Explanation Given Information: The voltage is discharged in an electric capacitor through a resistor after time t is given by, E = E 0 e − t R C Where, E 0 is the initial voltage in volts, C is the capacitance in farads, t is the time required for E 0 to decrease to E and R is the resistance in ohm. The initial voltage is 25.0 mV , the resistance is 1.85 Ω and the capacitance is 0.450 F . Formula used: The formula to calculate the exponential decay is as follows, y = A e − r t Where, y is the amount present at any time, A is the original amount, e is the natural number (exponential), r is the rate of decay and t is time for which the decay occurred. Calculation: Consider the function, E = E 0 e − t R C . Where, E 0 is the original voltage in volts (V), t is the time required for E 0 to decrease to E , R is the resistance in ohms ( Ω ) and C is the capacitance in farads (F). The initial voltage is 25.0 mV , the resistance is 1.85 Ω and the capacitance is 0

Bundle: Elementary Technical Mathematics, Loose-leaf Version, 12th + WebAssign Printed Access Card, Single-Term

12th Edition

ISBN: 9781337890199

Author: Dale Ewen

Publisher: Cengage Learning

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Chapter A, Problem 28E

To determine

To calculate: The voltage after 0.500 s if the initial voltage is 25.0mV with the resistance of 1.85Ω and the capacitance of 0.450F.

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Chapter A Solutions

Bundle: Elementary Technical Mathematics, Loose-leaf Version, 12th + WebAssign Printed Access Card, Single-Term

Ch. A - Prob. 1E Ch. A - Prob. 2E Ch. A - Prob. 3E Ch. A - Prob. 4E Ch. A - Prob. 5E Ch. A - Prob. 6E Ch. A - Prob. 7E Ch. A - Prob. 8E Ch. A - Prob. 9E Ch. A - Prob. 10E

Ch. A - Prob. 11E Ch. A - Prob. 12E Ch. A - Prob. 13E Ch. A - Prob. 14E Ch. A - Prob. 15E Ch. A - Prob. 16E Ch. A - Prob. 17E Ch. A - Prob. 18E Ch. A - Prob. 19E Ch. A - Prob. 20E Ch. A - Prob. 21E Ch. A - Prob. 22E Ch. A - Prob. 23E Ch. A - Prob. 24E Ch. A - Prob. 25E Ch. A - Prob. 26E Ch. A - Prob. 27E Ch. A - Prob. 28E

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The voltage after 0.500 s if the initial voltage is 25.0 mV with the resistance of 1.85 Ω and the capacitance of 0.450 F .

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To calculate: The voltage after 0.500 s if the initial voltage is 25.0mV with the resistance of 1.85Ω and the capacitance of 0.450F.

Chapter A Solutions