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Interpretation:
From the given options, the equilibrium constant expression for the reaction has to be chosen.
Concept Introduction:
Law of
The equilibrium constant is the product of molar concentrations of the product which is raised to its
Equilibrium Constant:
Consider a reaction,
Forward
Backward reaction rate
At equilibrium, the rate of forward reaction = rate of backward reaction
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Chapter 9 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- The Michaelis-Menten equation for the enzyme chymotrypsin is 0.14[S] v : 0.015 + [S] where v is the rate of an enzymatic reaction and [S] is the concentration of a substrate S. Calculate dv/d[S] and interpret it.arrow_forwardif the reaction given below occurs and pure A and B were mixed, which of the following would take place as equilibrium was established A + B ⇌ C a. the concentration of C would increase for a time, then remain constant b. the concentration of A would increase for a time, then decrease c. the concentration of B would increase for a time, then remain constantarrow_forwardver is given. A +B C+ D 1) Calculate AG for the above react un and indicáte whether the reaction is favorable or unfavorable [A] = 0.9 M 20°C AG° = 4 KJ/mol %3D [B] = 15mM [C] = 4mM [D] = 3 M R= 8.314 J/moleK %3D %3D 4.7 and explain how you know.arrow_forward
- a particular enzyme catalyzes a single reactant S to a single product P, following michaelis-menten kinetics rp=(VmaxCs) / (Km + Cs) 1. A reaction with this enzyme is carried out at very low substrate concentrations. Draw and label a curve on the plot that describes the reaction kinetics under those conditions.arrow_forwardShow how the Michaelis-Menten Equation was derived from this reaction. k1 k2 E + S = e ES E + Parrow_forwardWhich of the following statements are true for BOTH the "transition state" and an "intermediate" of reaction? (This is a multi-select question, select all that apply.). Both are only observed in enzyme-catalyzed reactions. Both can be converted to product(s) or might decompose back to the reactant(s). Neither are part of the "net equation" for the reaction. Both contain covalent bonds are in the process of breaking and/or forming. Both are part of every chemical reaction. (i.e. the mechanisms of all chemical reactions, whether enzyme catalyzed or not, will have involve both a transition state and an intermediate).arrow_forward
- Help me pleasearrow_forwardConsider the analogy of the jiggling box containing coins that was described on page 85. The reaction, the flipping of coins that either face heads up (h) or tails up (T), is described by the equation h ↔ T, where the rate of the forward reaction equals the rate of the reverse reaction.a. What are ΔG and ΔG° in this analogy? b. What corresponds to the temperature at which the reaction proceeds? What corresponds to the activation energy of the reaction? assume you have an “enzyme,” called jigglase, which catalyzes this reaction. What would the effect of jigglase be and what, mechanically, might jigglase do in this analogy?arrow_forwardConsider a general reaction enzyme A(aq) B(aq) The AGo of the reaction is -9.150 kJ mol-. Calculate the equilibrium constant for the reaction at 25 °C. Keg = What is AG for the reaction at body temperature (37.0 °C) if the concentration of A is 1.9 M and the concentration of B is 0.50 M? 9:26 PM 35% 77°F 6/14/2021arrow_forward
- For the reaction B A at standard conditions with [B] =1 M and [A] =1 M, AG is initially a large negative number. As the reaction proceeds, [B] decreases and [A] increases until the system reaches equilibrium. How do the values of AG and AG" change as the reaction moves toward equilibrium? both AG and AG stay the same O AG reaches zero and AG" becomes more negative AG becomes less negative and AG" stays the same AG stays the same and AG becomes less negative AG becomes positive and AG" becomes positivearrow_forwardWhat terms would best describe the above coupled reaction?A. it is non-spontaneous and endothermic (because the overall Go is positive)B. it is spontaneous and exothermic (because the overall Go is positive)C. it is non-spontaneous and exothermic (because the overall Go is positive)D. it is spontaneous and exothermic (because the overall Go is negative)E. it is non-spontaneous and endothermic (because the overall Go is negative)arrow_forwardWhich one of the following statements is completely TRUE? O When AG > 0, the reaction is BOTH product-favored (spontaneous) AND endergonic. When AG 0, the reaction is BOTH reactant-favored (nonspontaneous) AND endergonic. When AG > 0, the reaction is BOTH product-favored (spontaneous) AND exergonic. When AG > 0, the reaction is BOTH reactant-favored (nonspontaneous) AND exergonic. When AG < 0, the reaction is BOTH reactant-favored (nonspontaneous) AND exergonic.arrow_forward
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