Water Potential of Potato Cell Lab
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Water Potential of Potato Cell Lab
Biology 11 AP
November 28, 2018
AP BIOLOGY
Lab: Determining the Water Potential of Potato Cells
Background
In animal cells, the movement of water into and out of the cell is in±uenced by the relative
concentration of solute on either side of the cell membrane. If water moves out of the cell,
the cell will shrink. If water moves into the cell, the cell may swell or even bursts. In plant
cells, the presence of a cell wall prevents the cells from bursting, but pressure does
eventually build up inside the cell and a²ects the process of osmosis. When the pressure
inside the cell becomes large enough, no additional water will accumulate in the cell even
though the cell still has a higher solute concentration than does pure water. So the
movement of water through the plant tissue cannot be predicted simply through knowing
the relative solute concentrations on either side of the plant cell wall. Instead, the concept
of water potential is used to predict the direction in which water will di²use through living
plant tissues.
In a general sense, the water potential is the tendency of water to di²use from one area to
another under a given set of parameters. Water potential is expressed in bars, a metric unit
of pressure equal to about 1
the atmosphere and measured with a barometer. Water potential is abbreviated by the
Greek letter psi and has two major components: solute potential, which is dependent on
solute concentration and pressure potential, which results from the exertion of pressure -
either positive or negative - on a solution. We express this as:
In Figure 1.1. A potato cell is placed in pure water. Initially, the water potential outside the
cell is 0 and is higher than the water potential inside the cell (-3). Under these conditions,
there will be a net movement of water into the cell. The pressure potential inside the cell
will increase until the cell reaches a state of equilibrium.
Pre-Lab Questions
1.
What would happen if you applied saltwater to the roots of a plant? Why? (2
marks)
Due to the fact that the ionization constant of salt water is -2, this creates a solution with a
lower water potential. Water would move out of the cell into the hypertonic solution (from
higher to lower potentials), causing the roots of the plant to wilt as a result.
2.
Will water moves into or out of a plant cell if the plant cell has higher
water potential than the surrounding environment? (1 mark)
The water will move out of the plant cell into the surrounding environment, trying to reach a
state of equilibrium.
Directions:
1.
You will be provided with 5 sucrose solutions of unknown molarity (Each
unknown is one of the following: 0.2 M, 0.4 M, 0.6 M, 0.8 M, 1.0M).
2.
Slice a potato into 5 equal cylinders.
3.
Pour enough of each unknown solution into a test tube to cover the potato. Mark
each test tube.
4.
Determine the initial mass of the 5 potato cylinders and record.
5.
Place the potato cylinders into the test tubes with the solution and cover with
plastic wrap. Leave overnight.
6.
Remove the cylinders from the test tubes and carefully blot o² any excess
solution. Record the room temperature in Celsius.
7.
Determine the ³nal mass of the potato cylinders and record.
8.
Calculate the % change. Record.
9.
Determine the molarity of the unknown solutions.
This step will require some
thought.
10. Graph the results. In order to do so, the 0 axis line should actually be in the
middle of your graph. The y-axis above this line should be labelled % increase in
mass while the y-axis below this line should be labelled % decrease. The x-axis is
the sucrose molarity within the test tube.
Data Table 1: Mass of potato before and after exposure in solutions of di²erent molarities
Potato in
Solution
Initial
Mass (g)
Final
mass (g)
Calculations
Di±erence
in Mass (g)
Change (%)
A
4.9
3.79
3.79 - 4.9
-1.11
-23
B
5.05
4.25
4.25 - 5.05
-0.8
-16
C
4.39
4.04
4.04 - 4.39
-0.35
-8
D
4.31
4.17
4.17 - 4.31
-0.14
-3
E
4.38
4.44
4.44 - 4.38
0.06
1
Room temperature = 22 degrees Celsius = 295 degrees Kelvin
Analysis and Graph: (5 marks – 1 for the title, 1 for labelling x-axis, 1 for labelling
y-axis, 2 for points)
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Related Questions
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1. Fill in the table below to indicate what happened to the elodea cells in each of the following
solutions.
Solution
Hypertonic
Isotonic
Hypotonic
Distilled water
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1. Summarize the results of the experiment in the table below. First, indicate what the tonicity
(hypertonic, hypotonic or isotonic) of the solution is and then describe the appearance of the red
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Solution
10% NaCl
Will the cell membrane
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.9% NaCl
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TONICITY
DRAG THE WORDS INTO THE BLANK SPACES BEL@W TO ACCURATELY
COMPLETE THE PARAGRAPH
Hypertonic
Isotonic
Hypotonic
Hypertonic Lsotonic Hypotonic
animal cell
plant cell
A
Above are a represented plant cell and an animal cell. Refer to the key on slide 5 and fill in the blanks below. (If you find
yourself counting solute dots, you're working much too hard!) Assume that the cell membranes are allow only water (not the
solutes) to pass through.
Because the cytoplasms of the plant and the animal cell have equal concentrations of solutes, we can say that
their cytoplasms are
to each other. If we put both the plant and the animal cells into Solution A,
we would expect no change in the cells, because Solution A is
to the cytoplasm of each cell.
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Model 2 - Selectively Permeable Cell Membrane and Simple
Diffusion
Extracellular Fluid Wwwwww Cytoplasmic Fluid
Extracellular Fluid
www Cytoplasmic Fluid
www
w
wwwwww
www
www.x
www.
www.
www
www
www.
ACTE
Omw
ww
ww
Type lions
Type 2 molecules (glucose)
Extracellular Fluid Wwwwwww Cytoplasmic Fluid
Extracellular Fluid
ww Cytoplasmic Fluid
d
wwwx
w
mo
AM
8
MO
m
un
www
m
8
www
www.x
www.
Summ
Type 3 Urea molecules
upe 4 oxygen molecules
The four diagrams in Model 2 illustrate movement of four types of substances (see the table in
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phospholipid bilayer (extracellular fluid on left and cytoplasmic fluid on right).
of
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= Acidic
= Basic
= Polar (uncharged)
O = Hydrophobic
CO₂
T
20
CO2
T
20
NH₂
A.
T
20
NH₂
B.
NH₂
C.
T
20
NH₂
D.
NH₂
E.
tot
10
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dentify the structure labeled A (thick line)
I Choose |
(Choose
dentify the structure labeledB
Cell membrane
dentify the structure labeledC
Cell wall
Nucleus
Jentify the structure labeled D (thin line belween the whiteeand purple)
yloplasm
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The majority of solutes that diffuse across the plasma membrane cannot move directly through the lipid bilayer. The passive movement of such solutes (down their concentration gradients without the input of cellular energy)
requires the presence of specific transport proteins, either channels or carrier proteins. Diffusion through a transport protein in the plasma membrane is called facilitated diffusion.
outside cell
channel protein
inside cell
carrier protein'
Adapted from Biology by Campbell and Reece ©2008 Pearson Education, Inc.
Sort the phrases into the appropriate bins depending on whether they are true only for channels, true only for carrier proteins, or true for both channels and carriers.
▸ View Available Hint(s)
only channels
transport primarily small polar organic
molecules
provide a continuous path across the
membrane
provide a hydrophilic path across the
membrane
allow water molecules and small ions
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TONICITY DRAG THE WORDS INTO THE BLANK SPACES BELOW TO ACCURATELY
COMPLETE THE PARAGRAPH
Hypotonic
Osmosis
water
Swell
Cell wall
animal cell
plant cell
Facilitated
Stay the same
Hypertonic
Diffusion
Isotonic
Shrink
A
Let's put both cells into Solution B. Because Solution B is hypertonic to the cytoplasms of the cells, we
would expect water to
the cells through the process of
This would result in the
cytoplasm of both cells shrinking. Now we'll put both the plant and the animal cell into Solution C, which,
because it contains no solutes at all, is
to the cytoplasm of both cells.
will
enter both cells through osmosis. The animal cell is likely to
unfortunately. The plant cell,
however, is protected from this because of the presence of its
which is lacking in the
animal cell.
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Q11
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this question from bioengineering
asap
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Please see the picture below
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t be submitted on one attempt
auto-submit when time expires
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Question 6
Which ion is actively transported through the cell membrane and why?
O Na, because the ion is being moved against its gradient
O Mg, because the membrane is impermeable to this ion
OK, because the ion is being moved with its gradient
O Cl, because the ion is moved to equilibrium
< Previous
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a)
b)
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10% NaCl
0% NaCl
90% H₂O
83
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Tonicity3
:=
Homework • Unanswered
Suppose the circle represents a cell which is sitting in a solution. Compare
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1% sugar
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Drag and drop options on the right-hand side and submit. For keyboard navigation... SHOW MORE v
The solution is...
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The cell is...
isotonic
out of the cell.
Water will move...
hypertonic
hypotonic
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II
II
II
II
II
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the plant and thus avoid cytolysis.
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Part 2: Based on your answer in Part 1, would there be more hydration shells in the
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A
3
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B
Time
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с
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D
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imaging
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a
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E Fullscreen
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Initial Volume (Vi)
(mL)
Final Volume (Vf)
(mL)
Change in Volume
(Vi – Vf)
(mL)
A
20% sucrose
20% sucrose
92.0 mL
94.0 mL
-2.0 mL
B
40% sucrose
20% sucrose
92.0 mL
92.0 mL
0.0 mL
C
20% sucrose
40% sucrose
92.0 mL
90.0 mL
2.0 mL
Treatment
Percent Change
A
-2%
B
0%
C
2%
Hypothesize which dialysis bags should gain, lose or stay the same in regards to volume. Explain.
Which solution is hypotonic, hypertonic and isotonic?
Explain what the change in volume of the dialysis tube indicated and describe what happened when the volume increased and when the volume decreased.
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*YOU MUST ANSWER (1)-(27)
*JUST FILL IN THE BLANKS
THANK YOU IN ADVANCE.
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1:58
l 5GE
Done
11 of 23
3 of 12
During an investigation on membrane transport, a researcher
exposed bacterial cells to different concentrations of two
different solutes: A and B. The rate of transport of each
solute into cells is represented in the graph.
= Solute A
= Solute B
Solute Concentration
Which of the following best explains the greater rate of
transport for solute A than for solute B at higher solute
concentrations?
Solute A is being transported by simple
diffusion, which does not rely on membrane
proteins to control the rate of transport.
A
Solute A is being transported by active
transport, which uses ATP and has higher
rates of transport than passive transport.
B
Solute A is being transported by facilitated
diffusion, which uses membrane proteins to
increase the rate of transport.
Submit
!!
Rate of Transport
II
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Extracellular Fluid mu Cytoplasmic Fluid
Extracellular Fluid
wwwwwwy
hmmmml Cytoplasmic Fluid
www.wmy
wwwwwy
hummu
hmm
wwwwwwy
immmml
wwwwwwwwY
immu
hmmmml
wwwwy
hmmmm
O
wwwwwwy
wwwwwwwy
imm
hmmmmm
Y
www
Y
www
10. What appears to be the effect of inserting a protein channel into the membrane on the
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phospholipids) of the embedded protein likely to be polar or nonpolar? Explain your reasoning.
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cell uses energy from…
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