Lab 10- Manual Protein extractions and quantification 2 (3)
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Lab 10: Protein extraction/isolation and quantification
Exercise 10.1 Choice of buffers and pigment extraction from plants.
Successful preparation of crude extracts from eukaryotic cells and tissues for proteins and
enzyme studies require that one pay attention to conditions that may alter the activity or native
structure of an enzyme since nonspecific inactivation can result in inconsistent results and make
interpretation of such studies difficult. Another point to consider is that most tissues contain
various harmful agents that can degrade or harm proteins when present in a cell-free extract.
Their effects need to be minimized to avoid artifacts or partially degraded proteins. This is
generally accomplished by extracting at low temperatures and including various protective
chemical agents (see below).
Common Additions to Extraction Buffers
1.
Thiol compounds
are frequently added to protect proteins from oxidation. These include
DTT (dithiothreitol) or 2-mercaptoethanol.
2.
Chelating agents
such as EDTA (ethylenediaminetetraacetic acid, often as the disodium
salt) are useful in protecting enzymes from inactivation by heavy metals, which are
sometimes present in reagents or released from tissue storage compartments. EDTA can
prevent protein-metal ion aggregation/precipitation, substrate inhibition, or proteolysis
by metalloproteases.
3.
Cations
are frequently added to maintain ionic strength (e.g., K
+
or Na
+
) or provide
specific stabilizing interactions (e.g., Mg
2+
). Extraction invariably results in some
instability of cellular proteins.
4.
Substrates
are sometimes added to stabilize enzymes and are quite specific.
5.
Protease inhibitors
with widely differing mechanisms and specificities are available to
suppress endogenous proteases. Phenylmethylsulfonyl fluoride (PMSF) is commonly
used to inactivate many serine proteases.
6.
Osmotically active solutes
like sucrose or sorbitol are often added to maintain the
tonicity of the solution comparable to that of the cell or tissue. This way, osmotically
fragile organelles like plastids and mitochondria are kept from swelling or plasmolyzing.
Glycerol or other polyols are frequently added to stabilize enzymes, partly by increasing
the solution viscosity.
7.
Detergents
are often added to solubilize organelles or membrane-associated proteins.
Triton X-100 is a standard, non-ionic detergent added at 0.1-0.5%.
8.
Polyvinylpolypyrrolidone
(PVPP) is generally added (at 2-10% w/w) to plant extracts to
prevent 'browning' from alkaloids and polyphenolic compounds such as flavonoids and
tannins. These compounds can react with and inactivate proteins by hydrogen bonding
with peptide bond oxygens or by covalent modification of amino acid residues.
As a general rule,
foaming during extraction should be avoided
as this can result in the
inactivation of many enzymes through denaturation of the protein at the air/liquid interface of
bubbles. Also, extractions generally are done at 4
o
C to minimize proteolysis and other
undesirable effects due to warming. Sometimes, extraction buffers are partially frozen to form a
slurry when used.
Cell Lysis Methods
Bacteria are commonly lysed using a
French press,
as shown below, which breaks cells by
pressurizing the cell suspension in a closed chamber (e.g., 7-10,000 psi) and suddenly releasing
the pressure. The release of pressure creates a liquid shear capable of lysing the cells.
Bacteria can also be lysed by
sonication
, which focuses sound waves to create a liquid shear and
cavitation. The TA will demonstrate the use of a sonicator.
Tissue culture cells or cell suspensions can often be lysed by a hand-held or motor-driven
homogenizer
, as will be shown in the lab. Solid or more fibrous tissue requires other
approaches. Small samples can be extracted using a
mortar and pestle
. These are often frozen
in liquid N
2
and then powdered before adding extraction buffer. Larger samples may require the
use of a
blender
. A
polytron
homogenizer is a device with counter-rotating blades that can be
useful for very fibrous tissue.
Exercise 10.1 Calculate Buffer Components and Make Extraction Buffer:
Materials:
1.
Components of the extraction buffer
2.
Spinach leaf (at TI bench)
3.
Ice buckets
4.
1.5ml microfuge tubes
5.
Mortar pestles
6.
Centrifuge
7.
Plate reader (prep room)
8.
50 ml tube with H
2
0
Determine the volumes of each of the following components to be added from the stock
solutions provided in the laboratory to make 5 ml of the following extraction buffer
: Keep on
ice.
Extraction buffer
Making Leaf Extracts
1.
Put mortar pestle on the ice at the beginning of the lab to chill.
2.
Make the extraction buffer using your calculations and keep it on ice.
3.
Label two 1.5ml microfuge tubes
CR
(crude extract) and
E
and keep them on ice.
4.
Obtain a healthy-looking spinach leaf from the TA bench.
5.
Excise the leaf, remove prominent veins as feasible, and weigh 0.5 g fresh weight for
each. Add weighed leaf directly to mortar.
6.
Then, add 4 ml of extraction buffer and grind on ice. Grind vigorously until the leaf is
homogenized (like "spinach soup"). Add one drop of extract to the tube labeled
CR
(crude extract) using a plastic pasture pipette
. Add 50 µl of 2X SDS dye to it and leave it
on ice until step 13.
7.
Using the same plastic pasture pipette, transfer the extract to the microfuge tube
labeled as E
on ice and fill it up to 1 ml mark.
8.
Working with the other team, ensure the sample tubes have equal volumes and place
the balanced tubes opposite each other in a centrifuge. The rotor
MUST
be balanced
before spinning or damage and possibly injury. Do not forget to put the lid on.
9.
Spin tube E
for 5 min at maximum speed. Take tubes out and place them on ice. Label a
new tube as
S (Supernatant
)
and transfer all the Supernatant
to this tube. Keep this tube
Stock solutions concentrations
Final concentrations
Amount needed for 5ml
250 mM Tris-HCl pH 8.0
50 mM
200 mM MgCl
2
5mM
200mM EDTA
1mM
In chemical hood –14.3M
β-mercaptoethanol (β-ME)
10mM
H
2
O (to make up to 5 ml)
-
S
on ice all the time. You will need this tube in exercise 10.2
. If you discard this tube, you
must start over from step # 1.
10. Put
tube E with
the pellet on ice and add
200 µl of extraction buffer
. Flick the tube with
your finger and incubate on ice for 5 mins.
11. Meanwhile, take a new tube, label it as
SN,
and transfer 50 µl of the Supernatant from
tube S to this tube.
Add 50 µl of 2X SDS dye to it and leave it on ice.
12. After 5 mins of incubation on ice, centrifuge the tube E from step 9 for 3 mins at
maximum speed. Label a new tube as
P (pellet)
.
Transfer
50µl
of the Supernatant in this
tube.
Add 50 µl of 2X SDS dye to it and leave it on ice.
13. Take the tubes with the dye
(tubes CR, SN, and P
)
to the heat block on the front bench
and incubate at 90°C for 5 min.
14. After 5 min of incubation, carefully take tubes out. They will be VERY HOT.
15.
Relabel the tubes if needed and place the tubes in the box labeled with your section #.
Your TA will store your samples at -20°C for the next lab. At the end of this exercise
each
team should have three tubes saved for the lab in the future.
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Related Questions
2. Using the following data, determine the Vmax and Km of the
enzyme catalyzed reaction:
[S] (M)
2.5 X 10-6
4.0 X 106
1 X 105
2 X 10'5
Vo (uM/min)
28
40
70
95
[S] (M)
4 X 105
1 X 10
2 X 10³
1 X 10²
Vo (uM/min)
112
128
139
140
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3 Enzyme-linked antibody specific 4 Enzyme's substrate () is added,
for test antigen is added and binds and reaction produces a product
that causes a visible color change (O).
to antigen, forming sandwich.
A low concentration of a specific antigen in the patient's sample
O A high concentration of a specific enzyme in the patient's sample
The patient's antibody is specific for the enzyme's substrate
O A high concentration of a specific antigen in the patient's sample
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Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.
a
Sample B
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Color of lead acetate solution:
Color of original
Color after lead
Sample
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acetate
glutamic acid
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casein
albumin
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µM S
0.21000
k w/ 20 µM Inh
3.464
k sec!
4.1
0.21000
4.2
3.2
0.43000
6.9
5.50
9.82
10.2
0.87000
0.87000
1.3800
1.3800
7.67
7.71
11.556
10.98
8.95
9.01
9.76
2.0800
12.24
2.0800
11.86
9.89
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ИМ.
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b. Provide the type of inhibition for both?
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d. Calculate the reaction Kcat for the Control in experiment (1).
Draw a velocity versus [S] showing Michaelis-Menten curve for the Control. Clearly show Vmax
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c.
e.
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(1) V.
[(µmol/(ml.s)]
(2) V.
(3) V.
[(umol/(ml.s)]
[(µmol/(ml.s)]
2
7.6
4.4
6.6
4
14.6
8.6
11.4
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< Question 12 of 23
Attempt 3
Carry out the given conversions from one metric unit of length to another.
83.5 Mm =
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4.75 nm =
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* TOOLS
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v (mmol/ml/min)
0.1
3.33
0.2
5.0
0.5
7.14
0.8
8.0
1.0
8.3
2.0
9.09
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b) Assuming the enzyme was used in these reactions at a concentration of 10-6 M, then calculate the
turnover number for the enzyme.
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Be sure your answer has the correct number of significant digits.
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Construct a figure of Lineweaver-Burk plot. Determine the K, and Vmx of the enzyme-
substrate complex from this figure. Please make sure that your figure has all the
necessary components such as axis title, axis scale, axis unit etc.
concentration (in mM) of substrate (NPP):
0.005mM
0.01mM
0.025mM
0.5mM
0.075mM
0.1mM
0.125mM
p-nitrophenol (PNP):
0.00021mMmin-1
0.00023mMmin-1
0.00029mMmin-1
0.00043mMmin -1
0.00069mMmin-1
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0.00055mMmin -1
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3. Reactions that occur in the gaseous state are affected by changing the volume of
the container. Which choice best describes what will happen to the reaction if the
volume of the container is decreased?
The reaction will speed up.
The reaction will shift left.
The reaction will not change.
SAVE & EXIT
NEXT
The reaction will shift right.
3 of 25
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4. Graphing the results from kinetics experiments with enzyme inhibitors
The following kinetic data were obtained for an enzyme in the absence of inhibitor (1), and in the
presence of two different inhibitors (2) and (3) at 5 mM concentration. Assume [Er] is the same in
each experiment.
[S]
(mM)
1
2
4
8
12
1
2
4
8
12
[S]
(mm)
a. Determine Vmax and Km for the enzyme.
b. Determine the type of inhibition and the Kıfor each inhibitor.
1/[S]
M-1
Plot these data as double-reciprocal Lineweaver-Burk plots and use your graph to answers a.
and b.
1000
500
250
125
83.3
Answer: The data may be analyzed using double-reciprocal variables. For each [S] and corresponding u, we
will calculate 1/[S] and 1/v.
sed to get mo
Helmien
(1)
v (μmol/mL sec
12
20
29
35
40
1/v (1)
v (1)
μmol/mL se mL-sec/umol
C
12
20
29
35
40
Please explain
how to get
K
1/v
20 × 104
10 × 104
-400
8.33x104
5.00x104
3.45x104
2.86x104
2.50x104
Condition
No inhibitor
0
5 mM inhibitor (2)
5 mM inhibitor (3)
Plots of 1/v vs. 1/[S]…
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