6-2 Engineering a Better Air Bag Lab Report

(no subject)-ftar X → C 5 Esc app.101edu.co STARTING AMOUNT 71°F Sunny e A B 1₁ Q A 7 Mail - Francesca X N X @ 2 W S F2 X Homepage - CHI X # 3 E D F3 4 mol H₂ $ T C HOL Aktiv Chemistry x What volume in liters of H: gas would be produced by the complete reaction of 2.93 g of Al solid at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP. 2 Al(s) 6 HCI (aq) 2 AICI (aq) + 3 H: (g) R ADD FACTOR 6 F 22.4 26.98 g Al Dll. FS % 5 V T G molar mass of ox 2.93 G LAI 1 * ^ 6 F6 Question 25 of 34 B 2.02 1.62 Y LH₂ H 2 University of Del: x Online Payment X 17 & 7 ANSWER mol Al n N U 3 7.30 J 6.022 x 10 3.65 g H₂ ✔ N PrtScn 18 * 8 19 g/mol H₂ Home I M 0.329 ( 9 K g/mol Al End O F10 ) 0 L Sign In PgUp P x + PgDn : Po H 12 ☆ 10:47 AM 7/13/2022 ins □O ⠀ Submit D Del Backspace Enter Shif

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Need to calculate R and the average of R for each determination.  Gas law constant data Determination 1 2 3 4 5 mass Mg, g 0.0196 0.0168 0.0196 0.0166 0.0206 moles Mg, mol 0.0008064 mol 0.00069121 0.0008064 0.0006830 0.0008476 initial syringe volume, mL 0.93 0.91 1.09 1.05 1.01 final syringe volume, mL 21.09 18.47 21.47 18.40 22.38 volume H2, mL 20.16 17.56 20.38 17.35 21.37 barometric pressure, torr             760 T 760T 760T 760T 760T vapor pressure water, torr 22.4 T 22.4 T 22.4 T 22.4 T 22.4 T corrected pressure, atm* 0.970526 0.970526 0.970526 0.970526 0.970526 temperature, °C 24 C 24 C 24 C 24 C 24 C temperature, K 297  K 297  K 297  K 297  K 297  K R, mL*atm/K/mol ? ? ? ? ? average R, mL*atm/K/mol ? ? ? ? ?

g uis proulem Part A - Relating Mole Fractions and Partial Pressures A 4.0-L vessel containing N2 at STP and a 2.0-L vessel containing H2 at STP are connected by a valve. If the valve is opened allowing the two gases to mix, what is the mole fraction of hydrogen in the moture? O 0 034 O 0.96 O 0.33 O 0.50 O 067 Submit Request Answer rovide Feedback

← O Aktiv Chemistry Esc KU Portal D2 D2L https://app.101edu.co 457 Pantly sunny 1 X + Ch. 1 Introduction -... (@ 2 Aktiv Chemistry A chamber contains equal molar amounts of H2, N2, and O₂. If the total chamber pressure is 2.00 atm, then the partial pressure of H₂ is: #3 Connect-Bio Google Docs F3 $ 4 DII % 5 CG Grade Calculator .... R Point Grade Calcula... FS Question 28 of 30 Q FE A 6 * F7 & 7 PrtScn Class Sear Home 8

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The prevailing atmospheric pressure on a plateau in Colorado is 0.786 atm. Express this pressure in pounds per square inch, kilopascals, pascals, millimeters Hg, and inches Hg. Hint: 1 atm 101.3 КPa = 1.013x105 Pa = 760 mm Hg 14.69 psi 29.92 in Hg %3D atm psi КРа Ра mm Hg in Hg 0.786 Submit Answer Retry Entire Group 9 more group attempts remaining

[Relerences] Complete the following table for an ideal gas. P V n 7.74 x 10° Pa 13.5 mL mol 25°C а. b. atm 43.0 mL 0.472 mol 223 K 405 torr 4.4 x 10 -2 mol 331°C С. d. 745 mm Hg 10.3 L 0.401 mol °C Submit Answer Try Another Version 3 item attempts remaining

we use Pv=nRT. Everything here should be related to H2 (g)    --> Chemical equation1Mg +2 HCl à MgCl2 +H2(g) From video : mass of Mg =.0407 g H2 gas volume = 38.2ml Temperature of room=24.0 +273=297k Total Pressure of the room = 30.01 in mmHg Calculations: find total pressure from barometer and convert it to mmHg, 1 in =2.54 cm and 25.4 mm 30.01 in mmHg x 25.4 mm Hg =762.3 mmHg total pressure of room ​    ​​ 1in mmHg  First step- convert g of Mg to mol of H2 0.0407g Mg x 1mol/24 gx 1molH2 = 0.00169mol                                          1mol Mg Second step: Total pressure of gas = Pressure of H2 + P of water 762.3 = p H2 + 22.4    FROM reference (canvas)=Pressure of water at 24 C= 22.4 mmHg n= 0.00169mol H2 Pressure of H2= 762.3-22.4= 739.854  x 1atm/760= 0.973 atm H2 Volume of H2= 38.2 ml /1000 =0.038L H2 Temp= 297K   anwer this quesions with the information provide: Using PV=nRT, Find R=? (No R averge needed)  à 0.973X0.0382=0.00169XRx 297  0.0372=0.50R Then, Percent error…

The pressure in Denver, Colorado averages about 632 mm Hg. How many atmospheres is this? STARTING AMOUNT ADD FACTOR ANSWER RESET ( ) 632 0.98692 1 1000 42.5 760 0.832 105 1.01325 1.01325 x 105 6.24 0.001 101.325 14.70 atm Pa mm Hg torr kPa psi bar

STARTING AMOUNT + 78°F Mostly cloudy W X 1** * # 3 E X 140 $ 4 R 96 5 What volume in liters of H₂ gas would be produced by the complete reaction of 2.93 g of Al solid at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP T 6.022 x 1023 mol H₂ F SDEC ADD FACTOR x( ) -- 2 Al (s) + 6 6 140 6 2 g/mol Al Q Search G H 2.02 & 4 7 B N 3 mol Al U ** 3.65 CH 8 HCI (aq) → HCI (aq)→→ 2 AICI (aq)+ 3 H₂ (g) Question 3 of 33 6 M & Al 7.30 1 hp ¹144 ( 9 K 0.329 LAI Fig ANSWER O 2.93 V11 > 26.98 L LH₂ O alt P 1.62 22.4 g H₂ RESET 2 [ 1 g/mol H₂ 1 brt sc 1 backspace

STARTING AMOUNT + 78°F Mostly cloudy B 2 W 3 X E X 4 4 R 196 % 5 What volume in milliliters of CO gas would be produced by the complete reaction of 2.40 g of C solid at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP C(s) + H₂O(g) → CO(g) + H₂(g) BC T SDES C CV G ADD FACTOR 22.4 *( ) - B 40 28.01 6 LC Q Search 1000 Y H & mol CO - 7 6.022 x 102 N U 8.92 ek J Question 11 of 33 mL CO 8 M 2.40 4480 144 mol C 9 K ANSWER 12.01 1920 g/mol C O alt 1 0.001 P LCO RESET 2 4.48 ctri g CO 22 pause

An automobile tire is inflated to a pressure of 31.6 psi. Express this pressure in atmospheres, kilopascals, inches Hg, millimeters Hg and torr. Hint: 1 atm 101.3 kPa 29.92 in Hg = 760 mm Hg 14.69 psi 760 torr %3D %3D %3D psi atm kPa in Hg mm Hg torr 31.6 Submit Answer Retry Entire Group 9 more group attempts remaining

Pressure (Atm) 25 ▬▬ 20 15 State X 10- 5 2 State Y A plot of pressure-volume isotherms for an ideal gas at two different temperatures is shown below. In which of these processes would AS(gas) > 0? State Z 4 Volume (L) 6 T = 546 K T = 273 K 8 A) X→Y B) Y→ Z C) Z→ X D) X → Y and Y → Z E) Y→ Z and Z → X

I need help with both parts of the question please

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3 please

pllege.com/course. tml?courseld%3=16914186&OpenVellumHMAC=Df8cc2710256b118234d2cdf Maps M Gmail 85951877123 O Milton Ochoa - Exp... SANTILLANA PRESENTAC Part A The density of chlorine gas at 1.21 atm and 39.9°C is g/L. O 0.299 O 3.34 0.370 O 1.67 O 0.0471 Submit Request Answer Pearson Copyright O 2021 Pearson Education Inc. All rights reserved. Terms of L ar

Use the combined gas law by plugging in the numbers into it and solve the missing part

7. A sample of air analysed at 0°C and 1 atm. pressure is reported to contain 12 ppm of CO. The equivalent CO concentration in milligrams per cubic metre is 1) 8.25 mg/m3 3) 15.0 mg/m3 2) 11.25 mg/m3 4) 16.25 mg/m3

Does the data from my lab verify Boyles law? Please explain