BIO D7 Population Evolution Genetics

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Number 1-6 1. What is an allele? 2. In your own words, define the Hardy-Weinberg Principle. Include the purpose of the Hardy-Weinberg principle as it relates to our understanding of evolution. 3. What 5 conditions must be met for a population to be in equilibrium? 4. Using the chart in the PowerPoint, explain what happens when conditions are violated and how that will affect evolutionary equilibrium. 5. What is genetic drift? 6. What is a bottleneck in evolutionary terms?

Genetics Q2

Genetics Q5

7:56 O 2 Done + Quiz 1 Punnett Square Scientists at Bikini Bottoms have been investigating the genetic makeup of the organisms in this community. | Use the information provided and your knowledge of genetics to answer each question. 1. For each genotype below, indicate whether it is a heterozygous (He) OR homozygous (Но). TT Bb DD Ff tt dd Dd ff Tt bb BB FF Which of the genotypes in #1 would be considered purebred? Which of the genotypes in #1 would be hybrids? | 2. Determine the phenotype for each genotype using the information provided about SpongeBob. Yellow body color is dominant to blue. Text editor Edit picture Fill Form Annotation

what carries genetic information

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Question 11 What statement is FALSE regarding the use linkage mapping for human genetics? O The first linkage map showed the relative location of genetic markers. OA large number of chromosomes means that many traits assort independently, frustrating linkage mapping efforts. O Linkage mapping continues to be the preferred method to determine alleles associated with disease. Initial linkage mapping used family pedigrees. Question 12 Which of the following is not a component of Sanger sequencing?

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Genetics Question 7

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Question 3 Listen Which of the following statements describe disadvantages of the classical Sanger sequencing approach when compared to the modern Sanger sequencing method? |Radioactivity must be used, representing an added hazard Fluorescence is used, representing an added hazard Four reaction are used, requiring more reagents and escalating cost OGel electrophoresis is used to separate the various products by size but slowing overall completion of sequencing OA single reaction is used, complicating the analysis O Capillary electrophoresis is used to separate the various products by size but slowing overall completion of sequencing Question 4 4 Listen Electrophoresis of polynucleotides can be done using either agarose or polyacrylamide gels. What is the primary consideration when choosing which polymer gel to use? O Overall charge on polynucleotide sample, greater overall negative charge requires agarose gel with smaller pores to slow the migration of the highly charged sample O…

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GQ3

- Student Notes 46. Piedmontese Size: breed Cows average between 1..200 to 1.400 Ibs.: mature bulls average between 2,000 to 2,200 Ibs. Usage: have higher than any other breed and are also valued for their leanness due to their double muscling, small bones and thin skin 47. Pinzgauer Origin: Austria nipho ombei9 bevlave developed by Alpine exportation in Europe started in the 1800s; Canada imported them in 1972; semen was exported to the United States the same as far back as 500 A.D. year Characteristics: chestnut red with white on the back, tail and barrel horned or polled have strong, correct legs for traveling long distances

Question 4 Listen A gene known as H is epistatic to the ABO blood type genes. Based solely on this statement which of the following is possible? A) An individual with type A blood could be phenotypically hh even if they are genotypically Hh B) An individual who is genotypically IAA could be phenotypically type O if they are also hh C) An individual who is hh is more likely to be phenotypically type A than type B D) None of the above could ever be possible.

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216 Inquiry into Life Laboratory Manual, 16th Edition ©2020 Mader Experimental Procedure: Wing Length and Body Color in Drosophila If your instructor has frozen flies available, cross out the numbers in Table 22.4 and use the stereomicroscope or a hand lens to count the flies of each type given in Table 22.4. Otherwise simply use the data supplied for you in Table 22.4. Table 22.4 Wing Length and Body Color in Drosophila* Phenotypes Long Gray Long Ebony Short Short Phenotypic Gray Ebony Ratio Number of offspring 28 32 28 30 Class data 128 120 120 120 *Wings and body are understood in this table. Conclusions: Wing Length and Body Color in Drosophila • Calculate the actual phenotypic ratio based on the data and record in Table 22.4. Do the results differ from the expected ratio per individual data?. Per class data? Explain your answer. Two-Trait Genetics Problems 1. In tomatoes, tall is dominant and short is recessive. Red fruit is dominant and yellow fruit is recessive. Choose a key for…

I 1 Part I: Mendelian Inheritance Colour blindness is an X-linked recessive disorder characterized by the inability to either differentiate between colours or see colour at all. Cystic fibrosis is an autosomal recessive disorder characterized by the abnormal secretion of thick mucuses rather than thin. The resulting thick mucus can cause adverse effects in the lungs, pancreas, liver, kidneys, and intestines. Often men afflicted by this condition are rendered infertile. Gideon is colour blind and is a carrier for cystic fibrosis and his partner Malenia, is a carrier for both colour blindness and cystic fibrosis. Gideon and Malenia have 4 offspring; Sellen, Irina, Alexander, and Kenneth. Sellen is a carrier for colour blindness and has cystic fibrosis. Irina has colour blindness and is a carrier for cystic fibrosis. Alexander does not carry the mutation for colour blindness but is a carrier of cystic fibrosis. Finally, Kenneth is both colour blind and is afflicted by cystic fibrosis.…

Module 10 DNA & Protein - 20 O Module 9 Genetics - 2021SP/B X B Take Test: Heredity 2 Homewor X + A sunyocc.open.suny.edu/webapps/assessment/take/launch.jsp?course_assessment_id=_109843_1&course_id=_53817_1&content_id3D_ * Question Completion Status: QUESTION 1 Some dogs bark while following a scent trail; others are silent. The barker allele is dominant (B) to the silent recessive allele (b). The allele for straight tails is dominant (S) over the allele for curly tails (s). If two dogs are heterozygous for both traits, which of these correctly identifies the genotypes of the parents? O a. BbSs x BbSs O b. BbSs x bbss O c. BbSs x bbSs O d. Bbss x bbSs QUESTION 2 Some dogs bark while following a scent trail; others are silent. The barker allele is dominant (B) to the silent recessive allele (b). The allele for straight tails is dominant (S) over the allele for curly tails (s). If two dogs are heterozygous for both traits, when we "FOIL" to see what allele combinations they can give to…

GEN BIO NUMBER 4

123and4

FINALLLY FRIDAY Part B: How Mutations Can Lead to Disorders Note: The examples given in this octivity do not represent exact DNA sequences on the genes described. To do so would be impossible as most genes contain over 1000 nucleotides that code for several hundred omino acids which are joined together to form proteins. This activity gives small segments of DNA in each of these genes and DOES demonstrate actual mutations that do occur within them. Gene 1. Beta Hemoglobin Gene (HBB Gene) is an important gene located on human chromosome 11 shown below. This gene plays an important role in the production of hemoglobin, a protein in red blood cells responsible for carrying oxygen in your blood. Part A: Normal Beta Hemoglobin: Using the un-mutated DNA sequence supplied from the HBB gene below, transcribe and translate the DNA into the corresponding arnino ack sequence that forms hemoglobin. NORMAL H866 GENE MUTATED HBB GENE DNA RNA DNA RNA H 1 C C 2 3 11 S 2 3 Chromosome 11 6 7 56 TGAGCT 03…

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Question 9 Which of the following statements about Genome-wide association studies is NOT true? O A genome-wide association study is an approach that involves testing genetic variations in the genomes of many people to find genetic variations associated with a particular disease. O When DNA variations are linked to a trait through a genome-wide association study, they always exhibit an autosomal recessive inheritance pattern. O Genome-wide association studies are useful because they can identify alleles that have small effects on multifactorial traits. O Genome-wide association studies only became possible in the past 5-10 years when methods such as SNP-chip and whole genome sequencing were invented.

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practice problems not sure how to solve! genetics!