as:

  $\text{Percent yield = }\frac{\text{Actual yield}}{\text{Theoretical yield}}\text{ x 100}$

Interpretation Introduction

(c)

Interpretation:

We have to calculate the percent yield and mass of reactant used to calculate given amount of product.

Concept Introduction:

The actual yield of the product is the amount of product which is formed at the end of reaction experimentally whereas theoretical yield represents the amount of product calculated by expecting that 100 % of reactant changes to product. The percent yield can be shown as:

  $\text{Percent yield = }\frac{\text{Actual yield}}{\text{Theoretical yield}}\text{ x 100}$