PRACTICE OF STATISTICS F/AP EXAM
PRACTICE OF STATISTICS F/AP EXAM
6th Edition
ISBN: 9781319113339
Author: Starnes
Publisher: MAC HIGHER
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Question
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Chapter 9.1, Problem 10E

(a)

To determine

To Explain: the mean for the null hypothesis to be true in this setting.

(a)

Expert Solution
Check Mark

Answer to Problem 10E

The correct mean score for the students who are at least 30 years of age is 115.

Explanation of Solution

Given:

From the previous exercise

  H0:μ=115Ha:μ>115

  μ is the population mean score of students who are at least 30 years of age.

If the null hypothesis H0:μ=115 is true, then this means that the true mean score for students who are at least 30 years of age is 115

(b)

To determine

To Explain: the P-value.

(b)

Expert Solution
Check Mark

Answer to Problem 10E

The P-value is if the population mean is equal to 115, then there is possibility of 1.01% of getting a random sample with a sample mean of 125.7 or more.

Explanation of Solution

Given:

  n=45x¯=125.7s=29.8P=0.0101=1.01%

Result previous exercise:

  H0:μ=115Ha:μ>115

The P-value is if the population mean is equal to 115, then there is possibility of 1.01% of getting a random sample with a sample mean of 125.7 or more.

Chapter 9 Solutions

PRACTICE OF STATISTICS F/AP EXAM

Ch. 9.1 - Prob. 11ECh. 9.1 - Prob. 12ECh. 9.1 - Prob. 13ECh. 9.1 - Prob. 14ECh. 9.1 - Prob. 15ECh. 9.1 - Prob. 16ECh. 9.1 - Prob. 17ECh. 9.1 - Prob. 18ECh. 9.1 - Prob. 19ECh. 9.1 - Prob. 20ECh. 9.1 - Prob. 21ECh. 9.1 - Prob. 22ECh. 9.1 - Prob. 23ECh. 9.1 - Prob. 24ECh. 9.1 - Prob. 25ECh. 9.1 - Prob. 26ECh. 9.1 - Prob. 27ECh. 9.1 - Prob. 28ECh. 9.1 - Prob. 29ECh. 9.1 - Prob. 30ECh. 9.1 - Prob. 31ECh. 9.1 - Prob. 32ECh. 9.1 - Prob. 33ECh. 9.1 - Prob. 34ECh. 9.2 - Prob. 35ECh. 9.2 - Prob. 36ECh. 9.2 - Prob. 37ECh. 9.2 - Prob. 38ECh. 9.2 - Prob. 39ECh. 9.2 - Prob. 40ECh. 9.2 - Prob. 41ECh. 9.2 - Prob. 42ECh. 9.2 - Prob. 43ECh. 9.2 - Prob. 44ECh. 9.2 - Prob. 45ECh. 9.2 - Prob. 46ECh. 9.2 - Prob. 47ECh. 9.2 - Prob. 48ECh. 9.2 - Prob. 49ECh. 9.2 - Prob. 50ECh. 9.2 - Prob. 51ECh. 9.2 - Prob. 52ECh. 9.2 - Prob. 53ECh. 9.2 - Prob. 54ECh. 9.2 - Prob. 55ECh. 9.2 - Prob. 56ECh. 9.2 - Prob. 57ECh. 9.2 - Prob. 58ECh. 9.2 - Prob. 59ECh. 9.2 - Prob. 60ECh. 9.2 - Prob. 61ECh. 9.2 - Prob. 62ECh. 9.2 - Prob. 63ECh. 9.2 - Prob. 64ECh. 9.3 - Prob. 65ECh. 9.3 - Prob. 66ECh. 9.3 - Prob. 67ECh. 9.3 - Prob. 68ECh. 9.3 - Prob. 69ECh. 9.3 - Prob. 70ECh. 9.3 - Prob. 71ECh. 9.3 - Prob. 72ECh. 9.3 - Prob. 73ECh. 9.3 - Prob. 74ECh. 9.3 - Prob. 75ECh. 9.3 - Prob. 76ECh. 9.3 - Prob. 77ECh. 9.3 - Prob. 78ECh. 9.3 - Prob. 79ECh. 9.3 - Prob. 80ECh. 9.3 - Prob. 81ECh. 9.3 - Prob. 82ECh. 9.3 - Prob. 83ECh. 9.3 - Prob. 84ECh. 9.3 - Prob. 85ECh. 9.3 - Prob. 86ECh. 9.3 - Prob. 87ECh. 9.3 - Prob. 88ECh. 9.3 - Prob. 89ECh. 9.3 - Prob. 90ECh. 9.3 - Prob. 91ECh. 9.3 - Prob. 92ECh. 9.3 - Prob. 93ECh. 9.3 - Prob. 94ECh. 9.3 - Prob. 95ECh. 9.3 - Prob. 96ECh. 9.3 - Prob. 97ECh. 9.3 - Prob. 98ECh. 9.3 - Prob. 99ECh. 9.3 - Prob. 100ECh. 9.3 - Prob. 101ECh. 9.3 - Prob. 102ECh. 9.3 - Prob. 103ECh. 9.3 - Prob. 104ECh. 9.3 - Prob. 105ECh. 9.3 - Prob. 106ECh. 9.3 - Prob. 107ECh. 9.3 - Prob. 108ECh. 9.3 - Prob. 109ECh. 9.3 - Prob. 110ECh. 9 - Prob. R9.1RECh. 9 - Prob. R9.2RECh. 9 - Prob. R9.3RECh. 9 - Prob. R9.4RECh. 9 - Prob. R9.5RECh. 9 - Prob. R9.6RECh. 9 - Prob. R9.7RECh. 9 - Prob. T9.1SPTCh. 9 - Prob. T9.2SPTCh. 9 - Prob. T9.3SPTCh. 9 - Prob. T9.4SPTCh. 9 - Prob. T9.5SPTCh. 9 - Prob. T9.6SPTCh. 9 - Prob. T9.7SPTCh. 9 - Prob. T9.8SPTCh. 9 - Prob. T9.9SPTCh. 9 - Prob. T9.10SPTCh. 9 - Prob. T9.11SPTCh. 9 - Prob. T9.12SPTCh. 9 - Prob. T9.13SPT
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