Chapter 9.6, Problem 9.6.1SR

Interpretation Introduction

Interpretation:

The mass of $AgCl$ recovered has to be found out from the given set of options.

Concept introduction:

Precipitation reaction:

If the precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mass:

Mass of the substances is given by the product of mole of the compound with molar mass of the compound.

$Mass=Mole\times Molarmass$

Mole:

Mole of the compound is given by the ration between mass of analyte and molar mass of compound.

$Mole=\frac{Mass}{Molarmass}$