CHEMICAL PRINCIPLES (LL) W/ACCESS
7th Edition
ISBN: 9781319421175
Author: ATKINS
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter F, Problem K.2BST
(a)
Interpretation Introduction
Interpretation:
Oxidation number of sulfur in
Concept Introduction:
Oxidation state of a species is the one that has a specified oxidation number. Increase in oxidation number corresponds to oxidation while decrease in oxidation number corresponds to reduction. Rules for assigning oxidation number for an element is given as follows;
- The oxidation number is zero for the element that is present in uncombined state.
- Sum of the oxidation number of the atoms that is present in it is equal to the charge on the species.
- Oxidation number of the element is the charge that is possessed when the more electronegative atom is imagined to be an ion.
(b)
Interpretation Introduction
Interpretation:
Oxidation number of nitrogen in
Concept Introduction:
Refer part (a).
(c)
Interpretation Introduction
Interpretation:
Oxidation number of chlorine in
Concept Introduction:
Refer part (a).
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Phosphoric acid, one of the acids used in some cola drinks, is produced by the reaction of phosphorus(V) oxide, an acidic oxide, with water. Phosphorus(V) oxide is prepared by the combustion of phosphorus.(a) Write the empirical formula of phosphorus(V) oxide.(b) What is the molecular formula of phosphorus(V) oxide if the molar mass is about 280.(c) Write balanced equations for the production of phosphorus(V) oxide and phosphoric acid.(d) Determine the mass of phosphorus required to make 1.00 × 104 kg of phosphoric acid, assuming a yield of 98.85%.
Consider the series of reactions to synthesize the alum (KAl(SO4 )2 · xH2O(s)) from the introduction.
(a) Assuming an excess of the other reagents, from one mole of aluminum Al (s), how many moles of alum will be produced?
(b) Assuming an excess of the other reagents, from one mole of potassium hydroxide KOH, how many moles of alum will be produced?
(c) Assuming an excess of the other reagents, from one mole of sulfuric acid H2SO4 , how many moles of alum will be produced?
(d) If you start the synthesis with 1.00 g of Al, 40.0 mL of 1.50 M KOH, and 20.0 mL of 9.00 M H2SO4 , which of the three will be the limiting reagent?
(e) Assuming that the product is anhydrous (that there are no waters of hydration), calculate the theoretical yield of alum, in grams, based on the amounts of reagents in part
(d). 3. Consider the nickel salt: (NH4 )2Ni(SO4 )2 ·y H2O (Ammonium Nickel Sulfate Hydrate), where y is the number of coordinated waters.
(a) Assuming that the product is anhydrous (y = 0),…
Hematite, Fe₂O3, is an important ore of iron. (An ore is a natural substance from which the metal can be profitably obtained.) The free metal is obtained by
reacting hematite with carbon monoxide, CO, in a blast furnace. Carbon monoxide is formed in the furnace by partial combustion of carbon. The reaction is
Fe₂O3(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)
How many grams of iron can be produced from 1.34 kg Fe₂03?
g Fe
Chapter F Solutions
CHEMICAL PRINCIPLES (LL) W/ACCESS
Ch. F - Prob. A.1ASTCh. F - Prob. A.1BSTCh. F - Prob. A.2ASTCh. F - Prob. A.2BSTCh. F - Prob. A.3ASTCh. F - Prob. A.3BSTCh. F - Prob. A.4ASTCh. F - Prob. A.4BSTCh. F - Prob. A.5ASTCh. F - Prob. A.5BST
Ch. F - Prob. A.1ECh. F - Prob. A.2ECh. F - Prob. A.3ECh. F - Prob. A.4ECh. F - Prob. A.5ECh. F - Prob. A.6ECh. F - Prob. A.7ECh. F - Prob. A.8ECh. F - Prob. A.9ECh. F - Prob. A.10ECh. F - Prob. A.11ECh. F - Prob. A.12ECh. F - Prob. A.13ECh. F - Prob. A.14ECh. F - Prob. A.15ECh. F - Prob. A.16ECh. F - Prob. A.17ECh. F - Prob. A.18ECh. F - Prob. A.19ECh. F - Prob. A.20ECh. F - Prob. A.21ECh. F - Prob. A.22ECh. F - Prob. A.23ECh. F - Prob. A.24ECh. F - Prob. A.25ECh. F - Prob. A.26ECh. F - Prob. A.27ECh. F - Prob. A.28ECh. F - Prob. A.29ECh. F - Prob. A.30ECh. F - Prob. A.31ECh. F - Prob. A.32ECh. F - Prob. A.33ECh. F - Prob. A.34ECh. F - Prob. A.35ECh. F - Prob. A.36ECh. F - Prob. A.37ECh. F - Prob. A.38ECh. F - Prob. A.39ECh. F - Prob. A.40ECh. F - Prob. A.41ECh. F - Prob. A.42ECh. F - Prob. B.1ASTCh. F - Prob. B.1BSTCh. F - Prob. B.2ASTCh. F - Prob. B.2BSTCh. F - Prob. B.3ASTCh. F - Prob. B.3BSTCh. F - Prob. B.1ECh. F - Prob. B.2ECh. F - Prob. B.3ECh. F - Prob. B.4ECh. F - Prob. B.5ECh. F - Prob. B.6ECh. F - Prob. B.7ECh. F - Prob. B.8ECh. F - Prob. B.9ECh. F - Prob. B.10ECh. F - Prob. B.11ECh. F - Prob. B.12ECh. F - Prob. B.13ECh. F - Prob. B.14ECh. F - Prob. B.15ECh. F - Prob. B.16ECh. F - Prob. B.17ECh. F - Prob. B.18ECh. F - Prob. B.19ECh. F - Prob. B.20ECh. F - Prob. B.21ECh. F - Prob. B.22ECh. F - Prob. C.1ASTCh. F - Prob. C.1BSTCh. F - Prob. C.2ASTCh. F - Prob. C.2BSTCh. F - Prob. C.1ECh. F - Prob. C.2ECh. F - Prob. C.3ECh. F - Prob. C.4ECh. F - Prob. C.5ECh. F - Prob. C.6ECh. F - Prob. C.7ECh. F - Prob. C.8ECh. F - Prob. C.9ECh. F - Prob. C.10ECh. F - Prob. C.11ECh. F - Prob. C.12ECh. F - Prob. C.13ECh. F - Prob. C.14ECh. F - Prob. C.15ECh. F - Prob. C.16ECh. F - Prob. C.17ECh. F - Prob. C.18ECh. F - Prob. C.19ECh. F - Prob. C.20ECh. F - Prob. C.21ECh. F - Prob. C.22ECh. F - Prob. D.1ASTCh. F - Prob. D.1BSTCh. F - Prob. D.2ASTCh. F - Prob. D.2BSTCh. F - Prob. D.3ASTCh. F - Prob. D.3BSTCh. F - Prob. D.4ASTCh. F - Prob. D.4BSTCh. F - Prob. D.5ASTCh. F - Prob. D.5BSTCh. F - Prob. D.1ECh. F - Prob. D.2ECh. F - Prob. D.3ECh. F - Prob. D.4ECh. F - Prob. D.5ECh. F - Prob. D.6ECh. F - Prob. D.7ECh. F - Prob. D.8ECh. F - Prob. D.9ECh. F - Prob. D.10ECh. F - Prob. D.11ECh. F - Prob. D.12ECh. F - Prob. D.13ECh. F - Prob. D.14ECh. F - Prob. D.15ECh. F - Prob. D.16ECh. F - Prob. D.17ECh. F - Prob. D.18ECh. F - Prob. D.19ECh. F - Prob. D.20ECh. F - Prob. D.21ECh. F - Prob. D.22ECh. F - Prob. D.23ECh. F - Prob. D.24ECh. F - Prob. D.25ECh. F - Prob. D.26ECh. F - Prob. D.27ECh. F - Prob. D.28ECh. F - Prob. D.29ECh. F - Prob. D.30ECh. F - Prob. D.31ECh. F - Prob. D.32ECh. F - Prob. D.33ECh. F - Prob. D.34ECh. F - Prob. D.35ECh. F - Prob. D.36ECh. F - Prob. E.1ASTCh. F - Prob. E.1BSTCh. F - Prob. E.2ASTCh. F - Prob. E.2BSTCh. F - Prob. E.3ASTCh. F - Prob. E.3BSTCh. F - Prob. E.4ASTCh. F - Prob. E.4BSTCh. F - Prob. E.5ASTCh. F - Prob. E.5BSTCh. F - Prob. E.6ASTCh. F - Prob. E.6BSTCh. F - Prob. E.1ECh. F - Prob. E.2ECh. F - Prob. E.3ECh. F - Prob. E.4ECh. F - Prob. E.5ECh. F - Prob. E.6ECh. F - Prob. E.7ECh. F - Prob. E.8ECh. F - Prob. E.9ECh. F - Prob. E.10ECh. F - Prob. E.11ECh. F - Prob. E.12ECh. F - Prob. E.13ECh. F - Prob. E.14ECh. F - Prob. E.15ECh. F - Prob. E.16ECh. F - Prob. E.17ECh. F - Prob. E.18ECh. F - Prob. E.19ECh. F - Prob. E.20ECh. F - Prob. E.21ECh. F - Prob. E.22ECh. F - Prob. E.23ECh. F - Prob. E.24ECh. F - Prob. E.25ECh. F - Prob. E.26ECh. F - Prob. E.27ECh. F - Prob. E.28ECh. F - Prob. E.29ECh. F - Prob. E.30ECh. F - Prob. E.31ECh. F - Prob. E.32ECh. F - Prob. E.33ECh. F - Prob. E.34ECh. F - Prob. F.1ASTCh. F - Prob. F.1BSTCh. F - Prob. F.2ASTCh. F - Prob. F.2BSTCh. F - Prob. F.3ASTCh. F - Prob. F.3BSTCh. F - Prob. F.4ASTCh. F - Prob. F.4BSTCh. F - Prob. F.1ECh. F - Prob. F.2ECh. F - Prob. F.3ECh. F - Prob. F.4ECh. F - Prob. F.5ECh. F - Prob. F.6ECh. F - Prob. F.7ECh. F - Prob. F.8ECh. F - Prob. F.9ECh. F - Prob. F.10ECh. F - Prob. F.11ECh. F - Prob. F.12ECh. F - Prob. F.13ECh. F - Prob. F.14ECh. F - Prob. F.15ECh. F - Prob. F.16ECh. F - Prob. F.17ECh. F - Prob. F.18ECh. F - Prob. F.19ECh. F - Prob. F.20ECh. F - Prob. F.21ECh. F - Prob. F.22ECh. F - Prob. F.23ECh. F - Prob. F.24ECh. F - Prob. F.25ECh. F - Prob. F.26ECh. F - Prob. F.27ECh. F - Prob. F.28ECh. F - Prob. G.1ASTCh. F - Prob. G.1BSTCh. F - Prob. G.2ASTCh. F - Prob. G.2BSTCh. F - Prob. G.3ASTCh. F - Prob. G.3BSTCh. F - Prob. G.4ASTCh. F - Prob. G.4BSTCh. F - Prob. G.1ECh. F - Prob. G.2ECh. F - Prob. G.3ECh. F - Prob. G.4ECh. F - Prob. G.5ECh. F - Prob. G.6ECh. F - Prob. G.7ECh. F - Prob. G.8ECh. F - Prob. G.9ECh. F - Prob. G.10ECh. F - Prob. G.11ECh. F - Prob. G.12ECh. F - Prob. G.13ECh. F - Prob. G.14ECh. F - Prob. G.15ECh. F - Prob. G.16ECh. F - Prob. G.17ECh. F - Prob. G.18ECh. F - Prob. G.19ECh. F - Prob. G.20ECh. F - Prob. G.21ECh. F - Prob. G.22ECh. F - Prob. G.23ECh. F - Prob. G.24ECh. F - Prob. G.25ECh. F - Prob. G.27ECh. F - Prob. G.28ECh. F - Prob. G.30ECh. F - Prob. H.1ASTCh. F - Prob. H.1BSTCh. F - Prob. H.1ECh. F - Prob. H.2ECh. F - Prob. H.3ECh. F - Prob. H.4ECh. F - Prob. H.5ECh. F - Prob. H.6ECh. F - Prob. H.7ECh. F - Prob. H.8ECh. F - Prob. H.9ECh. F - Prob. H.10ECh. F - Prob. H.11ECh. F - Prob. H.12ECh. F - Prob. H.13ECh. F - Prob. H.14ECh. F - Prob. H.15ECh. F - Prob. H.16ECh. F - Prob. H.17ECh. F - Prob. H.18ECh. F - Prob. H.19ECh. F - Prob. H.20ECh. F - Prob. H.21ECh. F - Prob. H.22ECh. F - Prob. H.23ECh. F - Prob. H.24ECh. F - Prob. H.25ECh. F - Prob. H.26ECh. F - Prob. I.1ASTCh. F - Prob. I.1BSTCh. F - Prob. I.2ASTCh. F - Prob. I.2BSTCh. F - Prob. I.3ASTCh. F - Prob. I.3BSTCh. F - Prob. I.1ECh. F - Prob. I.2ECh. F - Prob. I.3ECh. F - Prob. I.4ECh. F - Prob. I.5ECh. F - Prob. I.6ECh. F - Prob. I.7ECh. F - Prob. I.8ECh. F - Prob. I.9ECh. F - Prob. I.10ECh. F - Prob. I.11ECh. F - Prob. I.12ECh. F - Prob. I.13ECh. F - Prob. I.14ECh. F - Prob. I.15ECh. F - Prob. I.16ECh. F - Prob. I.17ECh. F - Prob. I.18ECh. F - Prob. I.19ECh. F - Prob. I.20ECh. F - Prob. I.21ECh. F - Prob. I.22ECh. F - Prob. I.23ECh. F - Prob. I.24ECh. F - Prob. I.25ECh. F - Prob. I.26ECh. F - Prob. J.1ASTCh. F - Prob. J.1BSTCh. F - Prob. J.2ASTCh. F - Prob. J.2BSTCh. F - Prob. J.1ECh. F - Prob. J.2ECh. F - Prob. J.3ECh. F - Prob. J.4ECh. F - Prob. J.5ECh. F - Prob. J.6ECh. F - Prob. J.7ECh. F - Prob. J.8ECh. F - Prob. J.9ECh. F - Prob. J.10ECh. F - Prob. J.11ECh. F - Prob. J.12ECh. F - Prob. J.13ECh. F - Prob. J.14ECh. F - Prob. J.15ECh. F - Prob. J.16ECh. F - Prob. J.17ECh. F - Prob. J.18ECh. F - Prob. J.19ECh. F - Prob. J.20ECh. F - Prob. J.21ECh. F - Prob. J.22ECh. F - Prob. J.23ECh. F - Prob. J.24ECh. F - Prob. K.1ASTCh. F - Prob. K.1BSTCh. F - Prob. K.2ASTCh. F - Prob. K.2BSTCh. F - Prob. K.3ASTCh. F - Prob. K.3BSTCh. F - Prob. K.4ASTCh. F - Prob. K.4BSTCh. F - Prob. K.5ASTCh. F - Prob. K.5BSTCh. F - Prob. K.1ECh. F - Prob. K.2ECh. F - Prob. K.3ECh. F - Prob. K.4ECh. F - Prob. K.5ECh. F - Prob. K.6ECh. F - Prob. K.7ECh. F - Prob. K.8ECh. F - Prob. K.9ECh. F - Prob. K.10ECh. F - Prob. K.11ECh. F - Prob. K.12ECh. F - Prob. K.13ECh. F - Prob. K.14ECh. F - Prob. K.15ECh. F - Prob. K.16ECh. F - Prob. K.17ECh. F - Prob. K.18ECh. F - Prob. K.19ECh. F - Prob. K.20ECh. F - Prob. K.21ECh. F - Prob. K.22ECh. F - Prob. K.23ECh. F - Prob. K.24ECh. F - Prob. K.25ECh. F - Prob. K.26ECh. F - Prob. L.1ASTCh. F - Prob. L.1BSTCh. F - Prob. L.2ASTCh. F - Prob. L.2BSTCh. F - Prob. L.3ASTCh. F - Prob. L.3BSTCh. F - Prob. L.1ECh. F - Prob. L.2ECh. F - Prob. L.3ECh. F - Prob. L.4ECh. F - Prob. L.5ECh. F - Prob. L.6ECh. F - Prob. L.7ECh. F - Prob. L.8ECh. F - Prob. L.9ECh. F - Prob. L.10ECh. F - Prob. L.11ECh. F - Prob. L.12ECh. F - Prob. L.13ECh. F - Prob. L.14ECh. F - Prob. L.15ECh. F - Prob. L.16ECh. F - Prob. L.17ECh. F - Prob. L.18ECh. F - Prob. L.19ECh. F - Prob. L.20ECh. F - Prob. L.21ECh. F - Prob. L.22ECh. F - Prob. L.23ECh. F - Prob. L.24ECh. F - Prob. L.25ECh. F - Prob. L.29ECh. F - Prob. L.30ECh. F - Prob. L.31ECh. F - Prob. L.32ECh. F - Prob. L.33ECh. F - Prob. L.34ECh. F - Prob. L.35ECh. F - Prob. L.37ECh. F - Prob. L.38ECh. F - Prob. L.39ECh. F - Prob. L.40ECh. F - Prob. L.41ECh. F - Prob. L.42ECh. F - Prob. M.1ASTCh. F - Prob. M.1BSTCh. F - Prob. M.2ASTCh. F - Prob. M.2BSTCh. F - Prob. M.3ASTCh. F - Prob. M.3BSTCh. F - Prob. M.4ASTCh. F - Prob. M.4BSTCh. F - Prob. M.1ECh. F - Prob. M.2ECh. F - Prob. M.3ECh. F - Prob. M.4ECh. F - Prob. M.5ECh. F - Prob. M.6ECh. F - Prob. M.7ECh. F - Prob. M.8ECh. F - Prob. M.9ECh. F - Prob. M.10ECh. F - Prob. M.11ECh. F - Prob. M.12ECh. F - Prob. M.13ECh. F - Prob. M.14ECh. F - Prob. M.15ECh. F - Prob. M.16ECh. F - Prob. M.17ECh. F - Prob. M.18ECh. F - Prob. M.19ECh. F - Prob. M.20ECh. F - Prob. M.21ECh. F - Prob. M.22ECh. F - Prob. M.23ECh. F - Prob. M.25ECh. F - Prob. M.26ECh. F - Prob. M.27ECh. F - Prob. M.28E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Phosphorous acid, H3PO3, is oxidized to phosphoric acid, H3PO4, by nitric acid, which is reduced to nitrogen monoxide, NO. Write the balanced equation for this reaction.arrow_forward4.48 Elemental phosphorous is used in the semiconductor industry. It can be obtained from an ore called fluoroapatite via reaction with SiO2 and C: 4Ca5( PO4)3F+18SiO2+30C3P4+30CO+18CaSiO3+2CaF2 Suppose a particular semiconductor production plant requires 1500 kg of P4. If the recovery of P4 from this reaction is 73% efficient, what mass of fluoroapatite is needed?arrow_forward4.22 Generally, an excess of O2 is needed for the reaction Sn+O2SnO2 . What is the minimum number of moles of oxygen required to oxidize 7.3 moles of tin?arrow_forward
- Aluminum is produced commercially by the electrolysis of Al2O3 in the presence of a molten salt. If a plant has a continuous capacity of 1.00 million A, what mass of aluminum can be produced in 2.00 h?arrow_forwardComplete and balance the following acid-base equations:(a) A solution of HClO4 is added to a solution of LiOH.(b) Aqueous H2SO4 reacts with NaOH.(c) Ba(OH)2 reacts with HF gas.arrow_forwardConsider the series of reactions to synthesize the alum (KAl(SO4 )2 · xH2O(s)) from the introduction. Assuming an excess of the other reagents, from one mole of potassium hydroxide KOH, how many moles of alum will be produced?arrow_forward
- 13.) Calculate the mass of solid MgSO̟•7H,O that must be added to precipitate out all of the PO,3- ions in the form of MgNH¸PO¸ •6H,O from 10.0 mL of a 2.0 M solution of PO,³ (aq)?arrow_forwardWrite the balanced chemical equation for conversion of Al(s) to KAl(SO4)2·12H2O(s) in aqueous solution.arrow_forwardWould you expect potassium perchlorate, KClO4(aq), in a concentrated acidic solution to act as an oxidizing agent or as a reducing agent?arrow_forward
- Write the balanced net ionic equation for the reaction of hydrogen sulfide (H2S) with bromate ions, BrO3-, in acidic solution to form sulfur ions and bromide ions. How many H+ are there in the balanced equation?arrow_forward(A) if both sentences are true,(B) if both sentences are false,(C) if the first sentence is true but the second is false, and(D) if the first sentence is false but the second is true. 1. In a redox reaction, the oxidation number of iron changed from +2 to +3; thus, sulfur is a reducing agent. In a redox reaction, the oxidation number of nitrogen was unchanged; thus, nitrogen is an oxidant. 2. In a redox reaction, the reducing agent is oxidized and it gains electrons. In a redox reaction, the oxidizing agent is reduced and it gains electrons. 3. Bending stress is also known as flexural stress. The test used in observing the mechanical strength of chocolate is the three-point bend test. 4. The flexural strength of materials may be expressed in Pascals. Magnesium is more reactive than silver; therefore, magnesium corrodes faster than silver with the aid of air, oxygen, and sea water.arrow_forwardDescribe how to determine the oxidation number of sulfur in(a) H₂S and (b) SO₃²⁻.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY