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High School Math Algebra Algebra and Trigonometry: Structure and Method, Book 2

To find the number of tickets of each type.

To find the number of tickets of each type.

Algebra and Trigonometry: Structure and Method, Book 2

Algebra and Trigonometry: Structure and Method, Book 2

2000th Edition

ISBN: 9780395977255

Author: MCDOUGAL LITTEL

Publisher: McDougal Littell

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Question

Chapter 9.9, Problem 7P

To determine

To find the number of tickets of each type.

Expert Solution & Answer

Answer to Problem 7P

There are 48 Patron tickets, 103 Sponsor tickets and 175 Donor tickets.

Explanation of Solution

Given:

Patron tickets =$10

Sponsor tickets =$5

Donor tickets =$2.5

Total number of tickets sold =326

Receipts totalled =$1432.50

Calculation:

Given:

Patron tickets =$10

Sponsor tickets =$5

Donor tickets =$2.5

Total number of tickets sold =326

Let number of be Patron tickets be x , Sponsor tickets be y and Donor tickets be z .

Thus, we have:

z=x+y+24

And, x+y+z=326

And, 10x+5y+2.5z=1432.50

Solving the equation z=x+y+24 and x+y+z=326 , we have:

x+y+24=326−y−x2x+2y=302x+y=151

Solving the equation z=x+y+24 and 10x+5y+2.5z=1432.50 , we have:

x+y+24=1432.50−10x−5y2.52.5x+2.5y+60=1432.50−10x−5y12.5x+7.5y=1372.5125x+75y=137255x+3y=549

Solving the equation x+y=151 and 5x+3y=549 , we have:

5(151−y)+3y=549755−5y+3y−549=0−2y+206=0y=103

Solving the equation x+y=151 for value of x , we have:

x+y=151x=151−103x=48

Solving the equation z=x+y+24 for value of z , we have:

z=x+y+24z=48+103+24z=175

Thus, there are 48 Patron tickets, 103 Sponsor tickets and 175 Donor tickets.

Conclusion:

There are 48 Patron tickets, 103 Sponsor tickets and 175 Donor tickets.

Chapter 9.9, Problem 6P

Chapter 9.9, Problem 8P

Chapter 9 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 9.1 - Prob. 1OE Ch. 9.1 - Prob. 2OE Ch. 9.1 - Prob. 3OE Ch. 9.1 - Prob. 4OE Ch. 9.1 - Prob. 5OE Ch. 9.1 - Prob. 6OE Ch. 9.1 - Prob. 7OE Ch. 9.1 - Prob. 8OE Ch. 9.1 - Prob. 9OE Ch. 9.1 - Prob. 10OE

Ch. 9.1 - Prob. 11OE Ch. 9.1 - Prob. 12OE Ch. 9.1 - Prob. 13OE Ch. 9.1 - Prob. 14OE Ch. 9.1 - Prob. 15OE Ch. 9.1 - Prob. 1WE Ch. 9.1 - Prob. 2WE Ch. 9.1 - Prob. 3WE Ch. 9.1 - Prob. 4WE Ch. 9.1 - Prob. 5WE Ch. 9.1 - Prob. 6WE Ch. 9.1 - Prob. 7WE Ch. 9.1 - Prob. 8WE Ch. 9.1 - Prob. 9WE Ch. 9.1 - Prob. 10WE Ch. 9.1 - Prob. 11WE Ch. 9.1 - Prob. 12WE Ch. 9.1 - Prob. 13WE Ch. 9.1 - Prob. 14WE Ch. 9.1 - Prob. 15WE Ch. 9.1 - Prob. 16WE Ch. 9.1 - Prob. 17WE Ch. 9.1 - Prob. 18WE Ch. 9.1 - Prob. 19WE Ch. 9.1 - Prob. 20WE Ch. 9.1 - Prob. 21WE Ch. 9.1 - Prob. 22WE Ch. 9.1 - Prob. 23WE Ch. 9.1 - Prob. 24WE Ch. 9.1 - Prob. 25WE Ch. 9.1 - Prob. 26WE Ch. 9.1 - Prob. 27WE Ch. 9.1 - Prob. 28WE Ch. 9.1 - Prob. 29WE Ch. 9.1 - Prob. 30WE Ch. 9.1 - Prob. 31WE Ch. 9.1 - Prob. 32WE Ch. 9.1 - Prob. 1P Ch. 9.1 - Prob. 2P Ch. 9.1 - Prob. 3P Ch. 9.1 - Prob. 4P Ch. 9.1 - Prob. 5P Ch. 9.1 - Prob. 6P Ch. 9.1 - Prob. 7P Ch. 9.1 - Prob. 8P Ch. 9.1 - Prob. 9P Ch. 9.1 - Prob. 10P Ch. 9.1 - Prob. 11P Ch. 9.1 - Prob. 12P Ch. 9.1 - 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