Student's Solutions Manual To Accompany Elementary Statistics Tenth Edition

10th Edition

ISBN: 9780321470409

Author: Milton Loyer, Mario F. Triola

Publisher: PEARSON

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Chapter 9.4, Problem 8BSC

In Exercises 5–16, test the given claim.

8. Second-Hand Smoke Data Set 12 “Passive and Active Smoke” includes cotinine levels measured in a group of smokers (n = 40, x ¯ = 172.48 ng/mL, s = 119.50 ng/mL) and a group of nonsmokers not exposed to tobacco smoke (n = 40, x ¯ = 16.35 ng/mL, s = 62.53 ng/mL). Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed by the body, cotinine is produced.

a. Use a 0.05 significance level to test the claim that the variation of cotinine in smokers is greater than the variation of cotinine in nonsmokers not exposed to tobacco smoke.

b. The 40 cotinine measurements from the nonsmoking group consist of these values (all in ng/mL): 1, 1, 90, 244, 309, and 35 other values that are all 0. Does this sample appear to be from a normally distributed population? If not, how are the results from part (a) affected?

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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Chapter 9.4, Problem 7BSC

Chapter 9.4, Problem 9BSC

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Chapter 9 Solutions

Student's Solutions Manual To Accompany Elementary Statistics Tenth Edition

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Solution Summary: The author concludes that the variation of cotinine in smokers is greater than that in nonsmokers who are not exposed to tobacco smoke.

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Chapter 9 Solutions